Lesson 4C.1
4C.1 Tests for identifying inorganic ions Quiz: Pearson Edexcel Chemistry, Unit 4
20 questions
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Lesson 4C.1, Tests for identifying inorganic ions: 20 multiple choice questions for the Pearson Edexcel Chemistry (9CH0), Unit 4: Inorganic Chemistry and the Periodic Table, written with Revision Ninja.
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The 20 questions
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Which reagent identifies carbonate ions, CO3 2-?
- Barium chloride, which gives a cream precipitate with carbonate ions in the solution being tested
- Silver nitrate, which gives a yellow precipitate with carbonate ions in the solution being tested
- Sodium hydroxide, which gives a gas that turns litmus blue with carbonate ions in the solution being tested
- Dilute acid, which gives carbon dioxide that turns limewater milky
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What is the ionic equation for the reaction of carbonate ions with acid?
- CO3 2- + 2H+ -> CO2 + 2H2
- CO3 2- + H+ -> HCO3-
- CO3 2- + 2H+ -> CO2 + H2O
- CO3 2- + H+ -> CO2 + OH-
-
Which reagent confirms the presence of sulfate ions, SO4 2-?
- Sodium hydroxide, which gives off ammonia gas from the solution containing the sulfate ions being tested
- Acidified barium chloride solution, giving a white precipitate
- Acidified silver nitrate, which gives a white precipitate with sulfate ions in the solution being tested
- Dilute acid, which gives off carbon dioxide gas from the solution containing the sulfate ions being tested
-
What is the ionic equation for the test for sulfate ions?
- BaCl2 + SO4 2- -> BaSO4 + 2Cl-
- Ba + SO4 -> BaSO4
- Ba2+ + SO4 2- -> BaSO4
- Ba2+ + 2SO4 2- -> Ba(SO4)2
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Which test identifies ammonium ions, NH4+?
- Add dilute acid, and a gas is released that turns limewater milky in the test tube of the sample
- Add acidified barium chloride, and a white precipitate forms in the test tube containing the sample
- Add silver nitrate, and a cream precipitate forms in the test tube containing the sample solution
- Warm with sodium hydroxide, and ammonia gas turns damp red litmus paper blue
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What is the ionic equation for the test for ammonium ions?
- NH4+ + Cl- -> NH3 + HCl
- NH4+ + H+ -> NH3 + H2
- NH4+ + OH- -> NH3 + H2O
- NH4+ + OH- -> NH4OH2
-
Which reagent is used to test for halide ions, and what does it show?
- Barium chloride, which forms a yellow precipitate with the halide ions and so identifies the halide in the sample
- Acidified silver nitrate, which forms a precipitate that identifies the halide
- Sodium hydroxide, which forms a cream gas with the halide ions and so identifies the halide in the sample
- Dilute acid, which forms a precipitate with the halide ions and so identifies the halide in the sample
-
Which silver halide precipitate is yellow?
- Silver fluoride
- Silver iodide
- Silver bromide
- Silver chloride
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Why is dilute nitric acid added before silver nitrate in a halide test?
- To release ammonia from the sample, which then identifies the halide by its distinctive smell and colour
- To make the solution basic so that the silver halides form more readily and settle out of the solution
- To dissolve the silver halide precipitate once it forms, so that the halide can be identified by its colour
- To remove carbonate or other ions that would form a precipitate and confuse the result
-
Which reagent distinguishes carbonate from sulfate?
- Dilute acid, which gives a gas with carbonate but no reaction with sulfate
- Water, which dissolves only the carbonate and leaves the sulfate as an insoluble solid in the sample
- Sodium hydroxide, which gives ammonia gas with both carbonate and sulfate ions in the solution being tested
- Silver nitrate, which gives a white precipitate with both carbonate and sulfate ions in the solution being tested
-
What is the observation when limewater is used to test carbon dioxide?
- The limewater turns green
- The limewater turns yellow
- The limewater turns milky
- The limewater turns blue
-
What is observed in the test for sulfate with acidified barium chloride?
- A cream precipitate forms
- A gas with a pungent smell is released
- A white precipitate forms
- A yellow solution forms
-
What is the ionic equation for the formation of the yellow precipitate in the iodide test?
- Ag + I -> AgI
- Ag+ + 2I- -> AgI2
- Ag+ + I- -> AgI2
- Ag+ + I- -> AgI
-
Why are flame tests not suitable for identifying transition metal ions?
- Many transition metal ions do not give distinctive flame colours, so the test is not reliable for them
- Transition metals react with the flame to form water, which hides any colour that the metal ions might show
- Transition metals burn in the flame with an invisible colour, which is why no colour can be observed in the test
- Transition metal ions are always colourless in solution, so there is no colour to see in a flame test
-
Which compound gives a positive test for carbonate ions when dilute acid is added?
- Sodium sulfate, which reacts with dilute acid to give a gas that turns limewater milky in the test
- Sodium chloride, which reacts with dilute acid to give a gas that turns limewater milky in the test
- Sodium carbonate
- Sodium nitrate, which reacts with dilute acid to give a gas that turns limewater milky in the test
-
Which ionic equation represents the test for hydrogencarbonate ions?
- HCO3- + H+ -> CO2 + H2O
- HCO3- + Ba2+ -> BaCO3 + H+
- HCO3- + Cl- -> HCl + CO2
- HCO3- + OH- -> CO2 + H2O
-
A solid gives a white precipitate with acidified barium chloride. Which conclusion is best supported?
- The solid contains carbonate ions, since BaCO3 is soluble
- The solid contains chloride ions, since BaCl2 is white
- The solid contains nitrate ions, since barium nitrate is insoluble
- The solid contains sulfate ions, since BaSO4 is insoluble
-
Which test would identify a sample containing both carbonate and sulfate ions?
- Add dilute acid to detect carbonate, then add acidified barium chloride to detect sulfate
- Add water and filter to remove both ions, then test the solid that remains on the filter paper for identity
- Add sodium hydroxide only and test for ammonia, which identifies both ions in the same single test
- Add silver nitrate, which gives a yellow precipitate for both ions, so the sample can be identified in one step
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Explain why acidified barium chloride is used rather than barium chloride alone for the sulfate test.
- Acid is needed to make barium chloride ionic, so that the barium ions can then react with the sulfate ions
- Acid removes carbonate and other ions that would also form precipitates with barium, so the result is specific to sulfate
- Acid releases sulfur dioxide gas that identifies the sulfate ion in the sample being tested by the method
- Acid makes sulfate ions volatile so that they can be driven off and detected by the smell of the gas
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Explain why warming is needed in the test for ammonium ions.
- Warming converts ammonium ions into nitrate ions, which are then detected by the silver nitrate test instead
- Warming dissolves the solid sample completely so that the ammonium ions can be seen in the clear solution
- Warming forms a precipitate of ammonium hydroxide, which is then filtered off and tested for identity
- Warming drives off ammonia gas from the solution so that it can be detected
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