Lesson 8.3.1
8.3.1 Conservation of charge, energy and momentum in interactions Quiz: Pearson Edexcel Physics, Unit 8
20 questions
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Lesson 8.3.1, Conservation of charge, energy and momentum in interactions: 20 multiple choice questions for the Pearson Edexcel Physics (9PH0), Unit 8: Nuclear and Particle Physics, written with Revision Ninja.
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The 20 questions
-
Which quantities must be conserved in every particle interaction?
- Electric charge, total energy including rest mass energy, and momentum
- Electric charge and speed only, with no requirement on energy or momentum
- Kinetic energy alone, with charge and momentum allowed to change freely
- Number of particles and the mass of the heaviest particle only
-
What does the total charge before a particle interaction equal compared with the total charge after it?
- It is always larger than the total charge after the interaction
- It is equal to the total charge after the interaction
- It is zero in every interaction, so charge is not conserved
- It is always twice the total charge after the interaction
-
What does the curvature of a charged particle's track in a magnetic field indicate about that particle?
- Its momentum and the sign of its charge
- Its position at the moment of creation only
- Its rest mass and its lifetime only
- Its spin and the number of quarks it contains
-
A neutron decays into a proton, an electron and an antineutrino. What is the total charge of the products?
- +2, the combined charge of the proton and the electron
- -1, which is the charge of the electron alone
- +1, which is the charge of the proton alone
- Zero, the same as the neutron
-
What is the minimum total energy of the two photons produced when an electron and a positron at rest annihilate?
- 0.511 MeV
- 2.04 MeV
- 0 MeV
- 1.02 MeV
-
An electron and a positron at rest annihilate to produce two photons travelling in opposite directions. What is the total momentum of the two photons?
- Zero
- Equal to twice the momentum of one photon
- Equal to the mass energy of the electron divided by c
- Equal to the momentum of one photon
-
A stationary particle of rest energy 135 MeV decays into two photons of equal energy. What is the energy of each photon?
- 67.5 MeV
- 270 MeV
- 33.8 MeV
- 135 MeV
-
A stationary unstable particle decays into two particles of equal mass. How are their momenta related?
- They are equal in magnitude and opposite in direction
- They are zero, because the parent particle was at rest
- They are unequal, because one particle always carries all the momentum
- They are equal in magnitude and in the same direction
-
In pair production, a photon creates an electron and a positron. Why can a single electron not be produced instead?
- A single electron would have too much mass to be produced by a photon of any energy
- A single electron would not conserve charge, because the photon has no charge and the total charge would become -1
- A single electron would be produced, but it would immediately decay back into a photon
- A single electron would violate the conservation of momentum only, not of charge
-
In the annihilation of a stationary electron and a stationary positron, how does the total lepton number before the interaction compare with the total lepton number after it?
- It is +2 before and 0 after, because both particles count as leptons
- It is +1 before and +1 after, because the positron carries no lepton number
- It is zero both before and after, because the electron (+1) and positron (-1) cancel and photons carry no lepton number
- It is -2 before and +2 after, because the photons carry lepton number
-
A 2.0 MeV photon creates an electron-positron pair in the presence of a nucleus that absorbs the recoil momentum. What total kinetic energy is shared between the electron and positron?
- 2.0 MeV
- 0.51 MeV
- About 0.98 MeV
- 1.02 MeV
-
Why can a photon not create an electron-positron pair in empty space without another body present?
- Energy could never be conserved, because photons always carry zero energy
- Charge could never be conserved, because positrons cannot exist in a vacuum
- The photon would have to change its speed, which is forbidden by the laws of physics
- Momentum could not be conserved, because the photon's momentum must be shared with a third body such as a nucleus
-
A proton and an antiproton, both at rest, annihilate. Approximately what total energy is released? Each has rest energy of about 0.94 GeV.
- About 0.94 GeV
- About 1.9 GeV
- About 3.8 GeV
- About 0.51 GeV
-
A track in a bubble chamber has radius 0.50 m in a uniform magnetic field of flux density 0.30 T, for a particle of charge 1.6 x 10^-19 C. What is the momentum of the particle?
- 2.4 x 10^-20 kg m s^-1
- 3.2 x 10^-19 kg m s^-1
- 1.2 x 10^-20 kg m s^-1
- 4.8 x 10^-20 kg m s^-1
-
A student claims that an interaction is allowed whenever total energy is conserved. Which response is correct?
- The student is wrong because particle interactions do not conserve energy at any stage
- The student is wrong: charge, momentum and other quantities such as lepton number must also be conserved
- The student is right, but only when the particles involved have no charge at all
- The student is right: energy conservation alone decides whether any particle interaction is allowed
-
Why is the total momentum of the decay products of a particle that was at rest equal to zero?
- Decay products always move at the speed of light, so their momenta cancel exactly
- Momentum is never conserved in particle decays, so the products must be at rest
- Each decay product has zero mass, so each has zero momentum
- Momentum is conserved, and the parent particle had zero momentum before it decayed
-
Why is the reaction e^- -> gamma (a single electron decaying into a single photon) forbidden?
- The photon would travel faster than light, which is forbidden by the reaction
- The photon has too much energy to be created from an electron of any mass
- The electron's charge of -1 cannot be matched by a photon, which has zero charge, so charge would not be conserved
- The reaction would require a neutron to be present, which is never available
-
A pi-zero meson (charge 0) is produced in the collision p + p -> p + p + pi0. What is the total charge after the collision?
- 0
- +3
- +1
- +2
-
A particle at rest with rest energy 1000 MeV decays into two particles. One of them has energy 600 MeV. What is the energy of the other?
- 300 MeV
- 1600 MeV
- 600 MeV
- 400 MeV
-
Which conservation law forbids the decay of a proton into a positron and a neutral pion?
- Conservation of mass, because the mass of the products is always smaller than the proton
- Conservation of momentum, because the neutral pion carries no momentum
- Conservation of baryon number, because the proton has baryon number 1 but the products have none
- Conservation of electric charge, because the total charge changes from +1 to zero
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