Lesson 3.1.9.2
3.1.9.2 Determination of rate equation Quiz: AQA Chemistry, Unit 1
20 questions
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Lesson 3.1.9.2, Determination of rate equation: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
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The 20 questions
-
On a concentration-time graph, how is the rate of reaction at a particular time found?
- By measuring the height of the curve above the time axis at its end point
- By reading the concentration at that time and dividing it by the total time
- By finding the area under the curve from the start up to that time
- By drawing a tangent to the curve at that time and finding its gradient
-
Why is the initial rate method based on the concentrations at the start of the reaction?
- The equilibrium position is established at the start, so the rate is fixed at that time
- The catalyst is only active at the start of the reaction, so rates are measured then
- Concentrations have changed very little at the start, so the rate is approximately constant then
- Concentrations are at their maximum at the start, so the rate is at its highest value then
-
In a rate experiment, doubling [A] doubles the initial rate. What is the order with respect to A?
- 0
- 1
- 3
- 2
-
In a rate experiment, doubling [A] quadruples the initial rate. What is the order with respect to A?
- 2
- 4
- 1
- 0
-
In a rate experiment, doubling [A] has no effect on the initial rate. What is the order with respect to A?
- 0
- 1
- 2
- -1
-
Experiment 1 and Experiment 2 differ only in [B]: [B] doubles and the rate increases four times. What is the order with respect to B?
- 4
- 2
- 1
- 0
-
Rate data show that tripling [B] at constant [A] increases the rate by a factor of 9. What is the order with respect to B?
- 2
- 1
- 9
- 3
-
Rate data show that doubling [A] doubles the rate and doubling [B] has no effect. What is the rate equation?
- Rate = k[B]
- Rate = k[A]^2
- Rate = k[A][B]
- Rate = k[A]
-
A reaction has rate equation Rate = k[NO]^2[H2]. Which molecules are involved in the rate-determining step?
- Two molecules of NO and one molecule of H2
- Two molecules of NO and two molecules of H2
- One molecule of NO and two molecules of H2
- One molecule of NO and one molecule of H2
-
Which concentration-time graph shape indicates a zero-order reaction?
- A curve whose gradient becomes steadily more negative
- A straight line with a constant negative gradient
- A horizontal line with zero gradient at all times
- A curve that approaches zero concentration with a decreasing gradient
-
A concentration-time graph for a zero-order reaction has a gradient of -0.020 mol dm^-3 s^-1. What is the rate constant k?
- 0.020 mol dm^-3 s^-1
- 0.0004 mol dm^-3 s^-1
- 0.020 s^-1
- 50 mol dm^-3 s^-1
-
In the iodine clock reaction, why is the time for a fixed amount of product to form used to find the initial rate?
- The rate is inversely proportional to the time taken, so a shorter time means a faster initial rate
- The time gives the activation energy directly, so the rate is not needed
- The time is equal to the rate constant, so the reaction is zero order
- The rate is directly proportional to the time taken, so a longer time means a faster initial rate
-
What does the continuous monitoring method for measuring rate involve?
- Measuring the temperature of the solution only once at the end of the reaction
- Recording a property such as gas volume or mass loss against time throughout the reaction
- Measuring the rate only at the start of the reaction with fresh reactants each time
- Adding a single sample to a reagent at the end of the reaction and titrating it
-
What does the initial rate method involve?
- Measuring the rate once, at the end of a long reaction, with a single set of concentrations
- Repeating the experiment with different starting concentrations and measuring the early rate each time
- Recording a continuous graph and using only its final gradient to find the rate
- Measuring the rate of a reaction only when the catalyst is removed from the mixture
-
A tangent drawn to a concentration-time curve has a gradient of -0.0050 mol dm^-3 s^-1 at a given time. What is the rate of reaction at that time?
- 0.0050 s^-1
- -0.0050 mol dm^-3 s^-1
- 0.0050 mol dm^-3 s^-1
- 200 mol dm^-3 s^-1
-
In a reaction where doubling [B] has no effect on the rate, what happens to the rate if [B] is halved at constant [A]?
- It is unchanged, because the reaction is zero order with respect to B
- It doubles, because the reaction is first order with respect to B only
- It halves, because the reaction is first order with respect to B
- It falls to a quarter, because the reaction is second order with respect to B
-
Concentration-time data for a reaction are: [A] = 0.50 at t = 0 s, 0.40 at 10 s and 0.30 at 20 s mol dm^-3. What are the rate and the order with respect to A?
- 0.020 mol dm^-3 s^-1, zero order
- 0.010 mol dm^-3 s^-1, first order
- 0.050 mol dm^-3 s^-1, second order
- 0.010 mol dm^-3 s^-1, zero order
-
A rate experiment shows that doubling [A] and tripling [B] at constant temperature increases the rate by a factor of 18. What is the rate equation?
- Rate = k[A][B]
- Rate = k[A]^2[B]
- Rate = k[A][B]^2
- Rate = k[A]^2[B]^2
-
Which practical method is used to determine the order of reaction when concentrations are changed one at a time?
- The measurement of the enthalpy change for a single reaction at constant pressure
- The continuous monitoring method, in which only one experiment is run at constant concentration
- The initial rate method, in which each experiment is run with a different starting concentration
- The measurement of pH at equilibrium in a closed vessel only
-
A reaction has order 2 with respect to A and order 0 with respect to B. Which change increases the rate?
- Doubling [B] at constant [A], which increases the rate by a factor of two
- Doubling [B] at constant [A], which increases the rate by a factor of four
- Doubling [A] at constant [B], which increases the rate by a factor of four
- Doubling [A] at constant [B], which increases the rate by a factor of two
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