Lesson 15A.4
15A.4 Shapes of complexes and cis-platin Quiz: Pearson Edexcel Chemistry, Unit 15
20 questions
In partnership with Revision Ninja
Lesson 15A.4, Shapes of complexes and cis-platin: 20 multiple choice questions for the Pearson Edexcel Chemistry (9CH0), Unit 15: Transition Metals, written with Revision Ninja.
Host it live on the board and students join with a game code on their own devices, or revise alone with Free Play. The answers are revealed in the game.
The 20 questions
-
What shape do six-coordinate complexes with H2O, OH- or NH3 ligands usually adopt?
- Octahedral
- Linear
- Square planar
- Tetrahedral
-
What shape do four-coordinate complexes with large ligands such as Cl- usually adopt?
- Linear
- Tetrahedral
- Octahedral
- Trigonal bipyramidal
-
Which type of metal ion commonly forms square planar complexes?
- Ca2+, a Group 2 ion
- Ti4+, a d0 ion
- Na+, an s-block ion
- Pt2+, a d8 ion
-
What is the shape of cis-platin, [Pt(NH3)2Cl2]?
- Linear
- Tetrahedral
- Square planar
- Octahedral
-
What does the term cis mean in cis-platin?
- The two identical ligands are adjacent, at 90 degrees to each other
- The two identical ligands are opposite each other at 180 degrees
- The two identical ligands bridge between two platinum atoms
- The two identical ligands are both above the metal plane
-
Why is cis-platin supplied as a single isomer rather than a mixture with trans-platin?
- The trans form is far less active as an anticancer drug
- The trans form is more active and more toxic, so the mixture would be safer
- The trans form does not contain platinum
- The mixture would have a coordination number of 6
-
How many geometric isomers does a square planar complex of type [MA2B2] have?
- 4, one for each ligand
- 1, because all arrangements are identical
- 2, the cis and trans isomers
- 3, because each ligand can be placed in three positions
-
What is the shape of [Ni(H2O)6]2+?
- Square planar
- Octahedral
- Linear
- Tetrahedral
-
What is the molecular geometry of the square planar complex [PtCl4]2-?
- Tetrahedral
- Square planar
- Linear
- Octahedral
-
What are the bond angles between adjacent ligands in a square planar complex?
- 120 degrees
- 180 degrees for all pairs
- 109.5 degrees
- 90 degrees
-
What are the bond angles between ligands in an octahedral complex?
- 90 degrees only, with no opposite pairs, since all six ligands sit at the corners of a cube
- 120 degrees throughout, as in a trigonal planar arrangement of all six ligands
- 109.5 degrees throughout, as in every tetrahedral arrangement of six ligands
- 90 degrees between adjacent ligands and 180 degrees between opposite ligands
-
What is the bond angle in a regular tetrahedral complex?
- 180 degrees
- 90 degrees
- 120 degrees
- 109.5 degrees
-
In cis-platin, where are the two chloride ligands relative to each other?
- Both above the platinum plane in axial positions
- Bridging between two platinum atoms
- Adjacent to each other, at 90 degrees
- Opposite each other at 180 degrees
-
Which transition metal ion is most likely to form a square planar complex: Pt(II) or Ti(IV)?
- Ti(IV), a d0 ion
- Both are equally likely
- Pt(II), a d8 ion
- Neither forms complexes
-
What is the oxidation state of platinum in [Pt(NH3)2Cl2]?
- +4
- +2
- 0
- +1
-
Which isomer of [Pt(NH3)2Cl2] is the active anticancer drug?
- The trans isomer
- Neither isomer is active
- The cis isomer
- Both isomers are equally active
-
Which pair of compounds are geometric isomers of each other?
- cis- and trans-[Pt(NH3)2Cl2]
- [Co(H2O)6]2+ and [CoCl4]2-
- [Pt(NH3)4]2+ and [PtCl4]2-
- [Cu(NH3)4]2+ and [Cu(H2O)4]2+
-
How many geometric isomers does an octahedral complex of type [M(NH3)4Cl2] have?
- 1, because all arrangements of the four ligands are identical in an octahedron
- 4, one for each Cl- ligand around the octahedron
- 2, cis and trans
- 3, because each Cl- can occupy one of three different positions around the metal
-
A student predicts that [NiCl4]2- is square planar. Which evaluation is best?
- Incorrect, because large Cl- ligands favour a tetrahedral geometry for four-coordinate complexes
- Correct, because all four-coordinate complexes are square planar, whatever ligands are bound
- Correct, because Ni2+ always forms square planar complexes with any halide ligand present
- Incorrect, because nickel cannot form four-coordinate complexes of any kind, only six-coordinate ones
-
Why is the activity of cis-platin linked to its geometry?
- Geometry is irrelevant because all isomers have identical bonds and identical activity in the body
- Chloride ligands must be trans for platinum to bind DNA at all, since adjacent sites are blocked
- The trans arrangement binds DNA more strongly, so it is the active form and is used as the drug
- The cis arrangement lets two adjacent sites on DNA replace the chloride ligands, forming cross-links
Related quizzes
- Electronic configurations and oxidation states Quiz · 15A.1 · 20 questions
- Ligands, complex ions and coordination number Quiz · 15A.2 · 20 questions
- Colour of transition metal ions Quiz · 15A.3 · 20 questions
- Biological complexes: haemoglobin Quiz · 15A.5 · 20 questions
- Vanadium and dichromate redox chemistry Quiz · 15B.1 · 20 questions
- Ligand exchange reactions Quiz · 15B.2 · 20 questions
- Transition metals as catalysts Quiz · 15B.3 · 20 questions
- Sub-atomic particles, isotopes and relative masses Quiz · 1.1.1 · 20 questions
- Dynamic equilibrium and the equilibrium constant Kc Quiz · 10.1.1 · 20 questions
- Kp and partial pressures Quiz · 11.1.1 · 20 questions