Lesson 3.1.12.3
3.1.12.3 The ionic product of water, Kw Quiz: AQA Chemistry, Unit 1
20 questions
In partnership with Revision Ninja
Lesson 3.1.12.3, The ionic product of water, Kw: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
Host it live on the board and students join with a game code on their own devices, or revise alone with Free Play. The answers are revealed in the game.
The 20 questions
-
What is the ionic product of water, Kw, in terms of the ion concentrations?
- Kw = [H^+] + [OH^-]
- Kw = [H^+][OH^-]
- Kw = [H2O]/[H^+][OH^-]
- Kw = [H^+]/[OH^-]
-
Why is water described as slightly dissociated?
- Water is a strong electrolyte that fully ionises in all conditions
- Water dissociates completely into hydrogen and oxygen gas
- Only a very small fraction of water molecules ionise into H^+ and OH^- ions
- Water dissociates into ions only at temperatures above 100 C
-
At 298 K, Kw = 1.0 x 10^-14 mol^2 dm^-6. What is [H^+] in pure water?
- 1.0 x 10^-2 mol dm^-3
- 1.0 x 10^-12 mol dm^-3
- 1.0 x 10^-14 mol dm^-3
- 1.0 x 10^-7 mol dm^-3
-
What is the pH of a 0.010 mol dm^-3 solution of sodium hydroxide, a strong base, at 298 K?
- 7.00
- 10.00
- 2.00
- 12.00
-
A solution of a strong base has [OH^-] = 0.10 mol dm^-3 at 298 K. What is its pH?
- 13.00
- 0.10
- 7.00
- 1.00
-
The value of Kw varies with temperature. What happens to Kw as the temperature rises?
- It is unchanged, because Kw is a fixed constant for all substances
- It increases, because water ionises to a greater extent at higher temperature
- It decreases, because water ionises to a smaller extent at higher temperature
- It becomes zero at high temperature, because all the water is converted to ice
-
Why does pure water remain neutral even though its pH is not exactly 7 at every temperature?
- Its [OH^-] is always zero, so it is neutral by definition at all temperatures
- Its [H^+] equals its [OH^-] at any temperature, so it is neutral whatever its pH value
- Its pH is always exactly 7 because Kw is always 1.0 x 10^-14, whatever the temperature
- Its [H^+] is always greater than its [OH^-], so it is slightly acidic at all temperatures
-
What is the approximate value of [OH^-] in a solution of pH 3 at 298 K?
- 1.0 x 10^-7 mol dm^-3
- 1.0 x 10^-14 mol dm^-3
- 1.0 x 10^-3 mol dm^-3
- 1.0 x 10^-11 mol dm^-3
-
A solution of a strong base has pH 11.0 at 298 K. What is [OH^-] in mol dm^-3?
- 1.0 x 10^-11
- 1.0 x 10^-3
- 1.0 x 10^-1
- 1.0 x 10^-14
-
What is the pH of 0.0050 mol dm^-3 potassium hydroxide, a strong base, at 298 K?
- 12.30
- 11.70
- 7.00
- 2.30
-
Why is Kw described as the ionic product of water and not as a pH value?
- It is the concentration of H2O molecules, which never changes in any solution and so is written as a constant
- It is a constant for the equilibrium H2O <=> H+ + OH-, from which pH is calculated for any solution
- It is the pressure of hydrogen gas formed when water ionises at 298 K, which is measured in kPa in a closed vessel
- It is the pH value of pure water at 298 K, which is always a fixed number that is the same for all solutions
-
A solution of pH 9.0 is at 298 K. What is its [OH^-]?
- 1.0 x 10^-3 mol dm^-3
- 1.0 x 10^-9 mol dm^-3
- 1.0 x 10^-5 mol dm^-3
- 1.0 x 10^-14 mol dm^-3
-
Using Kw = [H^+][OH^-] = 1.0 x 10^-14 at 298 K, which statement about a neutral solution is correct?
- A neutral solution has [H^+] = 1.0 x 10^-14 and [OH^-] = 1.0 x 10^-14 mol dm^-3
- A neutral solution has [H^+] = 0 and [OH^-] = 0 mol dm^-3
- A neutral solution has [OH^-] = 1.0 and [H^+] = 1.0 x 10^-14 mol dm^-3
- A neutral solution has [H^+] = [OH^-] = 1.0 x 10^-7 mol dm^-3 at 298 K
-
Which expression gives the pH of a strong base when its hydroxide concentration is known?
- pH = -log10[OH^-] at 298 K
- pH = log10[OH^-] - 14 at 298 K
- pH = 14 - [OH^-] at 298 K
- pH = 14 + log10[OH^-] at 298 K
-
A solution has [OH^-] = 1.0 x 10^-4 mol dm^-3 at 298 K. What is its pH?
- 10.00
- 4.00
- 7.00
- 14.00
-
At 298 K, Kw = 1.0 x 10^-14. In a solution with [H^+] = 1.0 x 10^-5 mol dm^-3, what is [OH^-]?
- 1.0 x 10^-9 mol dm^-3
- 1.0 x 10^-14 mol dm^-3
- 1.0 x 10^-5 mol dm^-3
- 1.0 x 10^-19 mol dm^-3
-
What are the units of Kw for the ionisation of water?
- mol dm^-3
- No units, because Kw is a pure number
- mol^2 dm^-6
- mol dm^-3 s^-1
-
Pure water at 373 K has a higher Kw than at 298 K. Which statement about its pH is correct?
- Its pH is below 7, but the water is still neutral because [H^+] = [OH^-]
- Its pH is exactly 7 at every temperature, because neutrality always means pH 7
- Its pH is 14, because heating raises the pH of all water to the maximum value
- Its pH is above 7, because the water becomes alkaline when heated
-
A student says a solution with pH 7.5 at 298 K is acidic. Which evaluation is correct?
- Partly correct, because the solution is acidic only if it is diluted
- Correct, because any pH above 6 is an acidic solution at 298 K
- Incorrect, because pH 7.5 is above 7, so [OH^-] is greater than [H^+] and the solution is alkaline
- Correct, because a pH of 7.5 means the hydrogen ion concentration is greater than the hydroxide ion concentration
-
What is the pH of a 0.0010 mol dm^-3 solution of sodium hydroxide at 298 K?
- 14.00
- 3.00
- 7.00
- 11.00
Related quizzes
- Fundamental particles Quiz · 3.1.1.1 · 20 questions
- Mass number and isotopes Quiz · 3.1.1.2 · 20 questions
- Electron configuration Quiz · 3.1.1.3 · 20 questions
- Relative atomic mass and relative molecular mass Quiz · 3.1.2.1 · 20 questions
- The mole and the Avogadro constant Quiz · 3.1.2.2 · 20 questions
- The ideal gas equation Quiz · 3.1.2.3 · 20 questions
- Empirical and molecular formula Quiz · 3.1.2.4 · 20 questions
- Balanced equations and associated calculations Quiz · 3.1.2.5 · 20 questions
- Ionic bonding Quiz · 3.1.3.1 · 20 questions
- Nature of covalent and dative covalent bonds Quiz · 3.1.3.2 · 20 questions