Lesson 1.07m
1.07m Tangents, normals and stationary points Quiz: OCR Maths, Unit 7
20 questions
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Lesson 1.07m, Tangents, normals and stationary points: 20 multiple choice questions for the OCR Maths (H240), Unit 7: Differentiation, written with Revision Ninja.
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The 20 questions
-
For a tangent of gradient m, what is the gradient of the normal?
- 1/m
- -m
- m
- -1/m
-
What condition must be satisfied at a stationary point on a curve?
- dy/dx > 0
- dy/dx = 0
- y = 0
- d2y/dx2 = 0
-
What condition must be met for a point to be a point of inflection?
- f'(x) changes sign
- f''(x) > 0
- f'(x) = 0
- f''(x) changes sign
-
The function f is increasing where:
- f''(x) > 0
- f'(x) > 0
- f'(x) < 0
- f(x) > 0
-
At a stationary point with f''(x) < 0, the point is a:
- Maximum
- Point of inflection
- Cannot be classified
- Minimum
-
What is the tangent to y = x^2 - 4x + 1 at x = 3?
- y = x - 5
- y = -2x - 8
- y = 2x - 8
- y = 2x + 4
-
What is the normal to y = x^2 at x = 1?
- y = -x/2 + 3/2
- y = 2x - 1
- y = -2x + 3
- y = x/2 + 1/2
-
Find the stationary points of y = x^3 - 3x.
- (1, -2) and (-1, 2)
- (1, 2) and (-1, -2)
- (0, 0) only
- (3, 0) and (-3, 0)
-
Classify the stationary point at x = 1 on y = x^3 - 3x.
- Point of inflection
- Maximum
- Not stationary
- Minimum
-
For which values of x is the function y = x^3 - 3x increasing?
- |x| < 1
- -1 < x < 1
- |x| > 1
- x > 0
-
What type of stationary point occurs on y = x^4 - 4x^3 at x = 0?
- Local maximum
- Non-stationary inflection
- Local minimum
- Stationary inflection
-
How is the stationary point (0, 0) on the curve y = x^3 classified?
- Asymptote
- Local minimum
- Point of inflection
- Local maximum
-
What is the tangent to y = e^x at x = 0?
- y = x - 1
- y = 1
- y = e x
- y = x + 1
-
At what x is the tangent to y = ln x of gradient 1/2?
- x = 1/2
- x = e
- x = 2
- x = 4
-
Which points on y = x^3 - 6x^2 + 9x have a horizontal tangent?
- (2, -2) only
- (1, 0) and (3, 4)
- (0, 0) and (2, 2)
- (1, 4) and (3, 0)
-
For y = x^3 - 3x^2, what is the nature of the stationary point at x = 2?
- Not stationary
- Minimum
- Point of inflection
- Maximum
-
For y = x^2 + kx + 4 to have a horizontal tangent at x = 3, what is k?
- -6
- 6
- -3
- 3
-
Which condition makes the tangent to y = f(x) horizontal at x = a?
- f''(a) = 0
- f'(a) = 0
- f'(a) = 1
- f(a) = 0
-
What is the gradient of the normal to y = x^2 at x = 2?
- -1/4
- 4
- 1/4
- -4
-
What is the tangent to y = 1/x at x = 1?
- y = 2x - 1
- y = -x + 2
- y = -x
- y = x
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