Lesson 3.1.10
3.1.10 Equilibrium constant Kp for homogeneous systems (A-level Quiz: AQA Chemistry, Unit 1
20 questions
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Lesson 3.1.10, Equilibrium constant Kp for homogeneous systems (A-level: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
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The 20 questions
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What is the partial pressure of a gas in a mixture?
- The mole fraction of the gas multiplied by the total pressure of the mixture
- The total pressure of the mixture divided by the mole fraction of the gas
- The number of moles of the gas multiplied by the volume of the container
- The pressure exerted by the gas alone in its own container at the same temperature
-
What is the mole fraction of a component in a gas mixture?
- The moles of that component divided by the moles of the other gases only
- The moles of that component divided by the total moles of all gases in the mixture
- The mass of that component divided by the total mass of the mixture
- The volume of that component divided by the total volume of the container
-
For 2SO2(g) + O2(g) <=> 2SO3(g), which is the correct expression for Kp?
- Kp = p(SO3) / (p(SO2) x p(O2))
- Kp = p(SO3)^2 / (p(SO2)^2 x p(O2))
- Kp = p(SO2)^2 x p(O2) / p(SO3)^2
- Kp = p(SO3)^2 x p(SO2)^2 / p(O2)
-
In a gas mixture with total pressure 200 kPa, the mole fraction of NH3 is 0.25. What is the partial pressure of NH3?
- 800 kPa
- 50 kPa
- 0.25 kPa
- 200 kPa
-
At equilibrium for PCl5(g) <=> PCl3(g) + Cl2(g), the partial pressures are p(PCl5) = 0.50, p(PCl3) = 0.20 and p(Cl2) = 0.20 atm. What is Kp?
- 0.08 atm
- 0.40 atm
- 1.2 atm
- 2.5 atm^-1
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A mixture at a total pressure of 100 kPa contains 1 mol H2, 1 mol I2 and 2 mol HI at equilibrium for H2 + I2 <=> 2HI. What is Kp?
- 4
- 0.25
- 2
- 8
-
For N2O4(g) <=> 2NO2(g), what is the value of Kp when p(N2O4) = 0.80 atm and p(NO2) = 0.40 atm?
- 0.50 atm
- 5.0 atm
- 0.20 atm
- 2.0 atm
-
What are the units of Kp for N2(g) + 3H2(g) <=> 2NH3(g) when pressures are in kPa?
- No units, because Kp is always a pure number
- kPa^-4
- kPa^-2
- kPa^2
-
For H2(g) + I2(g) <=> 2HI(g), what are the units of Kp?
- kPa^-1, because the number of moles of product is one more than the number of moles of reactant in the balanced equation
- No units, because the number of gas moles is the same on both sides
- atm^2, because the pressure of hydrogen iodide appears squared in the expression while the other gases appear once
- kPa^2, because the partial pressures of the two reactants are multiplied together to give the units of the constant
-
Which expression is the correct Kp for 2A(g) + B(g) <=> C(g)?
- Kp = p(A)^2 x p(B) / p(C)
- Kp = p(C)^2 / (p(A) x p(B))
- Kp = p(A) x p(B) / p(C)
- Kp = p(C) / (p(A)^2 x p(B))
-
A reaction is exothermic in the forward direction. How does increasing temperature change the value of Kp?
- Kp increases, because the catalyst is more active at higher temperature
- Kp decreases, because the equilibrium shifts towards the reactants
- Kp is unchanged, because only pressure can change an equilibrium constant
- Kp increases, because the equilibrium shifts towards the products
-
Why is the value of Kp for a reaction changed only by a change in temperature?
- Temperature changes the total pressure at fixed volume, and the constant then changes by exactly that pressure change
- Temperature changes the mole fraction of each gas in the mixture, so the constant changes by the same factor for all
- Temperature changes the rate of both directions unequally, which changes the equilibrium position and the value of the constant
- Temperature changes the total number of gas moles in the vessel, which changes the value of the constant directly
-
Which change does NOT alter the value of Kp for a gas-phase equilibrium?
- Changing the total pressure of the system by changing the volume, which always changes the value of the constant
- Adding a catalyst, which changes the rate of attainment but not the value of the constant
- Changing the temperature of the system, which always changes the value of the constant for every reaction at once
- Changing the amount of one reactant so that the equilibrium shifts, which always changes the value of the constant
-
For a reversible reaction at equilibrium at constant temperature, what happens to Kp if the total pressure is doubled by reducing the volume?
- Kp halves, because the equilibrium shifts towards the reactants
- Kp becomes zero, because the partial pressures cannot both be maintained
- Kp doubles, because the total pressure doubles
- Kp is unchanged, although the equilibrium position may shift
-
At 1 atm total pressure, 0.5 mol of N2O4 dissociates for N2O4 <=> 2NO2 from 1 mol start, reaching a total pressure of 2.0 atm. What is Kp?
- 0.67 atm
- 2.67 atm
- 5.33 atm
- 1.33 atm
-
A student says adding an inert gas at constant volume changes the value of Kp for a gas equilibrium. Which evaluation is correct?
- Correct, because the inert gas reacts with the products and so changes the equilibrium constant
- Partly correct, because the inert gas only changes Kp if the reaction is endothermic
- Correct, because the inert gas raises the total pressure, which always changes Kp for any equilibrium
- Incorrect, because the partial pressures of the reacting gases are unchanged and Kp depends only on temperature
-
A gas mixture has a total pressure of 150 kPa and contains 0.60 mol of gas X out of 1.20 mol in total. What is the partial pressure of X?
- 150 kPa
- 75 kPa
- 30 kPa
- 0.5 kPa
-
For N2(g) + 3H2(g) <=> 2NH3(g), which is the correct expression for Kp?
- Kp = p(NH3) / (p(N2) x p(H2)^3)
- Kp = p(NH3)^2 / (p(N2) x p(H2)^3)
- Kp = p(N2) x p(H2)^3 / p(NH3)^2
- Kp = p(NH3)^2 / (p(N2) x p(H2))
-
For an endothermic gas equilibrium, what happens to the value of Kp when the temperature is raised?
- Kp is unchanged, because temperature affects only the rate of reaction
- Kp becomes zero, because the reactants are used up at high temperature
- Kp increases, because the equilibrium shifts towards the products
- Kp decreases, because the equilibrium shifts towards the reactants
-
Which description of the equilibrium constant Kp for a gas-phase equilibrium is correct?
- The partial pressure of the product only, measured at the end of the reaction, raised to its stoichiometric coefficient
- A ratio of product partial pressures to reactant partial pressures, each raised to its coefficient, at constant temperature
- A ratio of total pressure to the number of moles of gas present at equilibrium, each raised to its coefficient
- A ratio of reactant concentrations to product concentrations, expressed in mol dm^-3 and raised to its coefficient
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