Lesson 3.1.9.1
3.1.9.1 Rate equations Quiz: AQA Chemistry, Unit 1
20 questions
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Lesson 3.1.9.1, Rate equations: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
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The 20 questions
-
In a rate equation Rate = k[A]^m[B]^n, what is the order of reaction with respect to A?
- The concentration of A at the start of the reaction, which determines the power to which it is raised in the rate
- The total number of moles of A that react in one step, which is always the power of its concentration in the rate
- The coefficient of A in the balanced chemical equation, which always gives the power to which the concentration is raised
- The power m to which the concentration of A is raised in the rate equation
-
What is the rate constant, k, in a rate equation?
- The rate of reaction at a fixed concentration of reactants, which never changes
- The activation energy divided by the temperature in kelvin
- The total number of collisions per second in the reaction mixture
- The proportionality constant linking the rate to the concentrations, which varies with temperature
-
Which values can the orders m and n take in the rate equations you are expected to use at A level?
- Only 1 and 2, never zero
- 0, 1 and 2 only
- Any integer, including 3 and 4
- Any value including fractions such as 1/2
-
A reaction has the rate equation Rate = k[A][B]. What are the units of k when concentrations are in mol dm^-3 and rate in mol dm^-3 s^-1?
- s^-1
- dm^3 mol^-1 s^-1
- mol dm^-3 s^-1
- mol^-1 dm^3
-
A first-order reaction has Rate = k[A]. What are the units of k?
- s^-1
- dm^3 mol^-1 s^-1
- dm^6 mol^-2 s^-1
- mol dm^-3 s^-1
-
A zero-order reaction has Rate = k. What are the units of k when rate is in mol dm^-3 s^-1?
- dm^3 mol^-1 s^-1
- mol dm^-3 s^-1
- mol^-1 dm^3 s
- s^-1
-
For a reaction with Rate = k[A]^2 and k = 0.50 dm^3 mol^-1 s^-1, what is the rate when [A] = 0.20 mol dm^-3?
- 0.0080 mol dm^-3 s^-1
- 0.40 mol dm^-3 s^-1
- 0.020 mol dm^-3 s^-1
- 0.10 mol dm^-3 s^-1
-
For Rate = k[A][B]^2 with k = 2.0 dm^6 mol^-2 s^-1, [A] = 0.10 and [B] = 0.20 mol dm^-3, what is the rate?
- 0.10 mol dm^-3 s^-1
- 0.040 mol dm^-3 s^-1
- 0.0080 mol dm^-3 s^-1
- 0.0040 mol dm^-3 s^-1
-
How does an increase in temperature affect the rate constant k?
- It decreases k only for reactions with a positive activation energy
- It increases k, because more molecules have energy above the activation energy
- It decreases k, because molecules move too fast to collide effectively
- It has no effect on k, because only concentration appears in the rate equation
-
Which rearrangement of k = Ae^(-Ea/RT) allows a straight-line graph of experimental data to be plotted?
- ln k = -Ea/(RT) + ln A
- k = -Ea/(RT) + A
- ln k = Ea/(RT) - ln A
- 1/k = Ea/(RT) + A
-
The rate constant k is measured at several temperatures. What is the gradient of a graph of ln k against 1/T?
- Ea/R
- ln A
- -Ea/R
- -R/Ea
-
For a reaction with k = A e^(-Ea/RT), A = 1.0 x 10^10 s^-1, Ea = 60 kJ/mol and T = 300 K, what is k? Use R = 8.314 J K^-1 mol^-1.
- About 36 s^-1
- About 0.036 s^-1
- About 0.36 s^-1
- About 3.6 s^-1
-
For a zero-order reaction, what is the gradient of a graph of concentration against time?
- -k, because the concentration falls at a constant rate
- -k^2, because the rate is proportional to the square of the rate constant
- -1/k, because the concentration falls exponentially
- +k, because the concentration rises at a constant rate
-
A student doubles [B] and finds that the rate is unchanged. What does this show about the order with respect to B?
- The reaction is second order with respect to B
- The reaction is first order with respect to B only at high temperature
- The reaction is zero order with respect to B
- The reaction is first order with respect to B
-
The rate equation is Rate = k[A][B]^2. By what factor does the rate increase when [A] is tripled and [B] is doubled?
- 24
- 9
- 12
- 6
-
Initial rate data: [A] = 0.10, [B] = 0.10 mol dm^-3 gives rate 2.0 x 10^-3 mol dm^-3 s^-1; [A] = 0.20, [B] = 0.10 gives rate 8.0 x 10^-3. With Rate = k[A]^2, what is k?
- 0.20 dm^3 mol^-1 s^-1
- 2.0 dm^3 mol^-1 s^-1
- 0.020 dm^3 mol^-1 s^-1
- 0.50 dm^3 mol^-1 s^-1
-
The rate equation for a reaction is Rate = k[A]^2. What does this suggest about the rate-determining step?
- Two molecules of A are involved in the rate-determining step
- Three molecules of A are involved in the rate-determining step
- The rate-determining step is the final fast step of the reaction
- One molecule of A is involved in the rate-determining step and B is not involved
-
Why is it a mistake to deduce the order of a reaction from its balanced equation?
- Orders are always zero for any reaction that involves a catalyst
- Orders must be found from experimental data, and they can differ from the stoichiometric coefficients
- Orders always equal the stoichiometric coefficients, so the balanced equation is sufficient
- Orders can only be found from the activation energy, not from concentration data
-
A reaction is first order in A, with Rate = k[A]. If [A] is doubled at constant temperature, what happens to the rate?
- It is unchanged
- It doubles
- It halves
- It quadruples
-
For Rate = k[A]^2, if [A] is halved at constant temperature, by what factor does the rate change?
- It falls to one quarter of its original value
- It falls to one half of its original value
- It is unchanged from its original value
- It doubles from its original value
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