Lesson 4C.3.3
4C.3.3 Toppling and sliding of rigid bodies Quiz: Pearson Edexcel Further Maths, Unit 32
20 questions
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Lesson 4C.3.3, Toppling and sliding of rigid bodies: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 32: Centres of mass and equilibrium of rigid bodies, written with Revision Ninja.
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The 20 questions
-
A rigid box on a rough plane is about to tip over. What happens to the vertical line through its centre of mass?
- it falls outside the base, beyond the edge
- it falls inside the base, near the centre
- it passes above its top face
- it passes through its midpoint on the slope
-
A body on a rough inclined plane slides when which condition holds?
- tan theta exceeds the coefficient of friction
- sin theta exceeds the coefficient of friction
- cos theta exceeds the coefficient of friction
- tan theta is less than the coefficient of friction
-
A uniform block has base half-width b and centre of mass at height h above the base, on a slope of angle theta. Which condition gives toppling?
- tan theta > h/b
- tan theta < b/h
- tan theta > 2b/h
- tan theta > b/h
-
When a body is on the point of sliding on a rough plane, the friction force equals
- mu/R
- mu R
- R/mu
- mg sin theta always
-
A block is on the verge of toppling about a lower edge. Where does the normal reaction act?
- at the top of the block
- at the centre of the base
- at the centre of mass
- at the edge about which it would tip
-
A block on a horizontal plane is pushed horizontally. Which condition ensures it does not topple?
- the vertical line through its centre of mass passes within its base
- friction is greater than its weight
- the push passes through its top face
- the weight of the block is zero
-
A block is about to slide up a rough incline under an applied force. In which direction does friction act?
- zero at limiting equilibrium
- up the slope
- down the slope
- perpendicular to the slope
-
A block rests on a rough slope at 30 degrees with coefficient of friction 0.5. Does it slide?
- Yes, since cos 30 degrees exceeds 0.5
- No, since friction always exceeds the weight component
- No, since sin 30 degrees is less than 0.5
- Yes, since tan 30 degrees (about 0.577) exceeds 0.5
-
A uniform box with a square base of width 0.6 m has its centre of mass 0.8 m above the base. What is the critical value of tan theta for toppling on a slope?
- 1.33
- 0.3
- 0.375
- 0.75
-
A block of weight 20 N has base half-width 0.5 m and centre of mass 1 m above the base. It is pushed horizontally with a 10 N force applied at height 1 m. What happens?
- It slides but never topples
- It is on the point of toppling, since the moments about the lower edge are equal
- It topples forwards at once
- It is stable, since the push is less than the weight
-
A 5 kg block rests in equilibrium on a rough slope at 20 degrees without sliding (g = 10 m/s^2). What is the friction force?
- 17.1 N
- 18.2 N
- 47.0 N
- 1.7 N
-
A block is on the point of sliding on a rough plane with coefficient of friction 0.75. What is the angle of the plane?
- 36.9 degrees
- 48.8 degrees
- 41.4 degrees
- 53.1 degrees
-
Under what condition does a uniform block topple before it slides on a rough slope?
- b is greater than h
- b/h is less than mu
- b/h is greater than mu
- mu is less than 1
-
A 4 kg block rests on a rough horizontal floor with coefficient 0.3 (g = 10 m/s^2). It is pushed horizontally with 10 N and stays at rest. What is the friction force?
- 12 N
- 40 N
- 0 N
- 10 N
-
A 2 kg block is on a rough slope where tan theta = 0.5 and friction is limiting (g = 10 m/s^2). What is the normal reaction?
- 8 sqrt(5) N, about 17.9 N
- 4 sqrt(5) N, about 8.9 N
- 20 N
- 10 N
-
A block has base half-width 0.4 m and centre of mass height 1.2 m, and rests on a rough slope with coefficient 0.6. As the slope angle increases, what happens first?
- Sliding, at tan theta = 0.6
- Toppling, at tan theta = 0.6
- Toppling, at tan theta = 1/3
- Sliding, at tan theta = 1/3
-
A uniform cube of side a rests on a rough slope with coefficient of friction greater than 1. At what slope angle does it topple?
- arctan(2), about 63.4 degrees
- 30 degrees
- 45 degrees
- 60 degrees
-
A uniform block of weight 50 N has base half-width 0.2 m and centre of mass height 0.5 m. It is pushed horizontally at the height of its centre of mass on a rough floor. What push first causes toppling?
- 50 N
- 20 N
- 5 N
- 10 N
-
Why can a body topple before it slides on a rough incline when the coefficient of friction is large?
- The base is wider than the centre of mass height
- The normal reaction increases as the slope steepens
- Friction always exceeds the weight component, so sliding never occurs
- The toppling angle, where tan theta equals b/h, is smaller than the sliding angle when the base is narrow compared with the height
-
A block has b/h = 0.5 and coefficient of friction 0.8 on a rough slope. At what angle does it first move, and how?
- 14.0 degrees, by toppling
- 26.6 degrees, by toppling
- 45 degrees, by sliding
- 38.7 degrees, by sliding
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