Lesson 4.2.2
4.2.2 Stress, strain and elastic strain energy Quiz: Pearson Edexcel Physics, Unit 4
20 questions
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Lesson 4.2.2, Stress, strain and elastic strain energy: 20 multiple choice questions for the Pearson Edexcel Physics (9PH0), Unit 4: Materials, written with Revision Ninja.
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The 20 questions
-
How is tensile or compressive stress defined?
- Extension per unit original length
- Force divided by cross-sectional area
- Strain divided by the Young modulus
- Force multiplied by cross-sectional area
-
How is strain defined?
- Force divided by cross-sectional area
- Stress multiplied by the Young modulus
- Change in length in metres
- Change in length divided by original length
-
How is the Young modulus of a material defined?
- Stress divided by strain
- Strain divided by stress
- Stress multiplied by strain
- Force divided by extension
-
What is the unit of strain?
- Newtons per metre
- It has no unit, because it is a ratio of two lengths
- Metres
- Pascals
-
What is meant by the breaking stress of a material?
- The strain reached before the material returns to its original length
- The stress at the yield point
- The stress at which Hooke's law stops being obeyed
- The stress at which the material fractures
-
Which expression gives the elastic strain energy stored in a stretched wire that obeys Hooke's law?
- F delta x
- 1/2 F (delta x)^2
- 1/2 F delta x
- F^2/(2 delta x)
-
What does the area under a force-extension graph represent?
- The elastic strain energy stored in the material
- The gradient of the force-extension graph
- The stress multiplied by the extension at the elastic limit
- The force at the yield point
-
A force of 200 N acts on a wire of cross-sectional area 2.0 x 10^-4 m^2. What is the stress in the wire?
- 1.0 x 10^6 Pa
- 1.0 x 10^-6 Pa
- 4.0 x 10^-2 Pa
- 4.0 x 10^5 Pa
-
A wire of original length 2.0 m extends by 0.50 mm. What is its strain?
- 2.5 x 10^-4
- 0.25
- 2.5 x 10^-3
- 4.0 x 10^-4
-
A material has stress 5.0 x 10^7 Pa and strain 1.0 x 10^-3 within its elastic region. What is its Young modulus?
- 5.0 x 10^4 Pa
- 5.0 x 10^7 Pa
- 5.0 x 10^10 Pa
- 2.0 x 10^-11 Pa
-
A steel wire of length 1.5 m has stress 2.0 x 10^8 Pa and Young modulus 2.0 x 10^11 Pa. What is its extension?
- 0.67 mm
- 15 mm
- 1.5 mm
- 0.15 mm
-
A spring obeys Hooke's law. It is extended by 0.020 m under a force of 8.0 N. How much elastic strain energy is stored?
- 0.080 J
- 0.040 J
- 0.0040 J
- 0.16 J
-
A Hooke's law spring stores 0.50 J of elastic strain energy when extended by 0.10 m. What is its stiffness?
- 50 N/m
- 200 N/m
- 100 N/m
- 10 N/m
-
A wire carries a force of 500 N and has a stress of 1.0 x 10^8 Pa. What is its cross-sectional area?
- 2.0 x 10^-6 m^2
- 5.0 x 10^-8 m^2
- 5.0 x 10^-4 m^2
- 5.0 x 10^-6 m^2
-
A steel wire has Young modulus 2.0 x 10^11 Pa and is under stress 4.0 x 10^8 Pa. What is its strain?
- 2.0 x 10^-3
- 2.0 x 10^-2
- 8.0 x 10^-3
- 5.0 x 10^-4
-
A student says a material with a high Young modulus must be strong. Which evaluation is correct?
- This is correct, because a high Young modulus means a large breaking stress
- This is incorrect, because Young modulus measures stiffness, while breaking stress measures strength
- This is incorrect, because Young modulus is measured in units of strain
- This is correct, because stronger materials always have larger strains
-
A wire of diameter 0.50 mm carries a force of 20 N. What is the stress in the wire? Take pi = 3.14.
- 1.0 x 10^5 Pa
- 5.1 x 10^7 Pa
- 1.0 x 10^8 Pa
- 2.0 x 10^8 Pa
-
A wire of length 1.0 m, cross-sectional area 1.0 x 10^-6 m^2 and Young modulus 2.0 x 10^11 Pa carries a force of 400 N. What is its extension?
- 2.0 mm
- 0.50 mm
- 20 mm
- 0.20 mm
-
A force-extension graph is a straight line from the origin to (0.020 m, 10 N), then horizontal at 10 N until 0.040 m. How much energy is stored up to 0.040 m?
- 0.20 J
- 0.30 J
- 0.40 J
- 0.15 J
-
Why does the area under a force-extension graph give the stored energy even when the graph is not straight?
- The area is always equal to the Young modulus multiplied by the extension
- The area is only meaningful once the material has yielded
- The area equals the gradient multiplied by the extension for any curve
- The area represents the work done by the force, which is stored as elastic strain energy
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