Lesson 7.3
7.3 Area enclosed by polar curves Quiz: Pearson Edexcel Further Maths, Unit 7
20 questions
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Lesson 7.3, Area enclosed by polar curves: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 7: Polar coordinates, written with Revision Ninja.
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The 20 questions
-
Which formula gives the area enclosed by the polar curve r = f(theta) between theta = alpha and theta = beta?
- Area = integral from alpha to beta of r d(theta)
- Area = (1/2) integral from alpha to beta of r^2 d(theta)
- Area = (1/2) integral from alpha to beta of r d(theta)
- Area = integral from alpha to beta of r^2 d(theta)
-
What does theta represent in polar coordinates (r, theta)?
- The distance from the pole to the point
- The gradient of the tangent at the point
- The angle measured from the initial line
- The perpendicular height above the initial line
-
What is the area enclosed by the circle r = a, where a is greater than 0?
- a^2 / 2
- pi a
- pi a^2
- 2 pi a^2
-
What is the area enclosed by the curve r = 2 for 0 <= theta <= pi/2?
- 2
- pi/2
- 2 pi
- pi
-
Find the area enclosed by r = 4 sin(theta) for 0 <= theta <= pi.
- 16 pi
- 2 pi
- 8 pi
- 4 pi
-
Find the area enclosed by r = 2 cos(theta) for -pi/2 <= theta <= pi/2.
- pi
- pi/2
- 4 pi
- 2 pi
-
Find the area enclosed by the cardioid r = a(1 + cos theta) for 0 <= theta <= 2 pi.
- 2 pi a^2 / 3
- pi a^2 + 2 pi a
- 3 pi a^2 / 4
- 3 pi a^2 / 2
-
Find the area enclosed by r = theta for 0 <= theta <= pi.
- pi^3 / 6
- pi^2 / 2
- pi^3 / 2
- pi^3 / 3
-
Find the area inside the cardioid r = 1 + cos theta but outside the circle r = 1.
- 2 + pi/4
- pi/4
- 1 + pi/4
- 2 + pi/2
-
What is the total area enclosed by the four-petal rose r = sin(2 theta)?
- pi
- pi/4
- pi/8
- pi/2
-
At which points does the tangent to r = f(theta) run parallel to the initial line?
- Where r = 0 on the curve
- Where dy/d(theta) = 0 and dx/d(theta) is not zero
- Where dr/d(theta) = 0 only
- Where dx/d(theta) = 0 and dy/d(theta) is not zero
-
Why does the polar area formula use r^2 rather than r?
- Because the polar area always equals the integral of r with respect to theta
- Because the arc length of a polar curve is the integral of r^2
- Because theta must be converted to degrees before r is squared
- Because a thin sector of radius r and angle d(theta) has area (1/2) r^2 d(theta)
-
Find the area enclosed by the cardioid r = 1 + sin(theta) over one full cycle.
- 2 pi
- 3 pi
- pi
- 3 pi / 2
-
Find the area of the sector of the circle r = 3 for 0 <= theta <= pi/3.
- 3 pi / 2
- 3 pi
- pi/2
- 9 pi / 2
-
Which polar equation describes an Archimedean spiral?
- r = k theta
- r = a(1 + cos theta)
- r = a sec(alpha - theta)
- r = a cos(2 theta)
-
Which shape is described by r^2 = a^2 cos(2 theta)?
- A circle centred on the pole with radius a
- A lemniscate (figure of eight)
- A cardioid with a single inner loop
- An Archimedean spiral that winds outward
-
Find the area of the sector of r = 6 between theta = pi/6 and theta = pi/2.
- 3 pi
- 12 pi
- pi/3
- 6 pi
-
Find the area enclosed by the circle r = 4 cos(theta).
- 2 pi
- 8 pi
- 4 pi
- 16 pi
-
When finding the area of a single loop of a polar curve, what must the chosen theta-interval do?
- Cover the full interval from 0 to 2 pi
- Trace that loop exactly once
- Give the largest possible value of r
- Make r equal to zero at both ends
-
Find the area enclosed by the cardioid r = 2(1 - cos theta).
- 12 pi
- 6 pi
- 4 pi
- 3 pi
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