Lesson 3.1.2.5
3.1.2.5 Balanced equations and associated calculations Quiz: AQA Chemistry, Unit 1
20 questions
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Lesson 3.1.2.5, Balanced equations and associated calculations: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
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The 20 questions
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What is the formula for percentage atom economy?
- (Mr of desired product / sum of Mr of all reactants) x 100
- (actual mass of product / theoretical mass of product) x 100
- (Mr of all reactants / Mr of the desired product) x 100
- (Mr of desired product / Mr of the by-product only) x 100
-
Which expression gives percentage yield?
- (theoretical mass / actual mass) x 100
- (Mr / moles) x 100
- (mass of waste / total mass) x 100
- (actual mass / theoretical mass) x 100
-
In an ionic equation, what is a spectator ion?
- An ion that takes no part in the reaction and appears unchanged on both sides
- An ion that forms the precipitate in every reaction, so it is always removed from solution
- An ion that is removed from the reaction as a solid only, leaving no trace in solution
- An ion that is always a gas in the products and leaves the solution as a bubble
-
In a balanced equation, what do the coefficients represent?
- The molar ratio of reactants and products
- The volume of gas produced at 1 atm only
- The mass ratio of the products
- The number of protons in each species
-
Which set of coefficients balances the equation Al + O2 -> Al2O3?
- 1, 1, 1
- 3, 2, 4
- 4, 3, 2
- 2, 1, 1
-
In the balanced equation C3H8 + O2 -> CO2 + H2O, what is the coefficient of O2?
- 10
- 3
- 4
- 5
-
Which statement about percentage atom economy is correct?
- Atom economy is always greater than 100% for addition reactions because of extra atoms
- A high atom economy means the percentage yield is always high, so the reaction is efficient
- Atom economy depends on the experimental yield, which is measured after each reaction
- A high atom economy means more of the reactant mass ends up in the desired product
-
Heating 10.0 g of calcium carbonate (Mr = 100) gives calcium oxide and carbon dioxide. What is the mass of carbon dioxide produced?
- 5.6 g
- 4.4 g
- 10.0 g
- 2.2 g
-
What volume of hydrogen at room temperature and pressure (24.0 dm3 per mole) forms from 0.25 mol of magnesium reacting with excess hydrochloric acid?
- 24.0 dm3
- 0.25 dm3
- 6.0 dm3
- 12.0 dm3
-
What is the percentage atom economy for making iron from Fe2O3 + 3CO -> 2Fe + 3CO2? (Mr: Fe2O3 = 160, CO = 28, Fe = 56)
- 100%
- 70.0%
- 45.9%
- 91.8%
-
A reaction gives 5.00 g of product, but the theoretical yield is 6.25 g. What is the percentage yield?
- 20.0%
- 125%
- 80.0%
- 66.7%
-
H2SO4 reacts with NaOH: H2SO4 + 2NaOH -> Na2SO4 + 2H2O. 25.0 cm3 of 0.100 mol dm-3 NaOH is used. How many moles of H2SO4 reacted?
- 0.0025 mol
- 0.00125 mol
- 0.005 mol
- 0.0500 mol
-
2.40 g of magnesium burns completely in oxygen to form magnesium oxide. What is the mass of magnesium oxide formed? (Ar: Mg = 24, O = 16)
- 2.40 g
- 6.40 g
- 4.00 g
- 3.20 g
-
Zinc reacts with hydrochloric acid: Zn + 2HCl -> ZnCl2 + H2. What mass of hydrogen is formed from 6.5 g of zinc? (Ar: Zn = 65)
- 0.1 g
- 2.0 g
- 0.2 g
- 0.4 g
-
Which balanced equation represents the complete combustion of methane?
- CH4 + O2 -> CO2 + H2O
- 2CH4 + O2 -> 2CO2 + H2O
- CH4 + 2O2 -> CO + 2H2O
- CH4 + 2O2 -> CO2 + 2H2O
-
A 2.00 g tablet of calcium carbonate releases 0.60 g of carbon dioxide on complete reaction with excess acid. What is the percentage of calcium carbonate in the tablet? (Mr: CaCO3 = 100, CO2 = 44)
- 30.0%
- 100%
- 80.0%
- 68.2%
-
A 5.00 g sample of hydrated magnesium sulfate, MgSO4.xH2O, leaves 2.45 g of anhydrous MgSO4 (Mr = 120) when heated. What is x? (Mr of water = 18)
- 7
- 8
- 6
- 5
-
Which reaction type can, in principle, have an atom economy of 100%?
- Addition reaction
- Hydrolysis that forms a by-product
- Substitution reaction
- Elimination reaction
-
0.20 mol of Mg reacts with 0.30 mol of HCl: Mg + 2HCl -> MgCl2 + H2. What is the maximum amount of hydrogen formed in moles?
- 0.10 mol
- 0.15 mol
- 0.30 mol
- 0.20 mol
-
25.0 cm3 of 0.100 mol dm-3 HCl reacts exactly with sodium carbonate: Na2CO3 + 2HCl -> 2NaCl + H2O + CO2. What mass of Na2CO3 (Mr = 106) reacted?
- 0.265 g
- 0.0265 g
- 0.1325 g
- 0.0025 g
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