Lesson 15A.4

15A.4 Shapes of complexes and cis-platin Quiz: Pearson Edexcel Chemistry, Unit 15

20 questions

In partnership with Revision Ninja

Lesson 15A.4, Shapes of complexes and cis-platin: 20 multiple choice questions for the Pearson Edexcel Chemistry (9CH0), Unit 15: Transition Metals, written with Revision Ninja.

Host it live on the board and students join with a game code on their own devices, or revise alone with Free Play. The answers are revealed in the game.

Host this setFree Play

The 20 questions

  1. What shape do six-coordinate complexes with H2O, OH- or NH3 ligands usually adopt?

    • Octahedral
    • Linear
    • Square planar
    • Tetrahedral
  2. What shape do four-coordinate complexes with large ligands such as Cl- usually adopt?

    • Linear
    • Tetrahedral
    • Octahedral
    • Trigonal bipyramidal
  3. Which type of metal ion commonly forms square planar complexes?

    • Ca2+, a Group 2 ion
    • Ti4+, a d0 ion
    • Na+, an s-block ion
    • Pt2+, a d8 ion
  4. What is the shape of cis-platin, [Pt(NH3)2Cl2]?

    • Linear
    • Tetrahedral
    • Square planar
    • Octahedral
  5. What does the term cis mean in cis-platin?

    • The two identical ligands are adjacent, at 90 degrees to each other
    • The two identical ligands are opposite each other at 180 degrees
    • The two identical ligands bridge between two platinum atoms
    • The two identical ligands are both above the metal plane
  6. Why is cis-platin supplied as a single isomer rather than a mixture with trans-platin?

    • The trans form is far less active as an anticancer drug
    • The trans form is more active and more toxic, so the mixture would be safer
    • The trans form does not contain platinum
    • The mixture would have a coordination number of 6
  7. How many geometric isomers does a square planar complex of type [MA2B2] have?

    • 4, one for each ligand
    • 1, because all arrangements are identical
    • 2, the cis and trans isomers
    • 3, because each ligand can be placed in three positions
  8. What is the shape of [Ni(H2O)6]2+?

    • Square planar
    • Octahedral
    • Linear
    • Tetrahedral
  9. What is the molecular geometry of the square planar complex [PtCl4]2-?

    • Tetrahedral
    • Square planar
    • Linear
    • Octahedral
  10. What are the bond angles between adjacent ligands in a square planar complex?

    • 120 degrees
    • 180 degrees for all pairs
    • 109.5 degrees
    • 90 degrees
  11. What are the bond angles between ligands in an octahedral complex?

    • 90 degrees only, with no opposite pairs, since all six ligands sit at the corners of a cube
    • 120 degrees throughout, as in a trigonal planar arrangement of all six ligands
    • 109.5 degrees throughout, as in every tetrahedral arrangement of six ligands
    • 90 degrees between adjacent ligands and 180 degrees between opposite ligands
  12. What is the bond angle in a regular tetrahedral complex?

    • 180 degrees
    • 90 degrees
    • 120 degrees
    • 109.5 degrees
  13. In cis-platin, where are the two chloride ligands relative to each other?

    • Both above the platinum plane in axial positions
    • Bridging between two platinum atoms
    • Adjacent to each other, at 90 degrees
    • Opposite each other at 180 degrees
  14. Which transition metal ion is most likely to form a square planar complex: Pt(II) or Ti(IV)?

    • Ti(IV), a d0 ion
    • Both are equally likely
    • Pt(II), a d8 ion
    • Neither forms complexes
  15. What is the oxidation state of platinum in [Pt(NH3)2Cl2]?

    • +4
    • +2
    • 0
    • +1
  16. Which isomer of [Pt(NH3)2Cl2] is the active anticancer drug?

    • The trans isomer
    • Neither isomer is active
    • The cis isomer
    • Both isomers are equally active
  17. Which pair of compounds are geometric isomers of each other?

    • cis- and trans-[Pt(NH3)2Cl2]
    • [Co(H2O)6]2+ and [CoCl4]2-
    • [Pt(NH3)4]2+ and [PtCl4]2-
    • [Cu(NH3)4]2+ and [Cu(H2O)4]2+
  18. How many geometric isomers does an octahedral complex of type [M(NH3)4Cl2] have?

    • 1, because all arrangements of the four ligands are identical in an octahedron
    • 4, one for each Cl- ligand around the octahedron
    • 2, cis and trans
    • 3, because each Cl- can occupy one of three different positions around the metal
  19. A student predicts that [NiCl4]2- is square planar. Which evaluation is best?

    • Incorrect, because large Cl- ligands favour a tetrahedral geometry for four-coordinate complexes
    • Correct, because all four-coordinate complexes are square planar, whatever ligands are bound
    • Correct, because Ni2+ always forms square planar complexes with any halide ligand present
    • Incorrect, because nickel cannot form four-coordinate complexes of any kind, only six-coordinate ones
  20. Why is the activity of cis-platin linked to its geometry?

    • Geometry is irrelevant because all isomers have identical bonds and identical activity in the body
    • Chloride ligands must be trans for platinum to bind DNA at all, since adjacent sites are blocked
    • The trans arrangement binds DNA more strongly, so it is the active form and is used as the drug
    • The cis arrangement lets two adjacent sites on DNA replace the chloride ligands, forming cross-links

All Pearson Edexcel Chemistry quizzes