Lesson 3D.3.1
3D.3.1 The route inspection (Chinese postman) algorithm Quiz: Pearson Edexcel Further Maths, Unit 37
20 questions
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Lesson 3D.3.1, The route inspection (Chinese postman) algorithm: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 37: Algorithms on graphs II, written with Revision Ninja.
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The 20 questions
-
The route inspection problem asks for a route that
- traverses every edge at least once and returns to its start, with minimum total length
- visits every vertex exactly once
- finds the longest possible walk
- uses every edge exactly once
-
In this specification, what is the most odd vertices a route inspection network can contain?
- four
- six
- two
- eight
-
If a network is Eulerian, the minimum length of a route inspection is
- the total weight minus the largest edge
- twice the total weight
- the total weight of all its edges
- the shortest path between two vertices
-
Odd vertices in a route inspection problem are dealt with by
- adding new vertices
- deleting edges between them
- pairing only adjacent odd vertices
- repeating shortest paths that pair them up, so every vertex ends with even degree
-
Repeated edges in a route inspection solution are added so that
- every vertex has even degree
- the route visits each vertex exactly once
- they are removed from the network
- their weights are doubled
-
A route inspection route starts and ends at
- two different odd vertices
- the same vertex
- the vertex with the smallest edge weight
- the vertex with the largest degree
-
How many ways are there to pair up 4 odd vertices?
- 3
- 8
- 4
- 6
-
A network has exactly two odd vertices, and the shortest path between them has length 3. The total weight of all edges is 20. What is the minimum route inspection length?
- 17
- 26
- 20
- 23
-
Four odd vertices A, B, C and D have shortest path lengths AB 2, CD 3, AC 5, BD 4, AD 6 and BC 7. What is the minimum total length of the repeated paths?
- 5
- 13
- 3
- 9
-
A network has total edge weight 30. Its odd vertices can be paired with repeats totalling 5. What is the minimum route length?
- 25
- 40
- 35
- 30
-
A network is Eulerian with total edge weight 18. What is the minimum route inspection length?
- 9
- 18
- 36
- 20
-
A network with four odd vertices has pairing totals 7, 9 and 11, and total edge weight 25. What is the minimum route length?
- 36
- 30
- 34
- 32
-
A network has total edge weight 44, and the shortest repeats needed to pair its odd vertices total 7. What is the minimum route length?
- 56
- 47
- 37
- 51
-
Odd vertices P, Q, R and S have pair distances PQ 4, RS 4, PR 10, QS 10, PS 3 and QR 2. What is the minimum total repeat length?
- 20
- 3
- 8
- 5
-
A route inspection on a network of total weight 42 has length 50. What repeat length was needed?
- 8
- 42
- 92
- 50
-
Four odd vertices P, Q, R and S have pair distances PQ 3, RS 3, PR 6, QS 2, PS 4 and QR 5. What is the minimum total repeat length?
- 5
- 9
- 8
- 6
-
Why can't the postman simply repeat the shortest single edge between two odd vertices?
- all edge weights are equal
- edges cannot be repeated at all
- Repeats must make every vertex have even degree, so they must link all the odd vertices in pairs
- the postman must visit every vertex exactly once
-
Why is the augmented network Eulerian once the odd vertices are paired by repeats?
- it has become a tree
- all edges now have equal weight
- every vertex now has even degree and the network is connected
- it has exactly two odd vertices
-
A network has total weight 60 and a minimum pairing repeat of 12. The route must start and end at A. What is its length?
- 84
- 72
- 48
- 60
-
A postman's route must start and end at the same vertex. The network has total weight 45 and the minimum repeats total 10. What is the route length?
- 50
- 55
- 65
- 45
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