Lesson 8.2.1
8.2.1 Enthalpy cycles and Hess's Law Quiz: Pearson Edexcel Chemistry, Unit 8
20 questions
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Lesson 8.2.1, Enthalpy cycles and Hess's Law: 20 multiple choice questions for the Pearson Edexcel Chemistry (9CH0), Unit 8: Energetics I, written with Revision Ninja.
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The 20 questions
-
What does Hess's Law state?
- The enthalpy change is equal to the activation energy of the slowest step in the reaction mechanism
- Enthalpy changes can only be added if they are for gases, so solids must be excluded from the sum
- The total enthalpy change of a reaction is the same, regardless of the route taken
- The enthalpy change depends on the number of steps taken, so each route gives a different overall result
-
Given C(s) + O2(g) -> CO2(g), delta H = -393.5 kJ mol-1, and CO(g) + 1/2 O2(g) -> CO2(g), delta H = -283.0 kJ mol-1, what is delta H for C(s) + 1/2 O2(g) -> CO(g)?
- -110.5 kJ mol-1
- -283.0 kJ mol-1
- +110.5 kJ mol-1
- -676.5 kJ mol-1
-
What is the correct way to construct an enthalpy cycle for a reaction whose enthalpy change cannot be measured directly?
- Use only combustion data, since these are always measurable
- Add the activation energies of each step
- Use a route through known enthalpy changes that goes from the same reactants to the same products
- Draw the cycle with the reactants at the top and the products at the bottom and ignore the signs
-
When an equation is reversed in a Hess cycle calculation, what happens to the sign of its enthalpy change?
- The value is doubled
- The value becomes zero
- The sign changes
- The sign stays the same
-
When an equation is multiplied by 2 in a Hess calculation, what happens to its enthalpy change?
- It becomes negative
- It is halved
- It is doubled
- It stays the same
-
Using enthalpy of formation data, delta Hf of CO2 = -393.5, H2O(l) = -285.8, and C2H5OH(l) = -277.7 kJ mol-1, what is delta Hc of ethanol? C2H5OH + 3O2 -> 2CO2 + 3H2O
- -1366.7 kJ mol-1
- +1366.7 kJ mol-1
- -956.9 kJ mol-1
- -1088.0 kJ mol-1
-
What is the standard enthalpy change of formation of an element in a Hess cycle calculation?
- The same as its bond enthalpy
- Equal to the combustion enthalpy
- Equal to the enthalpy of neutralisation
- Zero
-
In an enthalpy cycle, what is the relationship between the direct route and the indirect routes?
- They have the same overall enthalpy change
- The direct route is always more exothermic
- The direct route has a zero enthalpy change
- The indirect routes have no enthalpy change
-
Given delta H1 = -285.8 kJ mol-1 for H2 + 1/2 O2 -> H2O(l) and delta H2 = -241.8 kJ mol-1 for H2 + 1/2 O2 -> H2O(g), what is delta H for H2O(l) -> H2O(g)?
- +241.8 kJ mol-1
- -527.6 kJ mol-1
- +44.0 kJ mol-1
- -44.0 kJ mol-1
-
What is the enthalpy change for the reaction C(s) + 2H2(g) -> CH4(g), given C(s) + O2 -> CO2 = -393.5, H2 + 1/2 O2 -> H2O(l) = -285.8 and CH4 + 2O2 -> CO2 + 2H2O(l) = -890.3 kJ mol-1? Use Hess's Law.
- -74.8 kJ mol-1
- -1569.6 kJ mol-1
- -890.3 kJ mol-1
- +74.8 kJ mol-1
-
Why are indirect enthalpy calculations useful?
- They give the rate of a reaction at any temperature by using the enthalpy values as a rate constant
- They prove that the reaction is reversible by showing the enthalpy change changes sign on the reverse
- They show the activation energy of the reaction from the difference between the reactant and product levels
- They allow enthalpy changes that cannot be measured directly to be found from other measurable changes
-
What must be true of the enthalpy cycle diagram before the sum is written?
- All enthalpy changes must be positive so that the sum of the cycle can be taken without any sign errors
- Only one route is needed, because a single route gives the full answer without any checks
- The reactants and products must be placed at the same two states for each route
- All reactants must be in the gas state so that the enthalpy changes can be combined in a single cycle
-
Which enthalpy change is used in a Hess cycle calculation of a reaction's enthalpy of formation from combustion data?
- Activation energies of each step in the mechanism, which are added to give the overall value
- Bond enthalpies only, with no data for the compounds needed, so that the cycle can be closed
- pH values of the reactants, which are converted into enthalpy changes using a standard formula
- Enthalpies of combustion of reactants and products, with the sum determined by Hess's Law
-
Given that the enthalpy of combustion of hydrogen is -285.8 kJ mol-1, how much heat is released when 4.00 g of hydrogen (Mr = 2.0) burns to form liquid water?
- 285.8 kJ
- 571.6 kJ
- 142.9 kJ
- 1143.2 kJ
-
In a Hess cycle, a student gets +120 kJ mol-1 for a reaction that is known to release heat. What is the most likely cause?
- The activation energy was included in the sum
- The reaction is catalysed
- A sign error when reversing one or more equations
- The mass of water was measured too precisely
-
Which statement about the enthalpy of formation of an element in its standard state is correct?
- Its enthalpy of formation is zero, so it is excluded from the sum
- It must be measured in each experiment
- Its enthalpy of formation is equal to its ionisation energy
- It is always positive
-
What is the enthalpy change for C(s) + 1/2 O2(g) -> CO(g), given C(s) + O2 -> CO2 = -393.5 and CO + 1/2 O2 -> CO2 = -283.0 kJ mol-1, if the second equation is multiplied by -1?
- -283.0 kJ mol-1
- -110.5 kJ mol-1
- -676.5 kJ mol-1
- +110.5 kJ mol-1
-
What is the sign convention used for a standard enthalpy change?
- Negative for exothermic reactions and positive for endothermic reactions
- Always negative regardless of the process
- Positive for exothermic reactions and negative for endothermic reactions
- Always positive for combustion
-
A Hess cycle is set up with two routes. Route A gives -200 kJ mol-1 and route B has one step of -50 and one step of -160 kJ mol-1. Which statement is correct?
- Route B is always more exothermic than route A
- The routes do not agree, so one of the measured values is wrong
- Route A is a catalysed route with lower enthalpy
- Both routes are correct because they have different intermediates
-
The standard enthalpy of combustion of carbon is -393.5 kJ mol-1. How much heat is released when 6.00 g of carbon (Ar = 12.0) burns completely?
- 393.5 kJ
- 196.8 kJ
- 98.4 kJ
- 787.0 kJ
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