Lesson 2.1.1
2.1.1 Equations for uniformly accelerated motion Quiz: Pearson Edexcel Physics, Unit 2
20 questions
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Lesson 2.1.1, Equations for uniformly accelerated motion: 20 multiple choice questions for the Pearson Edexcel Physics (9PH0), Unit 2: Mechanics, written with Revision Ninja.
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The 20 questions
-
Which SUVAT equation does NOT contain the final velocity v?
- v^2 = u^2 + 2as
- v = u + at
- s = (u + v)t/2
- s = ut + (1/2)at^2
-
Which SUVAT equation does NOT involve displacement s?
- s = ut + (1/2)at^2
- s = (u + v)t/2
- v = u + at
- v^2 = u^2 + 2as
-
A car starts from rest and accelerates uniformly at 2 m s^-2 for 5 s. What is its final speed?
- 20 m s^-1
- 5 m s^-1
- 2.5 m s^-1
- 10 m s^-1
-
The same car (from rest, a = 2 m s^-2) is in motion for 5 s. What is its displacement?
- 25 m
- 5 m
- 50 m
- 10 m
-
A ball is thrown vertically upwards at 15 m s^-1 with g = 10 m s^-2 (air resistance ignored). How long does it take to reach its maximum height?
- 3.0 s
- 1.5 s
- 0.67 s
- 15 s
-
A train travelling at 20 m s^-1 brakes with a uniform acceleration of -0.5 m s^-2 until it stops. What distance does it cover while stopping?
- 400 m
- 40 m
- 200 m
- 800 m
-
A body accelerates uniformly from 4 m s^-1 to 12 m s^-1. What is its average velocity?
- 8 m s^-1
- 12 m s^-1
- 4 m s^-1
- 16 m s^-1
-
In uniformly accelerated motion, the quantity (u + v)t/2 represents:
- Final velocity
- Acceleration
- Displacement
- Change in momentum
-
A ball is dropped from rest and falls freely with g = 9.8 m s^-2. What is its speed after 2 s?
- 19.6 m s^-1
- 4.9 m s^-1
- 39.2 m s^-1
- 9.8 m s^-1
-
A cyclist's speed increases uniformly from 3 m s^-1 to 9 m s^-1 in 4 s. What is her acceleration?
- 0.67 m s^-2
- 12 m s^-2
- 1.5 m s^-2
- 3.0 m s^-2
-
A car decelerates uniformly from 25 m s^-1 to rest in a distance of 50 m. How long does it take to stop?
- 4 s
- 0.5 s
- 2 s
- 8 s
-
A stone dropped from a cliff hits the ground 3.0 s later. Ignoring air resistance and taking g = 9.8 m s^-2, what is the height of the cliff?
- 88.2 m
- 29.4 m
- 22.1 m
- 44.1 m
-
A body starts from rest with constant acceleration. What is the ratio of the distance covered in the 5th second to that covered in the 1st second?
- 4.5
- 9
- 5
- 25
-
A body starts from rest and has a uniform acceleration. A velocity of 6 m s^-1 is reached after 10 s. What is its displacement?
- 6 m
- 30 m
- 15 m
- 60 m
-
Which assumption must hold to use the SUVAT equations?
- The time is measured from maximum height.
- The velocity is always zero at the start.
- The acceleration is uniform (constant) throughout the motion.
- The displacement is always negative.
-
A car accelerates uniformly from rest to 30 m s^-1 over a distance of 100 m. How long does this take?
- 10 s
- 0.15 s
- 6.7 s
- 3.3 s
-
A ball is thrown upwards at 12 m s^-1. Taking upwards as positive and g = 10 m s^-2, what is its velocity after 2 s?
- 32 m s^-1 downwards
- 8 m s^-1 downwards
- 12 m s^-1 upwards
- 8 m s^-1 upwards
-
A body starts from rest with a = 4 m s^-2. How far does it travel during the 3rd second?
- 6 m
- 10 m
- 18 m
- 8 m
-
Which of these quantities in SUVAT equations is a scalar?
- Displacement
- Time
- Velocity
- Acceleration
-
A trolley accelerates from rest at 0.80 m s^-2 for 2.5 s. What is its displacement?
- 2.5 m
- 5.0 m
- 4.0 m
- 1.0 m
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