Lesson 3.1.12.4
3.1.12.4 Weak acids and bases Ka for weak acids Quiz: AQA Chemistry, Unit 1
20 questions
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Lesson 3.1.12.4, Weak acids and bases Ka for weak acids: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
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The 20 questions
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For a weak acid HA dissociating as HA <=> H^+ + A^-, which is the correct expression for Ka?
- Ka = [H^+] + [A^-]/[HA]
- Ka = [HA]/([H^+][A^-])
- Ka = [H^+][HA]/[A^-]
- Ka = [H^+][A^-]/[HA]
-
What is pKa defined as?
- pKa = -Ka/10
- pKa = -log10 Ka
- pKa = log10 Ka
- pKa = 1/Ka
-
A weak acid has Ka = 1.0 x 10^-5 mol dm^-3. What is its pKa?
- 1.00
- 10.00
- 5.00
- -5.00
-
A weak acid has pKa = 4.74. What is its Ka in mol dm^-3?
- 1.8 x 10^-5
- 4.7 x 10^-4
- 4.74 x 10^-1
- 5.5 x 10^-5
-
What are the units of Ka for a weak acid?
- s^-1
- mol dm^-3
- dm^3 mol^-1
- No units, because Ka is a ratio
-
Which acid is stronger, one with pKa = 3.0 or one with pKa = 5.0?
- The acid with pKa = 3.0, because it has the larger Ka
- The acid with pKa = 5.0, because it dissociates more
- They are equally strong, because both are weak acids
- The acid with pKa = 5.0, because it has the larger pKa
-
Ethanoic acid has Ka = 1.8 x 10^-5 mol dm^-3. What is the approximate pH of a 0.050 mol dm^-3 solution?
- 2.87
- 4.74
- 1.30
- 3.02
-
A weak acid with Ka = 1.8 x 10^-5 mol dm^-3 is at 0.10 mol dm^-3. What is its pH, to two decimal places?
- 1.34
- 4.74
- 2.87
- 1.00
-
A 0.10 mol dm^-3 solution of a weak acid has pH 3.0. What is its Ka?
- 1.0 x 10^-6 mol dm^-3
- 1.0 x 10^-5 mol dm^-3
- 1.0 x 10^-3 mol dm^-3
- 3.0 x 10^-4 mol dm^-3
-
A 0.50 mol dm^-3 solution of a weak acid has pH 4.0. What is its Ka?
- 2.0 x 10^-8 mol dm^-3
- 2.0 x 10^-10 mol dm^-3
- 8.0 x 10^-5 mol dm^-3
- 2.0 x 10^-4 mol dm^-3
-
A strong acid and a weak acid have the same concentration. Which has the higher pH?
- They have the same pH, because they have the same concentration
- The strong acid, because it is fully dissociated and gives more H+ ions
- The strong acid, because its pH is always above 7
- The weak acid, because it is only partly dissociated and gives fewer H+ ions
-
Hydrofluoric acid has Ka = 6.8 x 10^-4 mol dm^-3 and ethanoic acid has Ka = 1.8 x 10^-5 mol dm^-3. Which statement is correct at equal concentrations?
- Ethanoic acid has the higher Ka and so is the stronger acid
- Hydrofluoric acid has the higher [H+] and lower pH
- Ethanoic acid has the higher [H+] and lower pH
- Both have the same pH, because both are weak acids
-
What is the pH of a weak acid at half-neutralisation by a strong base?
- Equal to 7, because half-neutralisation always gives a neutral solution
- Equal to the pOH of the strong base
- Equal to 14 minus the pKa of the weak acid
- Equal to the pKa of the weak acid
-
A weak acid has pKa = 4.0 and is at 0.20 mol dm^-3. What is the approximate pH?
- 0.70
- 4.00
- 3.35
- 2.35
-
When a weak acid is diluted ten times, its pH rises by less than one unit. Why?
- On dilution the Ka of the acid increases by a factor of ten, so [H+] stays the same
- On dilution the acid dissociates to a greater extent, so [H+] falls by less than tenfold
- On dilution the water molecules stop the acid dissociating at all
- On dilution the acid becomes a strong acid, so [H+] falls by exactly tenfold
-
A weak acid at 0.10 mol dm^-3 has pH 2.87. What is its pKa?
- 5.00
- 1.00
- 4.74
- 2.87
-
Which expression is an approximation for Ka of a weak acid when [H+] and c are known?
- Ka = c/[H^+]^2
- Ka = [H^+]/c
- Ka = [H^+]^2/c
- Ka = c x [H^+]
-
A weak acid with pKa = 3.8 is at 0.40 mol dm^-3. What is its Ka?
- 3.8 x 10^-1 mol dm^-3
- 1.6 x 10^-4 mol dm^-3
- 6.3 x 10^-4 mol dm^-3
- 2.5 x 10^-5 mol dm^-3
-
Which is the pKa of a weak acid with Ka = 6.3 x 10^-4 mol dm^-3?
- -3.20
- 6.30
- 3.20
- 4.20
-
Why is the approximation [H^+] = sqrt(Ka x c) acceptable for a weak acid?
- The acid is only slightly dissociated, so the undissociated acid is close to the starting concentration
- The acid dissociates completely, so the H+ concentration equals the starting concentration
- The pH is always seven, so the concentration of H+ is fixed
- The Ka value is always one, so the square root cancels the dissociation
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