Lesson 3.02f
3.02f Non-uniform acceleration Quiz: OCR Maths, Unit 17
20 questions
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Lesson 3.02f, Non-uniform acceleration: 20 multiple choice questions for the OCR Maths (H240), Unit 17: Kinematics, written with Revision Ninja.
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The 20 questions
-
For a particle moving in a straight line with displacement s at time t, which expression gives the velocity v?
- v = ds/dt
- v = s/t
- v = integral of s dt
- v = d^2s/dt^2
-
Which expression gives the acceleration a in terms of displacement s?
- a = ds/dt
- a = d^2s/dt^2
- a = s/t^2
- a = integral of s dt
-
If the velocity v is known, which integral gives the displacement s?
- s = integral of v^2 dt
- s = integral of v dt
- s = v/t
- s = integral of a dt
-
How is velocity obtained from a function for non-uniform acceleration a(t)?
- Multiply by displacement
- Differentiate acceleration
- Integrate acceleration
- Divide by time
-
What is evaluated using an initial condition when integrating acceleration to find velocity?
- Constant of integration
- Total displacement
- Gradient
- Maximum velocity
-
If a particle has zero velocity at an instant, what is true about its acceleration?
- Can be non-zero
- Is always infinite
- Is always negative
- Must be zero
-
In two dimensions the position vector is r = x i + y j. Which expression gives the velocity vector?
- v = dr/dt = (dx/dt) i + (dy/dt) j
- v = integral of r dt
- v = (x + y) i + (x - y) j
- v = r/t
-
A particle has displacement s = t^3 - 6t^2 + 9t metres at time t seconds. What is its velocity at t = 2 s?
- 3 m s^-1
- -9 m s^-1
- 9 m s^-1
- -3 m s^-1
-
A particle has displacement s = t^3 - 6t^2 + 9t metres at time t seconds. What is its acceleration at t = 2 s?
- 0 m s^-2
- -6 m s^-2
- 6 m s^-2
- 12 m s^-2
-
A particle starts from rest at the origin with acceleration a = 4t m s^-2. What is its displacement at t = 3 s?
- 18 m
- 12 m
- 24 m
- 36 m
-
A particle has velocity v = 3t^2 m s^-1 and displacement s = 2 m when t = 0. What is its displacement at t = 2 s?
- 14 m
- 6 m
- 10 m
- 8 m
-
A particle has velocity v = t^2 - 5t + 4 m s^-1 for t >= 0. At which times is the particle momentarily at rest?
- t = 2 s and t = 3 s
- t = 0 s only
- t = 1 s and t = 4 s
- t = 4 s and t = 5 s
-
A particle has velocity v = 4t - t^2 m s^-1. At what time is its acceleration zero?
- t = 0 s
- t = 2 s
- t = 1 s
- t = 4 s
-
A particle has position vector r = (t^2 i + 3t j) m. What is its velocity at t = 2 s?
- 4i + 3j m s^-1
- 2i + 6j m s^-1
- 4i + 6j m s^-1
- 2i + 3j m s^-1
-
A particle has acceleration a = (6t i - 2j) m s^-2 and starts from rest. What is its velocity at t = 1 s?
- (3i - 4j) m s^-1
- (6i - 2j) m s^-1
- (6i - 4j) m s^-1
- (3i - 2j) m s^-1
-
A particle has velocity 3i - 2j m s^-1 at t = 1 s. What is its speed at this instant, to 2 decimal places?
- 1 m s^-1
- 3.61 m s^-1
- 13 m s^-1
- 5 m s^-1
-
A particle has displacement s = t^3 - 3t^2 metres for t >= 0. What is the total distance travelled from t = 0 to t = 3 s?
- 8 m
- 0 m
- 4 m
- 12 m
-
A particle has acceleration a = 6t - 4 m s^-2 and velocity v = 2 m s^-1 at t = 0. What is its velocity at t = 2 s?
- 2 m s^-1
- 6 m s^-1
- 10 m s^-1
- 14 m s^-1
-
A particle has velocity v = 4t - t^2 m s^-1 for 0 <= t <= 5 with s = 0 at t = 0. What is the total distance travelled from t = 0 to t = 5 s?
- 13 m
- 10 m
- 8.33 m
- 8 m
-
At a particle's turning point, what is its instantaneous velocity?
- Zero
- Equal to acceleration
- Maximum
- Negative constant
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