Lesson F7
F7 Exponential growth and decay in modelling Quiz: AQA Maths, Unit 6
20 questions
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Lesson F7, Exponential growth and decay in modelling: 20 multiple choice questions for the AQA Maths (7357), Unit 6: Exponentials and logarithms, written with Revision Ninja.
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The 20 questions
-
Which expression describes exponential decay?
- y = A e^(-kt) with A > 0 and k > 0
- y = A e^(kt) with A > 0 and k > 0
- y = At + k with k > 0
- y = A t^k with k > 0
-
In continuous compound interest at annual rate r, what is the amount after t years from principal P?
- P + rt
- P e^(rt)
- P(1 + r)^t
- P r^t
-
Which limitation applies to an exponential growth model of a population?
- It ignores limited resources, so it eventually overestimates the population
- It predicts negative populations for all values of t
- It is valid only for populations below 10
- It predicts that the population stays constant forever
-
A radioactive substance has half-life 5 years. What fraction remains after 10 years?
- 1/2
- 1/5
- 1/10
- 1/4
-
Which quantity is constant for an exponential decay process?
- The half-life
- The amount remaining after a fixed time
- The amount removed each year
- The gradient at time zero for all substances
-
A drug concentration is C = 80 e^(-0.2t) mg/L, with t in hours. What is the concentration after 5 hours?
- 5.9 mg/L
- 64.0 mg/L
- 29.4 mg/L
- 16.0 mg/L
-
A sum of 1000 pounds is invested at 4% per year compounded continuously. What is its value after 10 years?
- 1400.00 pounds
- 1040.81 pounds
- 1491.82 pounds
- 1480.24 pounds
-
A population of 5000 grows continuously at 2% per year. What is its rate of growth when the population is 6000?
- 120 per year
- 6000 per year
- 0.02 per year
- 100 per year
-
A quantity is N = 200 e^(-0.3t). After approximately how long does N halve?
- 0.69
- 0.15
- 2.31
- 3.33
-
A population is y = 50 e^(0.1t), with t in years. What is the doubling time to 2 decimal places?
- 3.47 years
- 5.00 years
- 20.00 years
- 6.93 years
-
A model y = 1000 e^(kt) gives y = 2000 when t = 5. What is k to 3 decimal places?
- 0.139
- 0.035
- 0.200
- 0.693
-
Which refinement makes an exponential decay model of drug concentration more realistic?
- Changing the sign of the exponent to make the model grow
- Replacing the exponential with a linear function of time
- Using a power law so that the rate of decay becomes constant
- Including repeated doses so that the concentration is topped up rather than falling to zero indefinitely
-
A bacteria culture doubles every 3 hours and is modelled as N = N0 e^(kt). Which expression gives k?
- k = ln 3 / 2
- k = ln 2 / 3
- k = 2/3
- k = 3/ln 2
-
A population model P = P0 e^(0.02t) predicts a 20% increase at what time t, to 2 decimal places?
- 6.00 years
- 10.00 years
- 9.12 years
- 0.18 years
-
Under an exponential decay model with k = 0.5 per year, after what time is the quantity 1% of its initial value?
- 4.61 years
- 2.00 years
- 9.21 years
- 50.00 years
-
A cooling model is T = 20 + 80 e^(-0.05t) degrees. What is the long-run temperature the model approaches?
- 80 degrees
- 100 degrees
- 0 degrees
- 20 degrees
-
A model N = 500 e^(0.1t) predicts N = 1500 at what time t, to 2 decimal places?
- 5.49
- 15.00
- 10.99
- 1.10
-
An exponential model of a population of 100 reaches 400 at t = 10. What is the growth constant k to 3 decimal places?
- 0.693
- 0.040
- 0.139
- 0.400
-
Why might a logistic growth model be preferred to an exponential growth model for a population?
- The population never changes in any model of growth
- The data show a constant absolute increase in each period
- Growth is limited by a carrying capacity, so the rate slows as the population approaches a maximum
- Growth is always faster than exponential at every time
-
A sample falls from 80 units to 10 units in 6 hours under exponential decay. What is its half-life?
- 2 hours
- 1 hour
- 6 hours
- 3 hours
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