Lesson 4.1.2

4.1.2 Viscous drag and Stokes' law Quiz: Pearson Edexcel Physics, Unit 4

20 questions

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Lesson 4.1.2, Viscous drag and Stokes' law: 20 multiple choice questions for the Pearson Edexcel Physics (9PH0), Unit 4: Materials, written with Revision Ninja.

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The 20 questions

  1. Which equation is Stokes' law for the viscous drag on a small sphere?

    • F = 6 pi eta r v
    • F = 3 pi eta r v^2
    • F = 6 pi eta r^2 v
    • F = 4 pi eta r v^2
  2. Under which conditions does Stokes' law apply?

    • Objects of any shape moving at any speed
    • Small spherical objects moving at low speeds in laminar flow
    • Large spherical objects moving at high speeds in turbulent flow
    • Objects moving at speeds above the speed of sound in the fluid
  3. What is meant by the viscosity of a liquid?

    • Its ability to conduct electric current
    • The upthrust acting on a body placed in it
    • Its resistance to flow, arising from internal friction between layers of the liquid
    • Its density per unit volume
  4. How does the viscosity of a liquid change as its temperature increases?

    • It stays the same
    • It decreases
    • It increases in direct proportion to the absolute temperature
    • It increases
  5. A sphere falling through a viscous fluid reaches terminal velocity. What is true at that point?

    • Its acceleration is at a maximum
    • The net force on it is zero, so drag plus upthrust balances its weight
    • The drag force on it is zero
    • Its weight is zero
  6. What is the SI unit of viscosity?

    • N m
    • Pa s
    • kg m s^-1
    • m s^-2
  7. A small sphere of radius r and density rho_s falls at terminal velocity v through a fluid of density rho_f and viscosity eta. Which expression gives v?

    • v = 2 r^2 (rho_s - rho_f) g/(9 eta)
    • v = 9 r^2 (rho_s - rho_f) g/(2 eta)
    • v = 2 r (rho_s - rho_f) g/(9 eta)
    • v = 2 r^2 (rho_s + rho_f) g/(9 eta)
  8. A sphere of radius 2.0 mm moves at 0.050 m/s through a liquid of viscosity 0.80 Pa s. What is the viscous drag on it?

    • 3.0 x 10^-2 N
    • 1.5 x 10^-3 N
    • 6.0 x 10^-4 N
    • 3.0 x 10^-3 N
  9. A steel sphere of radius 1.0 mm (density 2700 kg/m^3) falls through a liquid of density 1000 kg/m^3 and viscosity 1.0 Pa s. What is its terminal velocity? Take g = 9.8 N/kg.

    • 7.4 x 10^-3 m/s
    • 3.7 x 10^-1 m/s
    • 1.9 x 10^-2 m/s
    • 3.7 x 10^-3 m/s
  10. If the radius of a sphere falling at terminal velocity in a fixed fluid is doubled, by what factor does its terminal velocity change?

    • 4 times greater
    • 2 times greater
    • 8 times greater
    • Unchanged
  11. At terminal velocity a sphere has weight 0.050 N and upthrust 0.020 N. What is the drag force on it?

    • 0.030 N
    • 0.070 N
    • 0.020 N
    • 0.050 N
  12. A sphere falls at a constant terminal velocity of 0.20 m/s. How long does it take to fall 0.50 m at this speed?

    • 0.40 s
    • 0.10 s
    • 10 s
    • 2.5 s
  13. In a falling-ball experiment, a sphere of radius 0.50 mm, with density difference 1500 kg/m^3 from the liquid, falls at terminal velocity 0.0040 m/s. What is the viscosity of the liquid? Take g = 9.8 N/kg.

    • 0.020 Pa s
    • 0.20 Pa s
    • 0.0020 Pa s
    • 2.0 Pa s
  14. The drag on a sphere moving at 0.10 m/s in a fluid of viscosity 0.10 Pa s is 0.00377 N. What is the radius of the sphere?

    • 2.0 cm
    • 20 m
    • 0.20 cm
    • 2.0 mm
  15. A sphere moving slowly through a fluid has drag 0.0030 N at speed 0.10 m/s. If its speed doubles to 0.20 m/s, staying in laminar flow, what is the new drag?

    • 0.0030 N
    • 0.0120 N
    • 0.0060 N
    • 0.0015 N
  16. A student uses Stokes' law to calculate drag on a large raindrop falling at 10 m/s through air. What is the best evaluation?

    • Stokes' law applies, because air is a viscous fluid at any speed
    • Stokes' law applies, but only with a different constant for air
    • Stokes' law does not apply, because the drop is not small and the flow at this speed is turbulent
    • Stokes' law applies, because raindrops are spherical
  17. A steel ball of radius 1.0 mm falls at constant speed 0.40 m/s in a liquid. Its density difference from the liquid is 6600 kg/m^3. What is the viscosity of the liquid? Take g = 9.8 N/kg.

    • 3.6 Pa s
    • 0.0036 Pa s
    • 0.36 Pa s
    • 0.036 Pa s
  18. A student says that a falling sphere's terminal velocity depends only on its mass. Which evaluation is correct?

    • The claim is right, because heavier objects always fall faster through any fluid
    • The claim is wrong, because terminal velocity does not depend on the fluid at all
    • The claim is right, because drag depends only on the mass of the sphere
    • The claim is wrong, because terminal velocity depends on radius, density difference and the fluid's viscosity
  19. A sphere of radius 0.50 mm and density 2500 kg/m^3 falls through oil of density 900 kg/m^3 and viscosity 0.50 Pa s. What is its terminal velocity? Take g = 9.8 N/kg.

    • 0.17 mm/s
    • 17 mm/s
    • 3.5 mm/s
    • 1.7 mm/s
  20. Why must temperature be controlled in a falling-ball viscosity experiment?

    • Stokes' law is valid only at one fixed temperature for every fluid
    • Temperature changes the mass of the ball, so its weight changes during the fall
    • The viscosity of a liquid depends strongly on temperature, so the terminal velocity and calculated viscosity would change
    • Temperature changes the value of g in the laboratory

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