Lesson 3.2.5.5
3.2.5.5 Variable oxidation states Quiz: AQA Chemistry, Unit 2
20 questions
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Lesson 3.2.5.5, Variable oxidation states: 20 multiple choice questions for the AQA Chemistry (7405), Unit 2: Inorganic chemistry, written with Revision Ninja.
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The 20 questions
-
What is the common oxidation state of vanadium in the vanadate(V) ion?
- +5
- +3
- +2
- +4
-
What is the reducing agent used to reduce vanadate(V) ions in acidic solution in the AQA practical?
- Zinc
- Potassium iodide
- Sodium hydroxide
- Chlorine
-
Which oxidation states of vanadium are formed when vanadate(V) is reduced by zinc in acidic solution?
- +5 only
- 0 and +1
- +4, +3 and +2
- +6 and +7
-
Which reagent is used to distinguish aldehydes from ketones by a silver mirror?
- Tollens' reagent
- Dilute sodium hydroxide
- Aqueous sodium chloride
- Acidified potassium manganate(VII)
-
Which species is reduced to metallic silver in the test with Tollens' reagent?
- Cu2+
- NH3
- OH-
- [Ag(NH3)2]+
-
In the reaction of Fe2+ with MnO4- in acid, what is the change in oxidation state of manganese?
- +7 to +2
- +7 to +6
- +7 to +4
- +2 to +7
-
What is the balanced equation for Fe2+ reacting with MnO4- in acid solution?
- Fe2+ + MnO4- -> Fe3+ + MnO2
- Fe2+ + 2MnO4- -> Fe3+ + 2Mn2+ + O2
- 5Fe2+ + MnO4- + 4H+ -> 5Fe3+ + Mn2+ + 2H2O
- 5Fe2+ + MnO4- + 8H+ -> 5Fe3+ + Mn2+ + 4H2O
-
What is the balanced equation for ethanedioate reacting with manganate(VII) in acid?
- 2C2O4^2- + MnO4- + 8H+ -> 4CO2 + Mn2+ + 4H2O
- 5C2O4^2- + 2MnO4- + 16H+ -> 10CO2 + 2Mn2+ + 8H2O
- C2O4^2- + MnO4- -> CO2 + Mn2+
- 5C2O4^2- + 2MnO4- + 8H+ -> 10CO2 + 2Mn2+ + 4H2O
-
A 25.0 cm3 sample of Fe2+ solution is titrated with 0.0200 mol dm-3 KMnO4, using 20.0 cm3 at the endpoint. How many moles of MnO4- are used?
- 4.00 x 10^-4 mol
- 2.00 x 10^-3 mol
- 1.00 x 10^-3 mol
- 5.00 x 10^-4 mol
-
Using the answer to the previous question, how many moles of Fe2+ are in the sample titrated with 4.00 x 10^-4 mol of MnO4-?
- 1.00 x 10^-2 mol
- 8.00 x 10^-4 mol
- 4.00 x 10^-4 mol
- 2.00 x 10^-3 mol
-
In a titration of ethanedioate with acidified KMnO4, 20.0 cm3 of 0.0200 mol dm-3 KMnO4 is used. How many moles of ethanedioate, C2O4^2-, react?
- 4.00 x 10^-4 mol
- 5.00 x 10^-4 mol
- 2.00 x 10^-3 mol
- 1.00 x 10^-3 mol
-
What is the oxidation state of vanadium in the VO2+ ion?
- +3
- +2
- +4
- +5
-
Why is no separate indicator needed in a titration of Fe2+ with acidified KMnO4?
- MnO4- is purple and is reduced to colourless Mn2+, so the endpoint is seen from the first excess of purple colour
- Iron(II) changes colour to show the endpoint
- MnO4- is colourless and Fe2+ is purple
- The reaction produces a precipitate that marks the endpoint
-
Which factor influences the redox potential for a transition metal ion changing to a lower oxidation state?
- pH and the ligand present
- Only the volume of the titration flask
- Only the colour of the solution
- Only the temperature of the room
-
Which change is a reduction in a redox titration?
- Mn in MnO4- going from +7 to +2
- Fe2+ going to Fe3+
- C in C2O4^2- going to CO2
- Hydrogen in H2O going to H+
-
Which statement about the redox titration of hydrogen peroxide with manganate(VII) is correct?
- H2O2 is always reduced to oxygen gas without any change
- The method only measures the mass of sodium chloride
- The method can find the concentration of H2O2 in hair bleach
- Manganate(VII) is reduced by H2O2 to MnO2 only
-
Which quantity can be found by a redox titration of iron(II) with manganate(VII)?
- The density of iron metal
- The mass of iron in an iron tablet
- The melting point of iron
- The boiling point of the solution
-
Why does the reduction of vanadate(V) by zinc in acid produce a sequence of different colours?
- Vanadium is colourless in every oxidation state
- The acid changes the colour of vanadium metal only
- Zinc reacts to form a different coloured oxide at each step
- Each lower oxidation state of vanadium absorbs a different wavelength of visible light, so the colour changes
-
Explain why the redox potential of the Fe3+/Fe2+ couple changes when the ligand is changed.
- The ligand removes all electrons from the iron ion
- The ligand is oxidised instead of the iron ion
- The ligand stabilises one oxidation state more strongly, which shifts the electrode potential
- The ligand has no effect on electrode potentials
-
Which equation shows that Cu2+ is reduced in a reaction with iodide?
- Cu2+ + Zn -> Zn2+ + Cu only
- I- -> I2 + e-
- 2Cu2+ + 4I- -> 2CuI + I2
- Cu2+ + 2e- -> Cu+ + 2e-
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