Lesson 4C.5.1
4C.5.1 Kinematics of a particle moving in a straight line with variable acceleration Quiz: Pearson Edexcel Further Maths, Unit 34
20 questions
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Lesson 4C.5.1, Kinematics of a particle moving in a straight line with variable acceleration: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 34: Kinematics with variable acceleration, written with Revision Ninja.
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The 20 questions
-
Which expression gives the velocity v of a particle whose displacement is x(t)?
- dx/dt
- x/t
- d^2x/dt^2
- dv/dt
-
To find displacement x(t) from a known velocity v(t), what is done?
- integrate v with respect to t
- differentiate v with respect to t
- integrate v with respect to x
- multiply v by t
-
To find velocity from a known acceleration a(t), what is done?
- divide a by t
- integrate a with respect to t and add a constant
- multiply a by t
- differentiate a with respect to t
-
How is the constant of integration found when integrating for velocity or displacement?
- from the total distance travelled
- from the acceleration alone
- from the mass of the particle
- from initial conditions
-
If the velocity of a particle is negative, the particle is moving
- at rest
- with negative acceleration
- with negative speed
- in the negative direction
-
When acceleration acts opposite to the direction of velocity, the speed
- becomes zero at once
- stays constant
- increases
- decreases
-
The area under a velocity-time graph gives the
- acceleration
- force
- displacement
- momentum
-
A particle has velocity v = 3t^2 - 6t and x = 0 at t = 0. What is its displacement at t = 3 s?
- 0 m
- 9 m
- -9 m
- 27 m
-
A particle has acceleration a = 6t - 4 and velocity 2 m/s at t = 0. What is its velocity at t = 2 s?
- 6 m/s
- 2 m/s
- 10 m/s
- 4 m/s
-
A particle has acceleration a = 2x and starts from rest at x = 0. What is its speed at x = 3 m?
- sqrt(6) m/s
- 3 sqrt(2) m/s
- 9 m/s
- 6 m/s
-
A particle has acceleration a = -2v and speed 10 m/s at t = 0. What is its speed at t = 1 s?
- 5 m/s
- 8 m/s
- 10 e^(-2) m/s, about 1.35 m/s
- 10 e^2 m/s
-
A particle has displacement x = t^3 - 6t^2 + 9t. What is its velocity at t = 1 s?
- 0 m/s
- -3 m/s
- 6 m/s
- 3 m/s
-
A particle has acceleration a = 12 - 3t^2 and starts from rest at t = 0. What is its velocity at t = 2 s?
- 12 m/s
- 16 m/s
- 24 m/s
- 8 m/s
-
A particle has velocity v = 4 + 2x m/s. What is its acceleration at x = 3 m?
- 16 m/s^2
- 10 m/s^2
- 14 m/s^2
- 20 m/s^2
-
A particle has velocity v = 2t + 3 m/s and x = 1 m at t = 0. What is its displacement at t = 2 s?
- 9 m
- 13 m
- 7 m
- 11 m
-
A particle starts from rest at the origin with acceleration a = 4 - 2t m/s^2. What is its displacement when it next comes to rest?
- 64/3 m
- 16 m
- 8/3 m
- 32/3 m
-
A particle has velocity v = 3 sqrt(x) m/s. What is its acceleration at x = 4 m?
- 9 m/s^2
- 4.5 m/s^2
- 1.5 m/s^2
- 6 m/s^2
-
A particle starts from rest and has acceleration a = 10 - 0.5v m/s^2. What is its limiting speed?
- 20 m/s
- 5 m/s
- 10 m/s
- 40 m/s
-
Why does finding displacement from velocity need an initial condition?
- Displacement and velocity are the same quantity
- Integration gives displacement only up to an additive constant, which the initial displacement fixes
- The integral of velocity is always zero
- Velocity is always zero at the start
-
A particle starts from rest with acceleration a = 12 - 2t m/s^2. At what time is its velocity greatest?
- 12 s
- 6 s
- 3 s
- 2 s
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