Lesson 4B.7.2-4B.7.3
4B.7.2-4B.7.3 Paired and two-sample t-tests Quiz: Pearson Edexcel Further Maths, Unit 24
20 questions
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Lesson 4B.7.2-4B.7.3, Paired and two-sample t-tests: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 24: t-tests, written with Revision Ninja.
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The 20 questions
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For a paired t-test with n pairs and differences d, which statistic is used under H0?
- t = d-bar / (s_d sqrt(n)), with 2n - 2 degrees of freedom
- chi-squared = (n - 1) s_d^2 / sigma^2
- z = d-bar / sigma, with known sigma
- t = d-bar / (s_d / sqrt(n)), with n - 1 degrees of freedom
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What is the pooled estimate of the common variance for two independent samples of sizes n1 and n2?
- s_p^2 = (s1^2 + s2^2) / 2
- s_p^2 = (n1 s1^2 + n2 s2^2) / (n1 + n2)
- s_p^2 = ((n1 - 1) s1^2 + (n2 - 1) s2^2) / (n1 + n2)
- s_p^2 = ((n1 - 1) s1^2 + (n2 - 1) s2^2) / (n1 + n2 - 2)
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What are the degrees of freedom for the pooled two-sample t-test?
- n1 + n2
- min(n1, n2) - 1
- n1 + n2 - 1
- n1 + n2 - 2
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Which conditions are required for the pooled two-sample t-test with equal but unknown variances?
- Samples of equal size with different population variances
- Samples from populations with unknown distributions and any variances
- Independent samples from normal populations with equal population variances
- Paired observations from populations with equal means
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When is a paired t-test appropriate rather than a two-sample test?
- When the observations are matched pairs, such as the same individuals measured twice
- When the population variances are known
- When the two samples have different sizes
- When the two samples are large and independent with known variances
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Why is a paired test usually more powerful than an unpaired test when the pairs are positively correlated?
- Pairing avoids the need for the t distribution
- Pairing doubles the sample size, so the test has twice as many observations
- Pairing removes between-subject variation, which reduces the variance of the differences
- Pairing increases the variance of the differences
-
What is a 95% confidence interval for mu1 - mu2 when the variances are equal but unknown?
- (x-bar - y-bar) +/- t(n1 + n2 - 2) sqrt(s1^2/n1 + s2^2/n2)
- (x-bar - y-bar) +/- t(n1 + n2 - 2) s_p sqrt(n1 + n2)
- (x-bar - y-bar) +/- z s_p sqrt(1/n1 + 1/n2)
- (x-bar - y-bar) +/- t(n1 + n2 - 2) s_p sqrt(1/n1 + 1/n2)
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Five paired differences are 2, 4, 1, 3, 0. What is the t statistic for H0: mu_d = 0, to 2 decimal places?
- 2.83
- 0.71
- 1.58
- 2.00
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Two independent samples have n1 = 8, s1 = 3 and n2 = 10, s2 = 4. What is the pooled variance s_p^2, to 2 decimal places?
- 12.50
- 12.94
- 14.00
- 11.50
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Using s_p^2 = 12.94 with n1 = 8 and n2 = 10, what is the t statistic for a difference of means of 5, to 2 decimal places?
- 5.00
- 2.93
- 1.71
- 0.34
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The statistic t = 2.93 has 16 df. The two-tailed 5% critical value is 2.120. What is the conclusion?
- Accept H0, since the population variances are not equal
- Reject H0 only if the statistic exceeds 5.00
- Do not reject H0, since the samples differ in size
- Reject H0, since 2.93 exceeds 2.120, so there is evidence the means differ
-
Ten paired differences have mean 2 and standard deviation 4. What is the 95% confidence interval for the mean difference, to 2 decimal places? (t value with 9 df is 2.262.)
- (-2.00, 6.00)
- (1.14, 2.86)
- (0.00, 4.00)
- (-0.86, 4.86)
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Two independent samples have n1 = 10 with s1^2 = 4 and n2 = 20 with s2^2 = 9. What is the pooled variance s_p^2, to 2 decimal places?
- 6.00
- 8.25
- 6.50
- 7.39
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A paired confidence interval for the difference (after minus before) is (-2.8, -0.2). What can be concluded?
- The mean increased by 1.5, which is significant
- Only the sign matters, and the test is not significant
- There is no change, since the interval includes zero
- The measurement tends to fall after the change, and since the interval excludes zero there is evidence of a change
-
Two independent samples each have n = 5, with mean difference 4, and s1 = s2 = 2. What is the 95% confidence interval for mu1 - mu2, to 2 decimal places? (t value with 8 df is 2.306.)
- (1.08, 6.92)
- (1.67, 6.33)
- (2.00, 6.00)
- (0.09, 7.91)
-
A researcher uses an unpaired two-sample test on data that are naturally paired and positively correlated. What is the consequence?
- The standard error is smaller, so the test has higher power
- The degrees of freedom double to 2(n - 1)
- The standard error is larger than the paired analysis would give, so the test has lower power
- The test becomes invalid because the data are not normal
-
Fifteen paired differences have mean 1.2 and standard deviation 2.0. What is the t statistic for H0: mu_d = 0, to 2 decimal places?
- 0.62
- 1.20
- 2.32
- 3.87
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Two independent samples each have 10 observations, with sample standard deviations 2 and 8. Is the pooled t-test appropriate?
- Appropriate, because equal sample sizes cancel the variance difference
- Appropriate, since both samples are normal
- Appropriate, but only if the two sample means are equal
- Not appropriate, since the sample variances differ by a factor of 16, so the equal-variance assumption looks doubtful
-
Six paired differences are 3, 2, 4, 1, 5, 3. What is the t statistic for H0: mu_d = 0, to 2 decimal places?
- 2.45
- 3.00
- 1.41
- 5.20
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Why does pooling the two sample variances give a more precise test?
- Pooling doubles the degrees of freedom to 2(n - 1)
- Combining the two variance estimates gives a better estimate of the common variance than either sample alone
- Pooling removes the need for the populations to be normal
- Pooling makes the two sample means equal
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