Lesson 5.06a
5.06a Chi-squared tests on contingency tables Quiz: OCR Further Maths, Unit 2
20 questions
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Lesson 5.06a, Chi-squared tests on contingency tables: 20 multiple choice questions for the OCR Further Maths (H245), Unit 2: Statistics (Y542), written with Revision Ninja.
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The 20 questions
-
In a chi-squared test for independence on a contingency table, what is the null hypothesis?
- Variables are independent
- Variables are dependent
- Data is normal
- Means are equal
-
What is the formula for degrees of freedom in an r by c contingency table?
- (r + 1)(c + 1)
- rc - 1
- r + c - 2
- (r - 1)(c - 1)
-
What is the minimum expected frequency required for each cell in a chi-squared test?
- 1
- 5
- 30
- 10
-
When must Yates' continuity correction be applied in a contingency table test?
- In 2x2 tables
- In 3x3 tables
- When E is under 5
- In all tables
-
How is the expected frequency of a cell in a contingency table calculated?
- (Row x Col) / Total
- (Row + Col) / Total
- (Row - Col) / Total
- Row x Col x Total
-
What is the standard formula for a cell's contribution to the chi-squared statistic?
- (O - E) / E
- (O - E)^2 / E
- (O + E)^2 / E
- (O - E)^2 / O
-
When comparing the calculated chi-squared statistic to the critical value, when is H0 rejected?
- Calculated > critical
- Calculated < critical
- Calculated = critical
- Calculated = 0
-
What action should be taken if an expected frequency in a table is less than 5?
- Multiply frequencies
- Discard cell
- Ignore constraint
- Combine categories
-
How many degrees of freedom does a 3 by 4 contingency table have?
- 7
- 5
- 12
- 6
-
In a contingency table, row total is 20, column total 25, grand total 50. What is E?
- 10
- 5
- 12.5
- 15
-
If an observed frequency is 15 and the expected frequency is 10, what is its chi-squared contribution?
- 0.5
- 2.5
- 5
- 1.25
-
What are the degrees of freedom for a standard 2 by 2 contingency table?
- 4
- 0
- 1
- 2
-
A row total is 40, column total is 30, and grand total is 120. Calculate expected frequency.
- 20
- 12
- 10
- 15
-
A contingency table cell has an expected frequency of 3.2. What step must be completed next?
- Proceed with calculation
- Divide by two
- Combine adjacent categories
- Apply Yates' correction
-
In a 2 by 2 table with O=12 and E=8, calculate the numerator before squaring in Yates' correction.
- 3
- 4
- 4.5
- 3.5
-
The calculated chi-squared is 7.82 and critical value is 5.991. What is the test outcome?
- Accept H0
- Increase sample size
- Inconclusive
- Reject H0
-
A 4 by 3 table has two rows combined due to small expected frequencies. What is the new v?
- 3
- 6
- 2
- 4
-
Using Yates' correction with O = 10 and E = 6, calculate the squared numerator value.
- 12.5
- 9.5
- 12.25
- 16
-
A 3 by 3 table has two rows merged to satisfy expected frequency requirements. What are the new dimensions?
- 1 x 3
- 2 x 2
- 3 x 2
- 2 x 3
-
How do degrees of freedom change when two columns in a 3 by 4 contingency table are combined?
- Decreases by 3
- Decreases by 1
- Remains unchanged
- Decreases by 2
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