Lesson 3.02f
3.02f Differentiation and integration with respect to time Quiz: OCR Maths, Unit 17
20 questions
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Lesson 3.02f, Differentiation and integration with respect to time: 20 multiple choice questions for the OCR Maths (H240), Unit 17: Kinematics, written with Revision Ninja.
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The 20 questions
-
What mathematical operation converts a displacement-time function into a velocity-time function?
- Substitution
- Differentiation
- Integration
- Factorisation
-
How is acceleration expressed in terms of velocity v and time t?
- d^2v/dt^2
- integral of v dt
- v/t
- dv/dt
-
Which process is used to determine displacement from a given velocity-time function?
- Differentiation
- Integration
- Extrapolation
- Rationalisation
-
What kinematic quantity is represented by the second derivative of displacement with respect to time?
- Velocity
- Acceleration
- Speed
- Jerk
-
A particle has displacement x = 3t^2 + 2t. What is its velocity at t = 2?
- 12
- 8
- 14
- 16
-
A particle has velocity v = 6t - 4. What is its acceleration at t = 3?
- 6
- 2
- 18
- 14
-
Velocity is given by v = 3t^2. What is displacement s from t = 0 to t = 2?
- 8
- 24
- 12
- 6
-
A particle has velocity v = 4t^3 - 2t. What is its acceleration function a(t)?
- 4t^2 - 2
- t^4 - t^2
- 12t^2
- 12t^2 - 2
-
Position is given by r = (t^2)i + (3t)j. What is the velocity vector v?
- 6ti + 3j
- 2ti + 3j
- 2ti + 3tj
- ti + 3j
-
Velocity is v = 3i + 4tj. What is the acceleration vector a?
- 4i
- 4j
- 3j
- 3i + 4j
-
Position is r = (4t^3)i + (2t)j. What is the acceleration vector at t = 1?
- 12i
- 24i + 2j
- 12i + 2j
- 24i
-
What constant must always be added when finding velocity by integrating non-uniform acceleration?
- Unit vector
- Initial time
- Gravity constant
- Constant of integration
-
Velocity is v = 6t - 3t^2. At what non-zero time t is acceleration equal to zero?
- t = 1
- t = 2
- t = 3
- t = 0.5
-
Position is r = (2t^3 - 6t)i. At what positive time t is the particle instantaneously at rest?
- t = 3
- t = 2
- t = 1
- t = 6
-
Acceleration is a = 6t. If velocity v = 4 when t = 0, find v when t = 2.
- 12
- 28
- 8
- 16
-
Velocity vector is v = 2i + 3j. What is the magnitude of the velocity vector?
- sqrt(5)
- sqrt(13)
- 13
- 5
-
In 2D kinematics, how is the velocity vector v derived from position vector r?
- r/t
- dr/dt
- integral of r dt
- d^2r/dt^2
-
Particle displacement is s = t^3 - 6t^2. At what time t > 0 is acceleration zero?
- t = 4
- t = 2
- t = 6
- t = 3
-
Under vertical gravity, what is the vertical component of the constant acceleration vector?
- 0
- -g/2
- -g
- g
-
Acceleration is a = 12t^2. If particle velocity is 0 at t = 0, find velocity at t = 1.
- 24
- 12
- 3
- 4
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