Lesson 3.02b
3.02b Graphical kinematics Quiz: OCR Maths, Unit 17
20 questions
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Lesson 3.02b, Graphical kinematics: 20 multiple choice questions for the OCR Maths (H240), Unit 17: Kinematics, written with Revision Ninja.
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The 20 questions
-
What physical quantity is represented by the gradient of a displacement-time graph?
- Speed
- Acceleration
- Displacement
- Velocity
-
What physical quantity is represented by the gradient of a velocity-time graph?
- Jerk
- Velocity
- Displacement
- Acceleration
-
What physical quantity is given by the area under a velocity-time graph?
- Displacement
- Velocity
- Acceleration
- Speed
-
What motion is represented by a horizontal line on a velocity-time graph?
- Increasing velocity
- Constant velocity
- Deceleration
- Constant displacement
-
What does a horizontal line on a displacement-time graph indicate about an object?
- It is stationary
- It moves uniformly
- It is accelerating
- It moves backwards
-
What motion is shown by a straight sloping line on a displacement-time graph?
- Constant acceleration
- Zero velocity
- Increasing speed
- Constant velocity
-
What motion is described by a straight sloping line on a velocity-time graph?
- Increasing acceleration
- Constant velocity
- Constant acceleration
- Variable velocity
-
What does area below the time axis on a velocity-time graph represent?
- Negative displacement
- Negative acceleration
- Total distance
- Positive displacement
-
A displacement-time graph goes from (0, 0) to (4 s, 20 m). What is the velocity?
- 24 m/s
- 5 m/s
- 0.2 m/s
- 80 m/s
-
A velocity-time graph forms a triangle from t=0 to t=6 s with peak velocity 10 m/s. Find displacement.
- 1.67 m
- 16 m
- 30 m
- 60 m
-
Velocity changes linearly from 2 m/s to 14 m/s in 3 seconds. What is the acceleration?
- 4 m/s²
- 4.67 m/s²
- 36 m/s²
- 12 m/s²
-
A velocity-time graph has areas +15 m above and -5 m below the time axis. Find total distance.
- -10 m
- 10 m
- 20 m
- 75 m
-
A velocity-time graph has areas +15 m above and -5 m below the time axis. Find net displacement.
- -20 m
- 10 m
- -10 m
- 20 m
-
How do you find instantaneous velocity at a point on a curved displacement-time graph?
- Gradient of secant
- Area under curve
- Gradient of chord
- Gradient of tangent
-
How do you find the displacement from a non-linear velocity-time graph?
- Gradient of tangent
- Area under curve
- Gradient of chord
- Peak velocity value
-
What happens to an object's motion at a local maximum on a displacement-time graph?
- Reverses direction
- Constant speed
- Stops permanently
- Maximum acceleration
-
A velocity-time graph accelerates to 8 m/s in 2 s, stays constant 4 s, then stops in 2 s. Find displacement.
- 32 m
- 48 m
- 64 m
- 40 m
-
An object travels +30 m in 3 s and -30 m back in 3 s. Find average speed.
- 0 m/s
- 20 m/s
- 5 m/s
- 10 m/s
-
An object travels +30 m in 3 s and -30 m back in 3 s. Find average velocity.
- 10 m/s
- 0 m/s
- -10 m/s
- 5 m/s
-
On a velocity-time graph, what does a curve getting steeper downwards represent?
- Constant deceleration
- Decreasing deceleration
- Increasing deceleration
- Constant acceleration
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