Lesson F3
F3 Logarithms as the inverse of exponentials Quiz: AQA Maths, Unit 6
20 questions
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Lesson F3, Logarithms as the inverse of exponentials: 20 multiple choice questions for the AQA Maths (7357), Unit 6: Exponentials and logarithms, written with Revision Ninja.
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The 20 questions
-
What is log base 2 of 8?
- 3
- 4
- 1/3
- 2
-
What is log base a of a, for a > 0 and a not equal to 1?
- a
- a^2
- 0
- 1
-
What is log base 10 of 0.001?
- -1
- -3
- 3
- -2
-
Which statement is equivalent to 2^5 = 32?
- log base 32 of 2 = 5
- log base 2 of 32 = 5
- log base 2 of 5 = 32
- log base 5 of 32 = 2
-
What is the inverse function of y = e^x?
- y = 1/e^x
- y = x^e
- y = log base 10 of x
- y = ln x
-
What is the value of e^(ln x) for x > 0?
- x
- 1
- e x
- ln x
-
Which domain restriction applies to log base a of x for a > 0 and a not equal to 1?
- All real values of x
- x < 0
- x >= 0 only
- x > 0
-
Solve log base 3 of x = 4.
- x = 12
- x = 81
- x = 64
- x = 7
-
Evaluate log base 5 of 1/25.
- -5
- -2
- 2
- -1/2
-
Solve ln x = 3 exactly.
- x = 3e
- x = ln 3
- x = e^(1/3)
- x = e^3
-
What is the value of log base 4 of 2?
- 4
- 1/2
- 1/4
- 2
-
If 3^x = 20, which expression gives x?
- x = ln 20 / ln 3
- x = ln 3 / ln 20
- x = 20/3
- x = 3 ln 20
-
Solve 10^x = 7, giving x to 2 decimal places.
- 0.85
- 0.15
- 1.85
- 0.70
-
Solve e^(2x) = 9 exactly.
- x = ln 3
- x = e^(9/2)
- x = 2 ln 9
- x = 4.5
-
For f(x) = ln x and g(x) = e^x, which statement about f(g(x)) is correct?
- f(g(x)) = 1 for all x
- f(g(x)) = e x
- f(g(x)) = x for all real x
- f(g(x)) = e^x ln x
-
Solve log base 2 of (x + 1) + log base 2 of (x - 1) = 3, with x > 1.
- x = sqrt(7)
- x = -3
- x = 3
- x = 9
-
For a > 0 and a not equal to 1, through which point does y = log base a of x always pass?
- (a, a)
- (0, 1)
- (0, 0)
- (1, 0)
-
Solve 2^x = 3^(x + 1) exactly.
- x = 3 ln 2
- x = ln 2 / ln 3
- x = ln 3 - ln 2
- x = ln 3 / (ln 2 - ln 3)
-
What is the inverse function of y = 2^x + 1?
- y = log base 2 of (x + 1)
- y = (log base 2 of x) - 1
- y = log base 2 of (x - 1), for x > 1
- y = log base 2 of x + 1
-
Solve log base 10 of x + log base 10 of (x - 3) = 1, with x > 3.
- x = 5
- x = 2
- x = -2
- x = 10
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