Lesson 9.3.1
9.3.1 Black body radiators, Stefan-Boltzmann and Wien's laws Quiz: Pearson Edexcel Physics, Unit 9
20 questions
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Lesson 9.3.1, Black body radiators, Stefan-Boltzmann and Wien's laws: 20 multiple choice questions for the Pearson Edexcel Physics (9PH0), Unit 9: Thermodynamics, written with Revision Ninja.
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The 20 questions
-
What is a black body radiator?
- A perfect reflector that emits no radiation at any temperature.
- An object that absorbs all incident radiation and emits a spectrum that depends only on its temperature.
- A dark object that emits only infrared radiation whatever its temperature.
- An object that reflects all visible light and so looks black at any temperature.
-
Which expression is the Stefan-Boltzmann law for the total power radiated by a black body?
- L = σ T^4 / A
- L = σ A T^4
- L = σ A T
- L = σ A T^2
-
What are the SI units of the Stefan-Boltzmann constant σ?
- J m^-3 K^-4
- W m^-2 K^4
- W m^-2 K^-4
- W m^2 K^-4
-
Wien's law gives λmax T = 2.898 x 10^-3 m K. What happens to the peak wavelength as the temperature of a black body rises?
- It doubles each time the temperature doubles.
- It stays the same, since the peak depends only on the surface area.
- It increases, since the peak wavelength is proportional to T.
- It decreases, since the peak wavelength is inversely proportional to T.
-
A star's spectrum peaks at a wavelength of 500 nm. Using Wien's law, what is its approximate surface temperature?
- about 2900 K
- about 5800 K
- about 11600 K
- about 580 K
-
A black body has surface area 0.50 m^2 and temperature 1000 K. Taking σ = 5.67 x 10^-8 W m^-2 K^-4, what is its total power output?
- about 28 kW
- about 283 kW
- about 2.8 kW
- about 5.7 kW
-
If the absolute temperature of a black body doubles, by what factor does the power emitted per unit area increase?
- 2
- 8
- 16
- 4
-
What is the peak wavelength of a black body at 3000 K?
- about 0.97 micrometres
- about 0.97 nanometres
- about 0.097 micrometres
- about 9.7 micrometres
-
A black body has its peak wavelength at 1.2 micrometres. What is its temperature?
- about 2400 K
- about 1200 K
- about 3500 K
- about 4800 K
-
A Sun-like star has radius 7.0 x 10^8 m and surface temperature 5800 K, and is treated as a black body with σ = 5.67 x 10^-8 W m^-2 K^-4. Approximately what is its luminosity?
- about 7.9 x 10^26 W
- about 1.2 x 10^26 W
- about 3.9 x 10^26 W
- about 3.9 x 10^22 W
-
Star B has the same surface temperature as star A but twice the radius. What is L_B / L_A?
- 4
- 16
- 8
- 2
-
A star's peak wavelength falls from 900 nm to 600 nm. What is the ratio of its final to initial absolute temperature?
- 1.5
- 0.44
- 0.67
- 2.25
-
A black body's absolute temperature doubles while its surface area halves. Its power output was P before. What is it now?
- 8P
- 4P
- 16P
- 32P
-
Why does a real object emit less power than a black body at the same temperature?
- Real surfaces emit only visible light, not infrared radiation at the same temperature.
- Real surfaces have emissivity below 1, so they radiate less power than a black body.
- Real surfaces are always cooler than their measured temperature, so they radiate less.
- Real surfaces have zero surface area in the emission calculation, which lowers their power.
-
Which statement about black body radiation curves is correct?
- As temperature rises, the peak shifts to shorter wavelengths and the total area under the curve increases.
- The area under the curve falls as temperature rises.
- As temperature rises, the peak shifts to longer wavelengths and the area is unchanged.
- The curve keeps the same shape at all temperatures and only moves up.
-
Star X is hotter than star Y, and both have the same radius. Which is more luminous, and why?
- Star X, because L is proportional to T^4 for the same surface area.
- They are equally luminous, since luminosity depends only on radius.
- Star Y, because its peak wavelength is shorter.
- Star Y, because cooler stars emit more energy per second.
-
What is the main reason the peak wavelength of a hotter object shifts to shorter values?
- Heat makes emitted photons travel more slowly through space.
- Hotter objects absorb more visible light, so they emit less red light.
- Hotter objects emit their energy at higher frequencies, so the peak moves to shorter wavelengths.
- Higher temperature increases the speed of light inside the object.
-
Two stars have equal luminosity but different surface temperatures. Which has the larger radius?
- The cooler star, since a lower T needs a larger surface area to give the same L.
- They must have equal radii.
- The hotter star, since its peak wavelength is shorter.
- The hotter star, since it has the greater energy per unit area.
-
Why is Wien's law only an approximation for real stars?
- Stars are not perfect black bodies, so their spectra differ from the ideal black body curve.
- Wien's law only applies to objects that are cooler than 1000 K.
- Stars emit no light at the peak wavelength, so the law cannot be used.
- Wien's law requires the star's radius to be measured in metres.
-
A sphere of radius 0.10 m is at 400 K and is treated as a black body. What power does it emit? Use σ = 5.67 x 10^-8 W m^-2 K^-4.
- about 180 W
- about 45 W
- about 1800 W
- about 18 W
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