Lesson 2.6.1
2.6.1 Work and kinetic energy Quiz: Pearson Edexcel Physics, Unit 2
20 questions
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Lesson 2.6.1, Work and kinetic energy: 20 multiple choice questions for the Pearson Edexcel Physics (9PH0), Unit 2: Mechanics, written with Revision Ninja.
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The 20 questions
-
The work done by a constant force is equal to:
- The force squared multiplied by the displacement.
- The force divided by the displacement.
- The force multiplied by the displacement in the direction of the force.
- The force added to the displacement.
-
The SI unit of work is the:
- Joule (J)
- Kilogram metre per second (kg m s^-1)
- Newton (N)
- Watt (W)
-
The kinetic energy of a body of mass m moving at speed v is:
- m v^2
- (1/2) m v
- (1/2) m v^2
- m v
-
The work done by a force that acts perpendicular to the direction of motion is:
- Zero
- Equal to the momentum
- Equal to the force times the distance
- Equal to the kinetic energy
-
A 5.0 kg object moves at 4.0 m s^-1. What is its kinetic energy?
- 10 J
- 40 J
- 20 J
- 80 J
-
A 20 N force acts at 60 degrees to the horizontal and the object moves 3.0 m horizontally. What work does the force do?
- 60 J
- 30 J
- 52 J
- 17 J
-
A 1000 kg car speeds up from 10 m s^-1 to 20 m s^-1 with no friction. What is the work done by the engine?
- 1.0 x 10^5 J
- 1.5 x 10^4 J
- 1.5 x 10^5 J
- 3.0 x 10^5 J
-
A block is pulled 4.0 m by a 15 N force, and a friction force of 5.0 N acts opposite to the motion. What is the work done against friction?
- 15 J
- 40 J
- 60 J
- 20 J
-
A car has 2.0 x 10^5 J of kinetic energy and brakes with a constant friction force of 8000 N. What is the stopping distance?
- 2.5 m
- 25 m
- 250 m
- 16 m
-
A 2.0 kg object has momentum 6.0 kg m s^-1. What is its kinetic energy?
- 18 J
- 3.0 J
- 9.0 J
- 36 J
-
The speed of a body is doubled. By what factor does its kinetic energy change?
- 2 times
- 4 times
- 8 times
- half
-
A 3.0 kg block accelerates from rest to 6.0 m s^-1 over a distance of 4.0 m under a constant force. What is the force?
- 4.5 N
- 27 N
- 13.5 N
- 54 N
-
The work done by a variable force over a displacement can be found from:
- The area under a force-displacement graph.
- The area under a velocity-time graph.
- The intercept of a force-displacement graph with the force axis.
- The gradient of a force-displacement graph.
-
A sledge is pulled with a rope of tension 50 N at 30 degrees to the ground over a distance of 10 m. What is the work done by the tension?
- 433 J
- 250 J
- 500 J
- 866 J
-
A 1500 kg car brakes from 25 m s^-1 and a friction force of 6000 N acts. What is the stopping distance?
- 78 m
- 25 m
- 39 m
- 156 m
-
Which statement about work and kinetic energy is correct?
- The net work done is always equal to the change in momentum.
- Kinetic energy is unchanged by a net force.
- The net work done on a body equals its total energy.
- The net work done on a body equals its change in kinetic energy.
-
A 1.0 kg object moving at 10 m s^-1 is brought to rest by a constant force over 5.0 m. What is the magnitude of the force?
- 10 N
- 5.0 N
- 20 N
- 50 N
-
A 40 N force is applied at an angle of 0 degrees to the displacement over a distance of 2.5 m. What is the work done?
- 100 J
- 16 J
- 80 J
- 0 J
-
A body moves in a circle at constant speed. What is the work done by the centripetal force?
- Equal to the centripetal force times the radius
- Equal to the kinetic energy
- Zero
- Equal to the momentum times the radius
-
A 2.0 kg object increases its speed from 3.0 m s^-1 to 5.0 m s^-1. What is the net work done on it?
- 32 J
- 10 J
- 16 J
- 8.0 J
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