Lesson 5.2.3
5.2.3 Redox and electrode potentials Quiz: OCR Chemistry, Unit 4
20 questions
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Lesson 5.2.3, Redox and electrode potentials: 20 multiple choice questions for the OCR Chemistry (H432), Unit 4: Physical chemistry and transition elements, written with Revision Ninja.
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The 20 questions
-
In a redox reaction, what does an oxidising agent do to electrons?
- Donates electrons
- Accepts electrons
- Releases protons
- Shares electrons
-
What is the oxidation number of manganese in the permanganate ion, MnO4-?
- +5
- +2
- +4
- +7
-
What is the oxidation number of chromium in the dichromate ion, Cr2O7^2-?
- +12
- +7
- +6
- +3
-
What is the standard electrode potential of the standard hydrogen electrode by definition?
- +0.34 V
- 0.00 V
- -0.76 V
- +1.23 V
-
Which expression gives the standard cell potential, E°cell, of an electrochemical cell?
- E°negative - E°positive
- E°positive - E°negative
- E°negative / E°positive
- E°positive + E°negative
-
Standard electrode potentials are E(Cu2+/Cu) = +0.34 V and E(Zn2+/Zn) = -0.76 V. What is the standard cell potential for a Zn/Cu cell?
- +1.10 V
- -1.10 V
- -0.42 V
- +0.42 V
-
How many electrons are gained per dichromate ion, Cr2O7²⁻, when reduced to Cr³⁺?
- Seven electrons
- Six electrons
- Fourteen electrons
- Three electrons
-
In the reaction between iodine and thiosulfate, I2 + 2S2O3^2- -> 2I- + S4O6^2-, what is the mole ratio of I2 to S2O3^2- ions?
- 2:1
- 1:2
- 1:4
- 1:1
-
In the redox titration of Fe2+ with MnO4- in acid, the balanced equation is MnO4- + 5Fe2+ + 8H+ -> Mn2+ + 5Fe3+ + 4H2O. What is the mole ratio of MnO4- to Fe2+?
- 8:1
- 1:5
- 1:1
- 5:1
-
A 25.0 cm^3 sample of 0.0200 mol dm^-3 MnO4- reacts exactly with 25.0 cm^3 of Fe2+ solution in acid. What is the concentration of Fe2+?
- 0.500 mol dm^-3
- 0.100 mol dm^-3
- 0.0200 mol dm^-3
- 0.0040 mol dm^-3
-
What is the oxidation number of sulfur, on average, in the thiosulfate ion, S2O3^2-?
- -2
- +6
- +2
- +4
-
What is the standard electrode potential of the Cu2+/Cu half-cell?
- +0.34 V
- +1.23 V
- -0.76 V
- +0.77 V
-
What kinetic factor can prevent a thermodynamically feasible redox reaction from occurring?
- Low activation energy
- High activation energy
- Negative cell potential
- Positive cell potential
-
The electrode potential E(Cu2+/Cu+) = +0.15 V and E(Cu+/Cu) = +0.52 V. What is the cell potential for the disproportionation 2Cu+ -> Cu2+ + Cu?
- +0.67 V
- +0.15 V
- -0.37 V
- +0.37 V
-
E(Fe3+/Fe2+) = +0.77 V and E(I2/I-) = +0.54 V. What is the standard cell potential for 2Fe3+ + 2I- -> 2Fe2+ + I2, and is the reaction feasible?
- -0.23 V, not feasible
- +0.23 V, feasible
- +1.31 V, not feasible
- +0.23 V, not feasible
-
What reaction occurs at the negative electrode of a hydrogen fuel cell?
- Reduction of oxygen
- Oxidation of hydrogen
- Reduction of hydrogen
- Oxidation of oxygen
-
What form of energy is directly generated by a hydrogen-oxygen fuel cell?
- Thermal energy
- Electrical energy
- Nuclear energy
- Light energy
-
In the reaction Zn + Cu2+ -> Zn2+ + Cu, which species is the reducing agent?
- Zn2+
- Zn
- Cu
- Cu2+
-
What is the oxidation number of nitrogen in the nitrite ion, NO2-?
- +5
- -3
- +3
- +1
-
In a disproportionation reaction, what happens to the reacting element?
- Oxidised and reduced
- Neutralised
- Only reduced
- Only oxidised
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