Lesson 3.4.2.2

3.4.2.2 The Young modulus Quiz: AQA Physics, Unit 4

20 questions

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Lesson 3.4.2.2, The Young modulus: 20 multiple choice questions for the AQA Physics (7408), Unit 4: Mechanics and materials, written with Revision Ninja.

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The 20 questions

  1. The Young modulus of a material is defined as:

    • tensile stress divided by tensile strain
    • force divided by extension
    • tensile stress multiplied by tensile strain
    • tensile strain divided by tensile stress
  2. The unit of Young modulus is:

    • Pa, equivalent to N m^-2
    • a ratio with no unit
    • J m^-1
    • N m^-1
  3. A stress-strain graph is used to find the Young modulus because:

    • the intercept on the stress axis gives the Young modulus
    • the gradient of the straight-line section gives the Young modulus
    • the area under the curve gives the Young modulus
    • the maximum stress gives the Young modulus
  4. For a given tensile stress, a material with a larger Young modulus has:

    • a strain independent of its modulus
    • the same tensile strain
    • a larger tensile strain
    • a smaller tensile strain
  5. The Young modulus is a property of:

    • the sample's cross-sectional area only
    • the specific sample's length only
    • the material, independent of the sample's dimensions
    • the applied force only
  6. Which expression gives the Young modulus in terms of force F, original length L, area A and extension delta L?

    • E = F delta L / (A L)
    • E = F A / (L delta L)
    • E = F L / (A delta L)
    • E = A L / (F delta L)
  7. Tensile strain is dimensionless because it is:

    • defined per unit time
    • a ratio of two lengths
    • measured in radians
    • a ratio of two forces
  8. A wire of length 2.0 m and cross-sectional area 1.0 mm^2 is stretched by 0.50 mm by a 100 N force. What is its Young modulus?

    • 4.0 x 10^9 Pa
    • 4.0 x 10^13 Pa
    • 2.5 x 10^11 Pa
    • 4.0 x 10^11 Pa
  9. A material has tensile stress 2.0 x 10^7 Pa and tensile strain 1.0 x 10^-3. What is its Young modulus?

    • 5.0 x 10^-11 Pa
    • 2.0 x 10^4 Pa
    • 2.0 x 10^13 Pa
    • 2.0 x 10^10 Pa
  10. A stress-strain line passes through the origin and the point (strain 0.0008, stress 1.6 x 10^8 Pa). What is the Young modulus?

    • 2.0 x 10^11 Pa
    • 1.6 x 10^8 Pa
    • 8.0 x 10^10 Pa
    • 1.3 x 10^11 Pa
  11. A material with stress 2.0 x 10^7 Pa and strain 1.0 x 10^-3 stores energy per unit volume equal to 0.5 x stress x strain. What is this energy density?

    • 1.0 x 10^3 J m^-3
    • 2.0 x 10^4 J m^-3
    • 1.0 x 10^4 J m^-3
    • 4.0 x 10^10 J m^-3
  12. A wire of length 3.0 m has Young modulus 2.0 x 10^11 Pa and is under a stress of 1.0 x 10^8 Pa. What is its extension?

    • 1.5 mm
    • 0.15 mm
    • 15 mm
    • 6.7 mm
  13. Wire 2 is made of the same material as wire 1, has twice the length and half the cross-sectional area, and carries the same force. Compared with wire 1, its extension is:

    • twice as great
    • one quarter as great
    • the same
    • four times greater
  14. Which measurements are needed to find the Young modulus of a wire using a simple method?

    • resistance with an ammeter, temperature change and density
    • temperature change, density and specific heat capacity
    • density and the wire's electrical resistance only
    • diameter with a micrometer, original length, force and extension
  15. A metal has a linear stress-strain region with stress 35 MPa at strain 0.00050. What is its Young modulus?

    • 7.0 x 10^10 Pa
    • 7.0 x 10^7 Pa
    • 1.4 x 10^10 Pa
    • 7.0 x 10^12 Pa
  16. A wire 1.5 m long and 0.80 mm in diameter extends by 0.60 mm under a 50 N force. What is its Young modulus?

    • 2.5 x 10^11 Pa
    • 2.0 x 10^11 Pa
    • 5.0 x 10^10 Pa
    • 2.5 x 10^9 Pa
  17. A wire obeying Hooke's law has E = 2.0 x 10^11 Pa, A = 1.0 x 10^-6 m^2, L = 2.0 m, and is stretched by 1.0 mm. What energy is stored?

    • 5 J
    • 0.05 J
    • 0.1 J
    • 0.025 J
  18. Why is a long, thin wire used when measuring the Young modulus?

    • A long wire gives a measurable extension for a given force, so the strain can be measured more accurately.
    • Long wires have a larger Young modulus than short wires.
    • A wire with high electrical resistance gives a larger extension.
    • A thick, short wire gives a larger extension, so strain is easier to measure.
  19. Material P has E = 2.0 x 10^11 Pa and material Q has E = 7.0 x 10^10 Pa. Under the same tensile stress, what is the ratio of strain in Q to strain in P?

    • about 2.9
    • about 3.5
    • about 2.0
    • about 0.35
  20. A student measures a Young modulus that is half the accepted value. Which error would most likely cause this?

    • Underestimating the wire's diameter, so the calculated area is too small
    • Overestimating the wire's diameter, so the calculated area is too large
    • Recording the extension too small
    • Measuring the original length too large

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