Lesson 9.1-9.4
9.1-9.4 First order differential equations Quiz: Pearson Edexcel Further Maths, Unit 9
20 questions
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Lesson 9.1-9.4, First order differential equations: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 9: Differential equations, written with Revision Ninja.
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The 20 questions
-
Which is the integrating factor for dy/dx + P(x) y = Q(x)?
- integral of P(x) dx
- e^(integral of P(x) dx)
- e^(integral of Q(x) dx)
- e^(-integral of P(x) dx)
-
What is the general solution of dy/dx + 2y = 0?
- y = A e^(2x)
- y = A x e^(-2x)
- y = A/(2x)
- y = A e^(-2x)
-
Solve dy/dx + y = e^x.
- y = e^x + C e^(-x)
- y = e^x + C e^x
- y = (1/2) e^x + C e^x
- y = (1/2) e^x + C e^(-x)
-
Solve dy/dx = 2xy with y(0) = 1.
- y = 2e^(x^2)
- y = e^(2x)
- y = x^2 + 1
- y = e^(x^2)
-
Solve dy/dx = y/x with y(1) = 2.
- y = 2x
- y = x + 1
- y = 2/x
- y = x^2 + 1
-
Solve dy/dx + y/x = x for x > 0.
- y = x^2/3 + C/x
- y = x^2 + C/x
- y = x^3/3 + C/x
- y = x^2/3 + C x
-
A particle has dv/dt = -kv with v(0) = 20. What is v(t)?
- v = 20/(kt)
- v = 20 - kt
- v = 20 e^(-kt)
- v = 20 e^(kt)
-
Newton's law of cooling is dT/dt = -k(T - 20) with T(0) = 100. What is T(t)?
- T = 20 + 80 e^(-kt)
- T = 100 e^(-kt) + 20
- T = 100 e^(-kt)
- T = 20 + 100 e^(kt)
-
A population satisfies dP/dt = 0.05P with P(0) = 1000. Find P(10) to 1 decimal place.
- 5000.0
- 1648.7
- 1500.0
- 1050.0
-
What is the integrating factor for dy/dx + (3/x) y = x with x > 0?
- x^2/3
- x^3
- x^(-3)
- 3x
-
Solve dy/dx + y = 2x with y(0) = 0.
- y = 2x - 2 - 2e^(-x)
- y = 2x - 2 + 2e^(-x)
- y = 2 - 2e^(-x)
- y = 2x + 2e^(-x)
-
Which method solves dy/dx = x/y, and what is the general solution?
- Separation giving y^2 = 2x + C
- Integrating factor giving y = x^2 + C
- Substitution giving y = Cx
- Separation of variables giving y^2 = x^2 + C
-
What is the solution of dy/dx = 3y with y(0) = 4, evaluated at x = 1?
- 4e^3, about 80.3
- 4 + 3e, about 12.2
- 12e, about 32.6
- 4e, about 10.9
-
What is a general solution of dy/dx = 5y?
- y = A + 5x
- y = A x^5
- y = A e^(5x)
- y = 5A e^x
-
What is needed to turn a general solution into a particular solution?
- The integrating factor
- An initial or boundary condition
- The limiting gradient as x tends to infinity
- The auxiliary equation
-
What is the integrating factor for dy/dx - (2/x) y = x^2?
- x^(-2)
- e^(2x)
- x^2
- -2/x
-
A body has dv/dt = 10 - 2v with v(0) = 0. What is v(t)?
- v = 10(1 - e^(-2t))
- v = 10t - 2
- v = 5 e^(-2t)
- v = 5(1 - e^(-2t))
-
Solve dy/dx + 2xy = 2x with y(0) = 3.
- y = 2 + e^(-x^2)
- y = 1 + 3e^(-x^2)
- y = 1 + 2e^(x^2)
- y = 1 + 2e^(-x^2)
-
Solve dy/dx = 2y/(x + 1) with y(0) = 1.
- y = 2(x + 1)
- y = x^2 + 1
- y = (x + 1)^2
- y = e^(2x)
-
A body obeys dT/dt = -0.1(T - 20) with T(0) = 100 in a room at 20. How long does it take to cool to 60?
- About 6.93 time units
- About 4.00 time units
- About 10.0 time units
- About 13.86 time units
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