Lesson 4D.5.4
4D.5.4 Mixed strategies by graphical methods Quiz: Pearson Edexcel Further Maths, Unit 44
20 questions
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Lesson 4D.5.4, Mixed strategies by graphical methods: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 44: Game theory, written with Revision Ninja.
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The 20 questions
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When a 2 by n game has no stable solution, what is plotted in the graphical method?
- The expected payoff against each column, as a function of the probability p of the first row.
- Each cell's payoff as a single point in the plane.
- The row maxima against the column minima.
- The objective function P against x and y.
-
Which games can the graphical method handle in this specification?
- Any game with n greater than 10.
- Only 2 by 2 games.
- 2 by n or n by 2 games, where n = 1, 2, 3 or 4.
- Only games that have a stable solution.
-
What is a mixed strategy?
- A strategy that is always uniform over all options.
- A strategy used only when the value of the game is zero.
- A probability distribution over the pure strategies, chosen to make the opponent indifferent.
- A strategy in which every entry is equal to the maximin.
-
How is the value of a 2 by n game read from its graph?
- It is the height of the lowest point of the upper envelope.
- It is the payoff in the top-left entry of the matrix.
- It is the height of the highest point of the lower envelope of the column lines.
- It is the average of the column payoffs at p = 1/2.
-
On the graph of a 2 by n game, what does the lower envelope show?
- The maximum of the column lines at each p, which the row player wants to minimise.
- The sum of all the column lines.
- The single line through the origin.
- The minimum of the column lines at each p, which the row player wants to maximise.
-
Why does the optimal probability occur where two lines of a graph cross?
- Because probabilities must be whole numbers.
- Because the best guaranteed payoff occurs where the minimum changes from one line to another.
- Because intersections always give a payoff of zero.
- Because the lines on the graph are parallel.
-
For a 2 by 2 game with no stable solution, how is the optimal probability found?
- By setting the two row sums equal to one.
- By setting the largest entry equal to zero.
- By setting the two column payoffs equal and solving for p.
- By adding the two columns together.
-
For the matrix [[2, -1], [-1, 3]], if the row player plays row 1 with probability p, what is the expected payoff against column 1?
- 2p - 1
- 3p - 1
- p - 1
- 3p + 1
-
For the matrix [[2, -1], [-1, 3]], what is the expected payoff against column 2 when row 1 is played with probability p?
- 4p - 3
- 3 - 4p
- 3p - 1
- 3 - p
-
For the matrix [[2, -1], [-1, 3]], what is the optimal probability p of playing row 1?
- 4/7
- 5/7
- 1/2
- 3/7
-
For the matrix [[2, -1], [-1, 3]], what is the value of the game?
- 4/7
- 5/7
- 2/7
- 1
-
For the matrix [[1, -2], [-3, 4]], what is the probability of playing row 1 in the optimal strategy?
- 7/10
- 4/5
- 3/10
- 1/2
-
What is the value of the game with pay-off matrix [[1, -2], [-3, 4]]?
- -1/5
- -2
- 7/10
- 1/5
-
For the matrix [[3, 0], [1, 2]], what is the value of the game?
- 3/2
- 5/4
- 1
- 2
-
For the matrix [[3, 0], [1, 2]], what is the probability that the row player plays row 2 in the optimal strategy?
- 3/4
- 1/2
- 1/4
- 2/3
-
For the matrix [[2, -1], [-1, 3]], why must the two column payoffs be equal at the optimum?
- Otherwise the column player could shift probability to the cheaper column and lower the row player's guaranteed payoff.
- Because probabilities must always sum to one.
- Because the lines on the graph are parallel.
- Otherwise the matrix would have a saddle point.
-
If the row player plays p = 1/2 in the matrix [[2, -1], [-1, 3]], what is the worst-case payoff?
- 1/2
- 1
- 5/7
- 0
-
For the matrix [[3, 0], [1, 2]], what is the optimal probability that the column player plays column 1?
- 1/4
- 1/2
- 3/4
- 2/3
-
For the matrix [[2, -1], [-1, 3]], what is the optimal probability that the column player plays column 1?
- 5/7
- 3/7
- 1/2
- 4/7
-
In the graph for [[2, -1], [-1, 3]] at p = 4/7, what happens to the column lines?
- Only the column 2 line is active at height 3.
- Both column lines are at height 4/7.
- The lines are parallel at height 0.
- Both column lines meet at height 5/7, which is the peak of the lower envelope.
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