Lesson 3.1.2.3
3.1.2.3 The ideal gas equation Quiz: AQA Chemistry, Unit 1
20 questions
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Lesson 3.1.2.3, The ideal gas equation: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
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The 20 questions
-
In the ideal gas equation pV = nRT, what are the SI units of pressure, volume and temperature?
- kPa, dm3 and C
- atm, cm3 and K
- Pa, m3 and K
- Pa, dm3 and C
-
What does n represent in pV = nRT?
- The mass of gas in grams
- The number of moles of gas
- The number of molecules per litre
- The number of atoms per molecule
-
Which expression correctly rearranges pV = nRT to find n?
- n = V / pRT
- n = pV / RT
- n = pRT / V
- n = RT / pV
-
Why must the temperature be in kelvin when using pV = nRT?
- Because the gas constant only works with whole numbers, so temperatures must be rounded to kelvin
- Because kelvin is the SI unit for volume, so the temperature must be converted before the calculation
- Because kelvin values are always larger than Celsius values, which makes the calculation safer overall
- Because the equation needs the absolute scale, where zero is the point of zero molecular kinetic energy
-
Which assumption is made about molecules in an ideal gas?
- They all have the same mass and charge
- They move at a fixed speed in a fixed direction
- They have large volumes and strong attractions
- They have negligible volume and no intermolecular forces
-
What is 250 cm3 expressed in m3?
- 2.5 x 10^-4 m3
- 2.5 x 10^-6 m3
- 2.5 x 10^-1 m3
- 250 m3
-
Which of these is the SI unit of pressure?
- Pascal
- Millimetre of mercury
- Bar
- Atmosphere
-
Calculate the volume occupied by 0.100 mol of an ideal gas at 100 kPa and 298 K. Use R = 8.31 J mol-1 K-1.
- 2.48 x 10^-3 m3
- 2.48 x 10^-1 m3
- 2.48 x 10^-5 m3
- 24.8 m3
-
0.50 g of a gas occupies 250 cm3 at 100 kPa and 300 K. What is its approximate relative molecular mass? Use R = 8.31 J mol-1 K-1.
- 100
- 200
- 50
- 25
-
What is the pressure exerted by 0.200 mol of gas in a 2.00 dm3 container at 300 K? Use R = 8.31 J mol-1 K-1.
- 2.49 x 10^6 Pa
- 2.49 x 10^5 Pa
- 2.49 x 10^2 Pa
- 2.49 x 10^4 Pa
-
What volume does 1.00 mol of an ideal gas occupy at 273 K and 101 kPa? Use R = 8.31 J mol-1 K-1.
- 22.5 dm3
- 225 dm3
- 0.0225 dm3
- 2.25 dm3
-
0.500 mol of gas is in a 0.0200 m3 container at 200 kPa. What is the temperature? Use R = 8.31 J mol-1 K-1.
- 1925 K
- 96.2 K
- 481 K
- 962 K
-
Which change would most increase the pressure of a fixed mass of ideal gas at constant volume?
- Increasing the volume of the container
- Removing some of the gas from the vessel
- Decreasing the temperature in kelvin
- Increasing the temperature in kelvin
-
Calculate the volume in dm3 occupied by 0.0500 mol of nitrogen at 25 C and 100 kPa. Use R = 8.31 J mol-1 K-1.
- 1.24 dm3
- 0.124 dm3
- 124 dm3
- 12.4 dm3
-
How many moles of gas are in 2.0 dm3 at 1.0 x 10^5 Pa and 27 C? Use R = 8.31 J mol-1 K-1.
- 0.802 mol
- 8.02 mol
- 0.0802 mol
- 0.00802 mol
-
A 0.350 g sample of a volatile liquid vaporises at 373 K and 100 kPa, filling a 250 cm3 flask. What is its approximate Mr? Use R = 8.31 J mol-1 K-1.
- 173.6
- 34.5
- 43.4
- 86.8
-
Why do real gases deviate from ideal behaviour at high pressure?
- At high pressure, molecules are closer together, so their volume and intermolecular forces become significant
- At high pressure, gas molecules stop moving, so the gas no longer obeys the ideal gas equation
- At high pressure, the gas constant changes value, which alters how the ideal gas equation behaves
- At high pressure, molecules are converted into ions, so the gas stops behaving ideally in practice
-
A fixed amount of ideal gas at 300 K and 100 kPa in a fixed container is heated to 450 K. What is the new pressure?
- 100 kPa
- 150 kPa
- 66.7 kPa
- 225 kPa
-
0.10 mol of O2 and 0.20 mol of N2 are in a 2.0 dm3 container at 300 K. What is the total pressure? Use R = 8.31 J mol-1 K-1.
- 3.74 x 10^5 Pa
- 1.25 x 10^2 Pa
- 1.25 x 10^5 Pa
- 9.00 x 10^5 Pa
-
What is 27 C expressed in kelvin?
- 27 K
- 300 K
- 246 K
- -246 K
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