Lesson 3.4.2.2
3.4.2.2 The Young modulus Quiz: AQA Physics, Unit 4
20 questions
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Lesson 3.4.2.2, The Young modulus: 20 multiple choice questions for the AQA Physics (7408), Unit 4: Mechanics and materials, written with Revision Ninja.
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The 20 questions
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The Young modulus of a material is defined as:
- tensile stress divided by tensile strain
- force divided by extension
- tensile stress multiplied by tensile strain
- tensile strain divided by tensile stress
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The unit of Young modulus is:
- Pa, equivalent to N m^-2
- a ratio with no unit
- J m^-1
- N m^-1
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A stress-strain graph is used to find the Young modulus because:
- the intercept on the stress axis gives the Young modulus
- the gradient of the straight-line section gives the Young modulus
- the area under the curve gives the Young modulus
- the maximum stress gives the Young modulus
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For a given tensile stress, a material with a larger Young modulus has:
- a strain independent of its modulus
- the same tensile strain
- a larger tensile strain
- a smaller tensile strain
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The Young modulus is a property of:
- the sample's cross-sectional area only
- the specific sample's length only
- the material, independent of the sample's dimensions
- the applied force only
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Which expression gives the Young modulus in terms of force F, original length L, area A and extension delta L?
- E = F delta L / (A L)
- E = F A / (L delta L)
- E = F L / (A delta L)
- E = A L / (F delta L)
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Tensile strain is dimensionless because it is:
- defined per unit time
- a ratio of two lengths
- measured in radians
- a ratio of two forces
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A wire of length 2.0 m and cross-sectional area 1.0 mm^2 is stretched by 0.50 mm by a 100 N force. What is its Young modulus?
- 4.0 x 10^9 Pa
- 4.0 x 10^13 Pa
- 2.5 x 10^11 Pa
- 4.0 x 10^11 Pa
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A material has tensile stress 2.0 x 10^7 Pa and tensile strain 1.0 x 10^-3. What is its Young modulus?
- 5.0 x 10^-11 Pa
- 2.0 x 10^4 Pa
- 2.0 x 10^13 Pa
- 2.0 x 10^10 Pa
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A stress-strain line passes through the origin and the point (strain 0.0008, stress 1.6 x 10^8 Pa). What is the Young modulus?
- 2.0 x 10^11 Pa
- 1.6 x 10^8 Pa
- 8.0 x 10^10 Pa
- 1.3 x 10^11 Pa
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A material with stress 2.0 x 10^7 Pa and strain 1.0 x 10^-3 stores energy per unit volume equal to 0.5 x stress x strain. What is this energy density?
- 1.0 x 10^3 J m^-3
- 2.0 x 10^4 J m^-3
- 1.0 x 10^4 J m^-3
- 4.0 x 10^10 J m^-3
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A wire of length 3.0 m has Young modulus 2.0 x 10^11 Pa and is under a stress of 1.0 x 10^8 Pa. What is its extension?
- 1.5 mm
- 0.15 mm
- 15 mm
- 6.7 mm
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Wire 2 is made of the same material as wire 1, has twice the length and half the cross-sectional area, and carries the same force. Compared with wire 1, its extension is:
- twice as great
- one quarter as great
- the same
- four times greater
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Which measurements are needed to find the Young modulus of a wire using a simple method?
- resistance with an ammeter, temperature change and density
- temperature change, density and specific heat capacity
- density and the wire's electrical resistance only
- diameter with a micrometer, original length, force and extension
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A metal has a linear stress-strain region with stress 35 MPa at strain 0.00050. What is its Young modulus?
- 7.0 x 10^10 Pa
- 7.0 x 10^7 Pa
- 1.4 x 10^10 Pa
- 7.0 x 10^12 Pa
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A wire 1.5 m long and 0.80 mm in diameter extends by 0.60 mm under a 50 N force. What is its Young modulus?
- 2.5 x 10^11 Pa
- 2.0 x 10^11 Pa
- 5.0 x 10^10 Pa
- 2.5 x 10^9 Pa
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A wire obeying Hooke's law has E = 2.0 x 10^11 Pa, A = 1.0 x 10^-6 m^2, L = 2.0 m, and is stretched by 1.0 mm. What energy is stored?
- 5 J
- 0.05 J
- 0.1 J
- 0.025 J
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Why is a long, thin wire used when measuring the Young modulus?
- A long wire gives a measurable extension for a given force, so the strain can be measured more accurately.
- Long wires have a larger Young modulus than short wires.
- A wire with high electrical resistance gives a larger extension.
- A thick, short wire gives a larger extension, so strain is easier to measure.
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Material P has E = 2.0 x 10^11 Pa and material Q has E = 7.0 x 10^10 Pa. Under the same tensile stress, what is the ratio of strain in Q to strain in P?
- about 2.9
- about 3.5
- about 2.0
- about 0.35
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A student measures a Young modulus that is half the accepted value. Which error would most likely cause this?
- Underestimating the wire's diameter, so the calculated area is too small
- Overestimating the wire's diameter, so the calculated area is too large
- Recording the extension too small
- Measuring the original length too large
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