Lesson 5.7.1
5.7.1 Solving simple trigonometric equations Quiz: Pearson Edexcel Maths, Unit 5
20 questions
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Lesson 5.7.1, Solving simple trigonometric equations: 20 multiple choice questions for the Pearson Edexcel Maths (9MA0), Unit 5: Trigonometry, written with Revision Ninja.
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The 20 questions
-
What is the principal value of arcsin(0.5) in radians?
- pi / 6
- pi / 3
- pi / 2
- pi / 4
-
Solve sin(theta) = 0.5 for the interval 0 to 2pi radians.
- pi / 3 and 2pi / 3
- pi / 6 and pi / 3
- pi / 6 and 5pi / 6
- pi / 3 and 4pi / 3
-
Find all solutions to cos(theta) = 0 inside the interval 0 to 2pi.
- pi / 4 and 7pi / 4
- pi / 2 and 3pi / 2
- pi and 2pi
- 0 and pi
-
What is the second solution for tan(theta) = 1 if the first is pi / 4?
- 5pi / 4
- 7pi / 4
- pi / 2
- 3pi / 4
-
Solve tan(theta) = -1 for principal value in radians.
- -pi / 6
- -pi / 2
- -pi / 4
- -pi / 3
-
How many solutions exist for sin(theta) = 2 in the real number domain?
- One
- Infinite
- Zero
- Two
-
Solve cos(theta) = -0.5 for the primary interval 0 to 360 degrees.
- 60 and 300 degrees
- 150 and 210 degrees
- 135 and 225 degrees
- 120 and 240 degrees
-
What is the exact value of arccos(0) in degrees?
- 0 degrees
- 180 degrees
- 90 degrees
- 270 degrees
-
How many distinct solutions does sin(2theta) = 0.5 have for theta between 0 and 2pi?
- 2
- 8
- 4
- 1
-
Find the general solution for sin(theta) = 0 in terms of integer n.
- n * pi / 2
- 2n * pi
- n * pi
- pi + 2n * pi
-
State the general solution for cos(theta) = 1 in terms of integer n.
- pi / 2 + n * pi
- n * pi
- 2n * pi
- pi + 2n * pi
-
Solve 2 * sin(theta) - 1 = 0 for theta between 0 and 360 degrees.
- 30 and 150 degrees
- 60 and 120 degrees
- 45 and 135 degrees
- 30 and 330 degrees
-
Solve tan(3theta) = 0 for the smallest positive angle theta in degrees.
- 30 degrees
- 90 degrees
- 60 degrees
- 0 degrees
-
What is the range of values for valid solutions of sin(theta) = k?
- -1 <= k <= 1
- k <= -1
- k >= 1
- All real numbers
-
Find the number of solutions to cos(theta) = 0.5 within 0 to 2pi radians.
- Three
- Two
- Four
- One
-
Solve cos(theta - pi / 3) = 1 for the principal value of theta.
- 0
- pi / 6
- pi / 3
- 2pi / 3
-
Solve 3 * tan^2(theta) - 1 = 0 for positive acute theta.
- 60 degrees
- 45 degrees
- 90 degrees
- 30 degrees
-
Identify the quadrant where both sine and cosine are negative.
- First quadrant
- Third quadrant
- Fourth quadrant
- Second quadrant
-
Solve sin(theta) = -0.5 for the principal value in degrees.
- -30 degrees
- -90 degrees
- -45 degrees
- -60 degrees
-
Solve cos^2(theta) = 1 for theta between 0 and 2pi radians.
- pi / 3, 5pi / 3
- pi / 4, 7pi / 4
- 0, pi, 2pi
- pi / 2, 3pi / 2
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