Lesson 12.3.1
12.3.1 Titration curves and indicators Quiz: Pearson Edexcel Chemistry, Unit 12
20 questions
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Lesson 12.3.1, Titration curves and indicators: 20 multiple choice questions for the Pearson Edexcel Chemistry (9CH0), Unit 12: Acid-base Equilibria, written with Revision Ninja.
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The 20 questions
-
What is the pH at the equivalence point of a strong acid titrated with a strong base at 298 K?
- 7.00, because the salt formed is neutral
- Above 10, because the base remains in excess
- Below 4, because the acid remains in excess
- About 5, because water is partly dissociated
-
Why is the equivalence point of a weak acid titrated with a strong base above pH 7?
- The solution is buffered at exactly pH 7 because both species are present
- Strong bases always give a solution with pH above 10 at equivalence
- The conjugate base of the weak acid is hydrolysed, producing excess OH- ions
- The weak acid is stronger than the base at equivalence, leaving excess H+ ions
-
Why is the equivalence point of a strong acid titrated with a weak base below pH 7?
- The weak base remains in excess, making the solution basic
- Strong acids and weak bases always neutralise to exactly pH 7
- The salt formed is hydrolysed, producing H+ ions
- The indicator is protonated, so the solution is strongly basic
-
What property must an indicator have to be suitable for a titration?
- Its colour change must be at exactly pH 7 for every titration
- It must be colourless in both acid and base so that no change is seen
- It must be used at a pH far below the equivalence point to act quickly
- Its colour change must occur within the steep vertical section of the titration curve
-
At the half-equivalence point of a weak acid titrated with a strong base, which statement is true?
- pH equals 7, because the solution is neutral
- pH equals 14 minus pKa
- pH equals pKa, because [HA] equals [A-]
- pH equals the concentration of the base in mol dm-3
-
What does the steep vertical section of a titration curve show?
- A constant pH throughout, because the buffer resists every addition of titrant made before the equivalence point
- The total moles of acid present in the flask
- A large change in pH for a very small volume of titrant added near the equivalence point
- A gradual, steady change in pH over the whole titration, with no sharp change at any single volume of titrant
-
Why is it important for an indicator's colour change to fall within the steep section of a curve?
- It means the indicator must change colour exactly at pH 7 in every titration
- It means the end point is sharp, so the volume read at the colour change is close to the equivalence volume
- It means the indicator avoids the buffer region, so the titration is always quicker
- It means the indicator is strongly coloured only in the acid and colourless in the base
-
A 25.0 cm3 sample of 0.100 mol dm-3 hydrochloric acid is titrated, and no sodium hydroxide has been added. What is its pH?
- 2.00
- 13.00
- 0.10
- 1.00
-
What is the pH after 10.0 cm3 of 0.100 mol dm-3 NaOH is added to 25.0 cm3 of 0.100 mol dm-3 HCl?
- 7.00
- 4.30
- 1.37
- 1.00
-
What is the approximate pH at the equivalence point when 0.100 mol dm-3 ethanoic acid (Ka = 1.7 x 10^-5 mol dm-3) is titrated with 0.100 mol dm-3 NaOH?
- About 8.7
- About 3.0
- Exactly 7.00
- About 5.3
-
What volume of 0.100 mol dm-3 NaOH is needed to reach the equivalence point with 25.0 cm3 of 0.200 mol dm-3 HCl?
- 12.5 cm3
- 25.0 cm3
- 50.0 cm3
- 100 cm3
-
A weak acid is titrated with NaOH. At the half-equivalence point the pH is 4.76. What is the pKa of the acid?
- 4.76
- 2.38
- 7.00
- 9.52
-
Which indicator is most suitable for titrating 0.100 mol dm-3 ethanoic acid with NaOH, where the equivalence pH is about 8.7?
- Methyl red, which changes colour over about pH 4.4 to 6.2
- Methyl orange, which changes colour over about pH 3.1 to 4.4
- Phenolphthalein, which changes colour over about pH 8.2 to 10
- Bromothymol blue, which changes colour over about pH 6.0 to 7.6
-
A student titrates a weak acid with NaOH using methyl orange, which changes colour between pH 3.1 and 4.4. What is the likely effect on the result?
- The indicator does not change colour, so the titre cannot be measured
- The colour change occurs after the equivalence point, so the titre is too large
- The titre is accurate because methyl orange changes at the equivalence point of all acids
- The colour change occurs well before the equivalence point, so the titre is too small
-
What is the pH of 25.0 cm3 of 0.100 mol dm-3 ethanoic acid (Ka = 1.7 x 10^-5 mol dm-3) before any NaOH is added?
- 2.88
- 4.76
- 1.00
- 7.00
-
Why does a weak acid-strong base titration curve rise more slowly at the start than a strong acid-strong base curve of the same concentrations?
- The weak acid and its conjugate base together resist pH change, so the curve is flatter at the start
- The weak acid releases more hydrogen ions than a strong acid, so the pH rises more slowly
- The weak acid is fully dissociated, so the pH changes only at the equivalence point
- The strong base reacts with water first, so no pH change occurs until the end
-
A 0.100 mol dm-3 weak acid HA with Ka = 2.0 x 10^-5 mol dm-3 is titrated with 0.100 mol dm-3 NaOH; 25.0 cm3 of acid is used. What volume of NaOH gives the half-equivalence point?
- 6.25 cm3
- 12.5 cm3
- 25.0 cm3
- 50.0 cm3
-
Two 0.100 mol dm-3 titrations are done with 25.0 cm3 of acid: one strong (HCl) and one weak monobasic (HA), both against 0.100 mol dm-3 NaOH. Which statement is correct?
- Neither can be titrated accurately, because the equivalence point of a weak acid cannot be detected by any indicator
- The weak acid needs twice as much NaOH because weak acids release two protons
- The strong acid needs more NaOH because its ionisation releases fewer hydrogen ions than the weak acid does
- Both need the same volume of NaOH to reach equivalence, but their equivalence point pH values differ
-
What is the pH after 30.0 cm3 of 0.100 mol dm-3 NaOH is added to 25.0 cm3 of 0.100 mol dm-3 HCl?
- 7.00
- 11.96
- 12.50
- 2.04
-
A teacher claims that any indicator changing colour near pH 7 will work for every titration. Which response is best?
- Correct, because the equivalence point of every acid-base titration is pH 7, so any indicator changing near 7 will do
- Incorrect, because the indicator must change colour within the steep section at the equivalence point, which is above pH 7 here
- Incorrect, because indicators cannot be used reliably for any titration involving a weak acid or a weak base
- Correct, because an indicator only needs a colour change somewhere in the broad range between pH 4 and pH 10 to work
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