Lesson 5.1.2
5.1.2 How far Quiz: OCR Chemistry, Unit 4
20 questions
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Lesson 5.1.2, How far: 20 multiple choice questions for the OCR Chemistry (H432), Unit 4: Physical chemistry and transition elements, written with Revision Ninja.
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The 20 questions
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How is the mole fraction of a gas in a mixture calculated?
- Component moles ÷ total
- Component moles ÷ volume
- Total moles ÷ component
- Component moles × pressure
-
How is the partial pressure of a gas in a mixture calculated?
- Mole fraction ÷ pressure
- Mole fraction × pressure
- Pressure ÷ mole fraction
- Mole fraction × volume
-
What are the units of Kc for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g)?
- mol^-1 dm^3
- mol^2 dm^-6
- mol dm^-3
- mol^-2 dm^6
-
Why are pure solids omitted from heterogeneous equilibrium Kc expressions?
- Temperature fluctuates
- They are unreactive
- Mass remains zero
- Concentration is constant
-
What effect does adding a catalyst have on the value of Kc?
- No effect
- Increases Kc
- Doubles Kc
- Decreases Kc
-
How does increasing temperature affect the Kc value of an exothermic reaction?
- Stays the same
- Doubles
- Decreases
- Increases
-
Where does the position of equilibrium lie if the value of Kc is very large?
- In the centre
- To the left
- To the right
- At the start
-
Initially 1.0 mol of H2 and 1.0 mol of I2 are placed in a 1.0 dm^3 vessel. At equilibrium 0.20 mol of H2 and 0.20 mol of I2 remain, with 1.60 mol of HI present. What is Kc for H2 + I2 <=> 2HI?
- 3.2
- 8.0
- 64
- 0.125
-
At equilibrium N2O4(g) <=> 2NO2(g), the partial pressures are p(N2O4) = 0.60 atm and p(NO2) = 0.80 atm. What is Kp?
- 0.75 atm
- 1.1 atm
- 2.1 atm
- 0.48 atm
-
A gas mixture at equilibrium contains 0.40 mol of CO and 0.60 mol of H2 out of a total of 1.00 mol. What is the mole fraction of CO?
- 0.40
- 0.60
- 0.67
- 0.24
-
The total pressure of an equilibrium mixture is 200 kPa and the mole fraction of CO is 0.25. What is the partial pressure of CO?
- 80 kPa
- 25 kPa
- 200 kPa
- 50 kPa
-
1.0 mol of PCl5 is placed in a 1.0 dm^3 vessel and at equilibrium PCl5 <=> PCl3 + Cl2 contains 0.40 mol of PCl5. What is Kc?
- 0.90 mol dm^-3
- 0.60 mol dm^-3
- 0.36 mol dm^-3
- 1.5 mol dm^-3
-
For the equilibrium C(s) + CO2(g) <=> 2CO(g), which expression is correct for Kc?
- Kc = [CO]^2 / ([C][CO2])
- Kc = [CO] / [CO2]
- Kc = [CO2] / [CO]^2
- Kc = [CO]^2 / [CO2]
-
If gas mole numbers are equal on both sides of a reaction, how do Kp and Kc compare?
- Kp is zero
- Kc is larger
- Kp is larger
- They are equal
-
For 2SO2(g) + O2(g) <=> 2SO3(g), a mixture starts with 2.0 mol SO2 and 1.0 mol O2 in 1.0 dm^3. At equilibrium 1.6 mol SO3 is present. What is Kc, given SO2 = 0.40 mol dm^-3 and O2 = 0.20 mol dm^-3?
- 1.6 mol^-1 dm^3
- 0.0125 dm^3 mol^-1
- 80 dm^3 mol^-1
- 8.0 dm^3 mol^-1
-
What does a Kc value of 1 × 10^-8 indicate about the equilibrium position?
- In the centre
- Far to right
- At start
- Far to left
-
Which change will increase the value of Kc for an endothermic forward reaction?
- Decreasing temperature
- Increasing pressure
- Adding catalyst
- Increasing temperature
-
What is the only factor that alters the numerical value of Kc?
- Catalyst
- Concentration
- Pressure
- Temperature
-
For the equilibrium 2NO(g) + O2(g) <=> 2NO2(g), which expression gives Kc?
- [NO2] / ([NO] [O2])
- [NO2]^2 / ([NO]^2 [O2])
- [NO2]^2 / ([NO] [O2])
- [NO]^2 [O2] / [NO2]^2
-
How does increasing total pressure affect the equilibrium position for N2O4(g) ⇌ 2NO2(g)?
- No change
- Shifts right
- Shifts left
- Fluctuates
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