Lesson 17C.3
17C.3 Polyesters Quiz: Pearson Edexcel Chemistry, Unit 17
20 questions
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Lesson 17C.3, Polyesters: 20 multiple choice questions for the Pearson Edexcel Chemistry (9CH0), Unit 17: Organic Chemistry II, written with Revision Ninja.
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The 20 questions
-
What type of polymerisation forms polyesters?
- Free-radical polymerisation of alkenes only, which needs a peroxide initiator to start the chain reaction
- Ionic polymerisation with no by-products, carried out at low temperature in a dry, inert solvent
- Addition polymerisation, with no molecules lost as each monomer unit joins the growing polymer chain
- Condensation polymerisation, with a small molecule such as water eliminated at each link
-
Which two monomers are used to make a polyester?
- Two alkenes with a catalyst
- Two monoalcohols and an alkene
- A dicarboxylic acid and a diol
- A diamine and a dicarboxylic acid
-
What small molecule is eliminated when a polyester forms from a dicarboxylic acid and a diol?
- Ammonia
- Carbon dioxide
- Hydrogen chloride
- Water
-
Which link is present in the backbone of a polyester?
- The ether link, -O-, between two carbon atoms
- The amide link, -CONH-
- The ester link, -COO-
- The peptide link, -CONH- joining amino acids
-
Which pair of monomers makes poly(ethylene terephthalate)?
- Ethanoic acid and ethane-1,2-diol, joined as a simple ester
- Benzene-1,4-dicarboxylic acid and ethane-1,2-diol
- Ethene and benzene-1,4-diol, joined across the double bond of ethene
- Ethane-1,2-diamine and hexanedioic acid, joined as an amide link
-
What is the repeat unit of a polyester made from hexanedioic acid and butane-1,4-diol?
- -[CO(CH2)4CO-O(CH2)4O]-, containing two ester links per unit
- -[C6H4-COO]- with one acid link per unit, formed from a benzene ring and a single carboxyl group
- -[CO(CH2)4CO]- with a diamine link per unit, formed by losing ammonia from each joining step
- -[CH2CH2O]- with one ester link per unit, formed from a single monomer with an acid group
-
Why are polyesters susceptible to hydrolysis?
- They contain amide links that are easily cleaved by water
- They contain ionic bonds that dissolve in water
- The polymer chains contain double bonds that react with water
- The ester links can be broken by water, especially in acid or alkali
-
A polyester is made from 1.0 mol of a dicarboxylic acid and 1.0 mol of a diol, with complete reaction. How many moles of water are eliminated per mole of repeat unit?
- 4
- 0
- 2
- 1
-
Why is a polyester described as a condensation polymer?
- It forms by adding monomers across double bonds without losing any atoms
- It forms only from monomers that contain a benzene ring
- It forms by cross-linking existing polymer chains with heat
- It forms by joining monomers while releasing a small molecule
-
What is the functional group that links the monomer units of nylon?
- A nitrile group, -CN
- An amide link, -CONH-
- An ether link, -O-
- An ester link, -COO-
-
Which monomers form a polyester whose repeat unit contains a benzene ring?
- Propan-1-ol and propanoic acid, which give a simple ester with no repeating unit at all
- Benzene-1,4-dicarboxylic acid and a diol
- Ethanoic acid and a diol, which gives a polyester with a single methyl group in each unit
- Hexane-1,6-diamine and a diacid, which gives a polyamide with no ester links in the chain
-
Which property of polyesters is affected by the length of the diol chain?
- The number of carbon atoms in the benzene ring
- Flexibility and melting temperature of the polymer
- Density of the monomers before polymerisation
- Colour, since the diol is responsible for the colour of the polymer
-
A polyester has a relative repeat unit mass of 192. How many repeat units make up a molecule with a relative molecular mass of 19 200?
- 100
- 200
- 10
- 1000
-
Which statement describes the condensation polymerisation step in polyester formation?
- A nitrogen atom attacks a carbonyl group, releasing ammonia as the amide link forms in the chain
- A hydroxyl group from the alcohol reacts with a carboxyl group from the acid, releasing water
- Two alkene groups add together across the double bond and form a single bond, with no atoms lost
- A chlorine atom replaces a hydrogen atom on the aromatic ring, releasing hydrogen chloride as a gas
-
Why does a polyester have a lower melting temperature than a polymer with stronger intermolecular forces?
- Its ester groups give dipole-dipole forces, which are weaker than hydrogen bonding between amide groups
- Its ester groups form strong ionic bonds between chains, which hold the polymer together more tightly
- It has no intermolecular forces at all between its chains, so the chains slide apart when heated
- It has more covalent cross-links per chain than polyamides, which makes the polymer easier to melt
-
What is a consequence of the repeat unit containing two ester links from a diacid and a diol?
- The polymer is formed only at very high pressure in the absence of water
- The polymer contains an amine group at each end of the chain
- The polymer has no regular structure and cannot crystallise
- The polymer chain has a regular, repeating pattern of ester groups along its length
-
Which molecule is a monomer used to make a polyester in industry?
- Ethane-1,2-diol
- Ethanamide
- Ethanenitrile
- Ethene
-
Which compound is the diacid monomer used to make poly(ethylene terephthalate)?
- Butanedioic acid, a dicarboxylic acid with four carbons in its chain
- Benzene-1,4-dicarboxylic acid
- Ethanedioic acid, a dicarboxylic acid with two carbons in its chain
- Benzene-1,2-diol, a diol with the two hydroxyl groups on adjacent carbons
-
A polyester has a repeat unit molar mass of 192 g mol-1. What is the molar mass of a chain with 50 repeat units?
- 960 g mol-1
- 9600 g mol-1
- 19 200 g mol-1
- 3840 g mol-1
-
What mass of water is eliminated for each mole of ester link formed in a polycondensation?
- 36 g, the molar mass of two moles of water
- 18 g, the molar mass of one mole of water
- 44 g, the molar mass of one mole of carbon dioxide
- 2 g, the molar mass of one mole of hydrogen
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