Lesson F6
F6 Logarithmic graphs to estimate parameters Quiz: AQA Maths, Unit 6
20 questions
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Lesson F6, Logarithmic graphs to estimate parameters: 20 multiple choice questions for the AQA Maths (7357), Unit 6: Exponentials and logarithms, written with Revision Ninja.
Host it live on the board and students join with a game code on their own devices, or revise alone with Free Play. The answers are revealed in the game.
The 20 questions
-
For y = a x^n, which plot gives a straight line?
- y against log x
- y against x squared
- log y against x
- log y against log x
-
For y = k b^x, which plot gives a straight line?
- y against x
- y against log x
- log y against log x
- log y against x
-
On a graph of log y against x for y = k b^x, what does the gradient equal?
- b
- k
- log b
- log k
-
On a graph of log y against log x for y = a x^n, what does the gradient represent?
- The value of log a
- The square of n
- The constant a
- The power n
-
What is the vertical intercept of a straight line of log y against x for y = k b^x?
- k
- log k
- log b
- 0
-
Which logarithm base can be used when plotting these graphs?
- Only base 2 can be used, since powers of 2 are the only valid values
- Any base works, since changing the base only scales the gradient and intercept
- Only base 10 can be used for these graphs
- Only base e can be used because the gradient is always 1
-
What relationship does a straight line on a log y against x graph indicate?
- An exponential relationship y = k b^x
- A power law y = a x^n
- A quadratic relationship y = a x^2
- A linear relationship y = mx + c
-
Points (x, log_10 y) = (0, 1.0) and (2, 1.6) lie on a straight line. What is its gradient?
- 1.6
- 0.3
- 0.6
- 1.0
-
A straight line of log_10 y against x has equation log_10 y = 1.0 + 0.3x. What is k in y = k b^x?
- k = 1
- k = 10
- k = 1.6
- k = 0.3
-
A line of log_10 y against x has equation log_10 y = 0.3x + 1. Which value is b?
- b = 10
- b is approximately 3
- b is approximately 2.0
- b is approximately 0.3
-
A log_10 y against log_10 x graph is a straight line with gradient 2 and intercept log_10 5. Which relationship fits?
- y = 5x^2
- y = 5x^(1/2)
- y = 2 x 5^x
- y = 2x^5
-
A log_10 y against x graph has gradient 0.5 and intercept 0. Which relationship fits?
- y = 10^(0.5x)
- y = x^10
- y = 0.5^x
- y = 0.5x
-
Data satisfy y = 3x^2. On a log-log graph, what is the gradient?
- 1/2
- log 3
- 2
- 3
-
Data satisfy y = 4(1.5)^x. On a log_10 y against x graph, what is the gradient to 3 decimal places?
- 1.5
- 0.176
- 0.405
- 0.6
-
On a graph of log_10 y against log_10 x, the line passes through the points (log_10 x, log_10 y) = (0, 2) and (1, 4). What is the gradient?
- 0.5
- 6
- 4
- 2
-
Points (1, 3) and (10, 300) lie on a log-log graph of y = a x^n. What is n?
- n = 2
- n = 0.5
- n = 100
- n = 3
-
The points (0, 2) and (3, 16) lie on the curve y = k b^x. What is b?
- b = 3
- b = 16
- b = 2
- b = 4
-
Why can a straight line on a log y against x graph reveal exponential behaviour?
- Because log y stays constant for exponential data
- Because log y = log k + x log b is linear in x
- Because log y equals x for every exponential function
- Because exponential graphs are always straight lines when plotted
-
A log-log plot has gradient 1.5 and intercept log 4. Which relationship is implied?
- y = 4x^(2/3)
- y = 1.5 x 4^x
- y = 4x^1.5
- y = 10^1.5 x^4
-
Data follow y = 10(0.8)^x. What is the gradient of log_10 y against x, to 3 decimal places?
- -1.250
- 0.097
- -0.8
- -0.097
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