Lesson 3D.4.3
3D.4.3 Critical path algorithm Quiz: Pearson Edexcel Further Maths, Unit 38
20 questions
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Lesson 3D.4.3, Critical path algorithm: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 38: Critical path analysis, written with Revision Ninja.
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The 20 questions
-
Critical activities are those with
- no predecessors
- maximum total float
- zero total float
- the longest duration
-
The forward pass in the critical path algorithm computes
- earliest event times
- resource levels
- latest event times
- total float of each activity
-
The backward pass computes
- earliest event times
- earliest start times of activities only
- critical durations
- latest event times
-
The critical path is
- a shortest path from start to finish
- a longest path from start to finish made of critical activities
- a path whose activities all have positive float
- the path with the most activities regardless of duration
-
The earliest time for an event is found by taking
- the average of the incoming durations
- the minimum over incoming activities of the same sum
- the sum of all incoming durations
- the maximum over incoming activities of the earliest start of the tail plus the duration
-
The latest time for an event is found by taking
- the sum of all outgoing durations
- the minimum over outgoing activities of the latest time at their head minus the duration
- the maximum over outgoing activities of the same difference
- the earliest time plus the duration
-
The project duration is equal to
- the earliest time at the finish event
- the latest time at the start event
- the longest single activity duration
- the sum of all activity durations
-
Start node 0 has earliest time 0. Activity 0-1 takes 3, 0-2 takes 5, 1-3 takes 4, 2-3 takes 1 and 3-4 takes 6. What is the project duration?
- 7
- 13
- 18
- 12
-
In the same network, the latest time at node 3 is 7. What is the latest time at node 2, where the activity 2-3 takes 1?
- 6
- 8
- 7
- 5
-
In the same network (durations 0-1: 3, 0-2: 5, 1-3: 4, 2-3: 1, 3-4: 6), which activities form the critical path?
- 0-1, 2-3 and 3-4
- 0-1, 1-3 and 3-4
- 0-2 and 2-3 only
- 0-2, 2-3 and 3-4
-
In the same network, what is the total float of activity 0-2, which takes 5, given earliest time 0 at node 0 and latest time 6 at node 2?
- 1
- 0
- 5
- 6
-
An event has earliest time 4 and latest time 4. What can be said about it?
- it is critical, with zero float
- it cannot be reached
- it has a float of 4
- it is not critical
-
An activity has earliest start 2, duration 4 and its head event has latest time 9. What is its total float?
- 5
- 1
- 3
- 0
-
An event has two incoming activities: one from node 0 (earliest time 0, duration 4) and one from node 1 (earliest time 2, duration 7). What is the earliest time at this event?
- 4
- 9
- 6
- 11
-
A node has outgoing activities to node 5 (duration 3, latest time 12) and to node 6 (duration 4, latest time 10). What is the latest time at this node?
- 9
- 6
- 12
- 7
-
How many critical paths can a network have?
- one or more
- none
- exactly two
- exactly one
-
Why does an activity with zero total float have to be critical?
- it always has the longest duration
- its earliest and latest times are always different
- it has no predecessors
- any delay to it delays the whole project, so it lies on a longest path
-
An activity runs from node 2 to node 3 and takes 4. Node 2 has earliest time 8, and node 3 has latest time 12. What is the total float of this activity?
- 4
- 1
- 2
- 0
-
Why compute latest times by working backwards from the finish?
- because the forward pass is impossible
- to find the latest each event can occur without delaying completion
- to count the number of activities
- to find the cheapest route through the network
-
A network has edges 0-1 (2), 0-2 (6), 1-3 (5), 2-3 (1), 3-4 (4) and 1-2 (3). What is the project duration?
- 11
- 7
- 12
- 9
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