Lesson 3C.4.2
3C.4.2 Successive direct impacts Quiz: Pearson Edexcel Further Maths, Unit 28
20 questions
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Lesson 3C.4.2, Successive direct impacts: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 28: Direct impact, written with Revision Ninja.
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The 20 questions
-
A sphere hits a fixed smooth vertical wall perpendicularly at speed u with coefficient of restitution e. What is its speed after impact?
- e u
- e^2 u
- u / e
- u (1 - e)
-
A ball is dropped from height h onto a fixed horizontal smooth plane with coefficient e. What is the height of its first rebound?
- h / e^2
- e^2 h
- e h
- (1 - e) h
-
What pattern do the speeds after successive impacts with a fixed smooth plane follow?
- A geometric sequence with common ratio e
- An arithmetic sequence with common difference e
- All speeds are equal
- A geometric sequence with common ratio e^2
-
What is the sum to infinity of a geometric series with first term a and common ratio r, |r| < 1?
- a (1 - r)
- a / (1 - r)
- a (1 + r)
- a r / (1 - r)
-
Why do successive impacts of a sphere with a fixed plane eventually stop for e < 1?
- The sphere loses mass at each impact
- Momentum is created at each impact
- Gravity increases with each bounce
- Each impact multiplies the speed by e, which is less than 1, so the speeds tend to zero
-
What happens to successive bounces of a sphere when e = 1 on a smooth fixed plane?
- The sphere stops after the first bounce
- The speed doubles at each bounce
- The bounces continue indefinitely with the same speed
- The speed halves at each bounce
-
A sphere leaves a smooth horizontal plane vertically upwards at speed v, under gravity g. How long does it take to return to the plane?
- v/g
- v^2/(2g)
- 2v/g
- 2g/v
-
A sphere is dropped from a height of 4 m onto a smooth horizontal plane with e = 0.5. How high does it rebound?
- 2 m
- 4 m
- 0.5 m
- 1 m
-
A sphere is dropped from a height of 4 m onto a smooth horizontal plane with e = 0.5 and g = 9.8. What is its speed just after the first impact, to 2 decimal places?
- 2.21 m/s
- 4.43 m/s
- 8.85 m/s
- 4.00 m/s
-
A sphere strikes a fixed smooth plane with speed 10 m/s with e = 0.6. What is its speed after the second impact?
- 2.16 m/s
- 1.2 m/s
- 3.6 m/s
- 6.0 m/s
-
A ball is dropped from a height of 2 m onto a smooth horizontal floor with e = 0.5. What is the total distance it travels before the bounces stop, to 2 decimal places?
- 4.00 m
- 2.67 m
- 6.00 m
- 3.33 m
-
A sphere bounces off a fixed smooth wall with e = 0.75 after successive impacts, having approach speed 8 m/s. What is its speed after the second impact?
- 4.5 m/s
- 3.0 m/s
- 2.25 m/s
- 6 m/s
-
A ball leaves a horizontal floor vertically upwards at 6 m/s, with g = 10 m/s^2. How long until it returns to the floor?
- 3.6 s
- 0.6 s
- 1.2 s
- 6 s
-
A sphere is dropped from a height of 10 m onto a smooth plane with e = 0.8. What is its height after the third rebound, to 2 decimal places?
- 5.12 m
- 2.62 m
- 8.00 m
- 1.60 m
-
A sphere has speed 20 m/s and e = 0.5 on repeated impacts with a smooth fixed plane. What is its speed after four impacts?
- 0.625 m/s
- 1.25 m/s
- 10 m/s
- 2.5 m/s
-
A ball is dropped from rest from a height of 1.8 m with e = 0.6. What is its height after the second bounce, to 3 decimal places?
- 0.389 m
- 0.648 m
- 0.233 m
- 1.080 m
-
A ball is dropped from rest from a height of 1 m onto a smooth horizontal floor with e = 0.5 and g = 10 m/s^2. What is the total time until the bounces stop, to 2 decimal places?
- 2.24 s
- 0.89 s
- 1.34 s
- 0.45 s
-
For successive impacts of a sphere on a smooth fixed plane, what fraction of the kinetic energy is lost at each impact?
- 1 - 2e
- 1 - e^2
- e^2
- 1 - e
-
A sphere has speed 9 m/s before ten successive impacts with a smooth fixed plane with e = 0.9. What is its speed after the tenth impact, to 2 decimal places?
- 0.35 m/s
- 3.49 m/s
- 4.05 m/s
- 3.14 m/s
-
Why does the total time for successive bounces converge when e < 1?
- The flight times form a geometric series with common ratio e, which is less than 1, so the sum is finite
- Because e equals one half in every case
- Each bounce takes exactly the same time
- Gravity is constant, so the sum of the times is always finite
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