Lesson F4
F4 Laws of logarithms Quiz: AQA Maths, Unit 6
20 questions
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Lesson F4, Laws of logarithms: 20 multiple choice questions for the AQA Maths (7357), Unit 6: Exponentials and logarithms, written with Revision Ninja.
Host it live on the board and students join with a game code on their own devices, or revise alone with Free Play. The answers are revealed in the game.
The 20 questions
-
Which is the product law of logarithms?
- log_a x + log_a y = log_a(xy)
- log_a(x + y) = log_a x + log_a y
- log_a x x log_a y = log_a(x + y)
- log_a x - log_a y = log_a(xy)
-
Which is the quotient law of logarithms?
- log_a x - log_a y = log_a(x - y)
- log_a x - log_a y = log_a(x/y)
- log_a x - log_a y = log_a(xy)
- log_a x / log_a y = log_a(x/y)
-
Which is the power law of logarithms?
- k log_a x = log_a(kx)
- k log_a x = log_a(x + k)
- k log_a x = log_a(x^k)
- k log_a x = (log_a x)^k
-
Simplify log_2 12 - log_2 3.
- log_2 9
- 2
- 4
- 1
-
Simplify log_10 5 + log_10 2.
- 0.5
- log_10 7
- log_10 3
- 1
-
Write 3 log_a 2 as a single logarithm.
- log_a 5
- log_a 6
- log_a 8
- log_a 23
-
What is log_a(1) for a > 0 and a not equal to 1?
- a
- 0
- 1
- undefined
-
Simplify log_3 81 - 2 log_3 3.
- 1
- 4
- 0
- 2
-
Express log_5(x^2 y) in terms of log_5 x and log_5 y.
- 2(log_5 x + log_5 y)
- log_5 x^2 - log_5 y
- 2 log_5 x + log_5 y
- log_5 x + log_5 y
-
Given log_a 2 = p and log_a 3 = q, express log_a 6 in terms of p and q.
- p/q
- pq
- 2p + 3q
- p + q
-
Given log 2 = 0.301 (base 10), find log 16 to 3 decimal places.
- 0.301^4
- 1.204
- 3.010
- 0.602
-
Evaluate (log_2 16)/(log_2 4).
- 2
- 1/2
- 8
- 4
-
Solve log_2 x - log_2(x - 2) = 2, with x > 2.
- x = 8/3
- x = 2
- x = 8
- x = 4/3
-
Simplify log_a(a^3 b) - log_a b.
- 3
- log_a(a^3 b)
- 2
- 3 + log_a b
-
Solve 2 log_10 x - log_10 4 = log_10 9, with x > 0.
- x = 4.5
- x = 18
- x = 3
- x = 6
-
Which expression is equivalent to log_a(x^2/y) for x, y > 0?
- (2 log_a x)/(log_a y)
- 2 log_a x + log_a y
- 2 log_a x - log_a y
- log_a x^2 + log_a y
-
Which statement about log_a(x + y) is true in general?
- log_a(x + y) is not equal to log_a x + log_a y in general
- log_a(x + y) equals log_a x divided by log_a y
- log_a(x + y) always equals log_a x + log_a y
- log_a(x + y) equals log_a x times log_a y
-
Simplify log_2 8 + log_2(1/4).
- -1
- 1
- 5
- 2
-
Solve log_2(x + 1) - log_2(x - 1) = 1, with x > 1.
- x = 3
- x = 2
- x = 1
- x = 5
-
Given that 2 log_a 3 - log_a 2 = log_a k, find k.
- k = 7
- k = 6
- k = 9/2
- k = 2/9
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