Lesson 3D.5.3
3D.5.3 The Simplex algorithm for maximising and minimising Quiz: Pearson Edexcel Further Maths, Unit 39
20 questions
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Lesson 3D.5.3, The Simplex algorithm for maximising and minimising: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 39: Linear programming, written with Revision Ninja.
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The 20 questions
-
Which type of constraint can the basic Simplex method handle directly, starting from the origin?
- Equality (=) constraints only
- Both ≤ and ≥ constraints with any sign of right-hand side
- Less-than-or-equal (≤) constraints with non-negative right-hand sides
- Greater-than-or-equal (≥) constraints only
-
In a maximisation Simplex tableau, which entry of the objective row is used to choose the entering variable?
- The largest coefficient in the first constraint row
- The largest positive entry in the Value column
- The most negative entry in the objective (P) row
- The smallest positive entry in the objective row
-
What does the slack variable s1 represent in the constraint 3x + 2y ≤ 20?
- The profit contribution made by the first constraint
- The coefficient that turns the inequality into an equation
- The amount by which 3x + 2y exceeds the limit of 20
- The unused amount of the resource, s1 = 20 - 3x - 2y, which must be non-negative
-
How is the leaving variable chosen in the Simplex method?
- Pick the row with the largest Value entry
- Divide each Value entry by the negative entry in the pivot column and pick the largest ratio
- Divide each Value entry by the positive entry in the pivot column and pick the smallest such ratio
- Pick the row containing the most negative objective coefficient
-
A maximisation problem has three ≤ constraints. How many slack variables are introduced to write it in standard form?
- 1
- 3
- 2
- 6
-
Which condition shows that a Simplex tableau for a maximisation problem has reached its optimal solution?
- Every basic variable appears with coefficient 2 in its row
- The Value column contains no zero entries
- All entries in the objective row are zero or positive
- All entries in the objective row are zero or negative
-
Within the specification's limits, how many decision variables and constraints can a basic Simplex problem have at most?
- Two decision variables and six constraints
- Five decision variables and five constraints
- Three decision variables and three constraints
- Four decision variables and four constraints
-
What is the maximum value of P = 3x + 2y subject to x + y ≤ 4, x + 3y ≤ 6 and x, y ≥ 0?
- 12
- 10
- 11
- 14
-
For the problem maximise P = 3x + 2y subject to x + y ≤ 4, x + 3y ≤ 6, at which point is the maximum attained?
- (4, 0)
- (0, 2)
- (3, 1)
- (2, 2)
-
What is the maximum of P = 2x + 5y subject to x + 2y ≤ 10, 3x + y ≤ 15 and x, y ≥ 0?
- 23
- 27
- 20
- 25
-
The initial tableau for maximise P = 3x + 2y with slack variables s1 and s2 has which objective row (columns x, y, s1, s2, Value)?
- -3, -2, 0, 0, 4
- -3, -2, 1, 1, 0
- 3, 2, 0, 0, 0
- -3, -2, 0, 0, 0
-
What is the maximum of P = 4x + 3y subject to 2x + y ≤ 8 and x + 2y ≤ 8 with x, y ≥ 0?
- 56/3
- 16
- 64/3
- 18
-
What is the maximum of P = 5x + 4y subject to x + y ≤ 5, 2x + y ≤ 8 and x, y ≥ 0?
- 21
- 25
- 23
- 20
-
If the constraint x + 3y ≤ 6 in maximise P = 3x + 2y subject to x + y ≤ 4 is relaxed to x + 3y ≤ 9, what is the new maximum of P?
- 9.5
- 13
- 11
- 12
-
What is the maximum of P = 2x + 3y subject to x + y ≤ 4 and y ≤ 2 with x, y ≥ 0?
- 10
- 11
- 8
- 12
-
Why does the basic Simplex method need no artificial variables when all constraints are ≤ with non-negative right-hand sides?
- The objective function is always negative at the origin.
- Slack variables make every constraint an equality, so artificial variables are never needed.
- The origin is feasible, so the slack variables give a starting basic feasible solution.
- Artificial variables are only needed for maximisation problems.
-
A column of the tableau has a negative objective-row entry but no positive entries in the constraint rows. What does this indicate?
- The solution is optimal but degenerate.
- The slack variable in that column must be zero.
- The problem has no feasible solution at all.
- The objective is unbounded in that direction, so there is no finite maximum.
-
Subject to x + 2y ≤ 6 and 2x + y ≤ 6 with x, y ≥ 0, a student says the maximum of P = x + y is 4. Is this correct?
- No, since the maximum is 5 at (1, 4).
- No, since the intersection gives P = 3.5.
- No, since the maximum is 6 at the origin.
- Yes, since the intersection (2, 2) gives P = 4, which is larger than the axis points, each giving 3.
-
A pivot element is 4 and the Value entry in the pivot row is 16. What is the new value of the entering variable after the pivot?
- 12
- 4
- 16
- 1/4
-
In a maximisation problem the final objective row reads P + 2 s1 = 18 with s1 non-basic. What does the coefficient 2 mean?
- Resource 1 is fully used and has no effect on P.
- Each extra unit of the first resource would increase the maximum P by 2.
- P falls by 18 for each unit of s1 used.
- Each unit of unused resource 1 increases P by 2.
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