Lesson 1.06i
1.06i Exponential modelling Quiz: OCR Maths, Unit 6
20 questions
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Lesson 1.06i, Exponential modelling: 20 multiple choice questions for the OCR Maths (H240), Unit 6: Exponentials and Logarithms, written with Revision Ninja.
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The 20 questions
-
Which formula models continuous compound interest?
- A = P(1 + r)^t
- A = P e^(t/r)
- A = P e^(rt)
- A = P r e^t
-
Which formula models radioactive decay with half-life T?
- N = N0 (1/2)^(t T)
- N = N0 (1/2)^(t/T)
- N = N0 2^(t/T)
- N = N0 e^(t/T)
-
As time t increases, what value does y = A e^(-kt) approach for k > 0?
- 0
- 1
- A
- Infinity
-
Which limit defines the mathematical constant e as n approaches infinity?
- (1 + 1/n)
- (1 + 1/n)^n
- (1 + n)^(1/n)
- (1 - 1/n)^n
-
For N = N0 e^(-lambda t), what is the half-life T?
- T = 2 / lambda
- T = ln 2 / lambda
- T = lambda / ln 2
- T = ln(lambda) / 2
-
Which parameter in a refined population model represents the maximum sustainable population size?
- Half-life
- Carrying capacity
- Growth rate
- Initial population
-
What is £2000 invested at 4% continuous compound interest worth after 3 years?
- £2254.99
- £2250.00
- £2249.73
- £2240.00
-
A sample of 80 g has half-life 5 years. How much remains after 15 years?
- 40 g
- 5 g
- 10 g
- 20 g
-
A count N = 500 e^(-0.2t) decays. Roughly how long does it take to halve?
- 0.69
- 5.00
- About 3.47
- 2.50
-
A population P = 1000 e^(0.05t) is modelled. What is its growth rate at t = 0?
- 1000 per year
- 50 per year
- 1050 per year
- 0.05 per year
-
A drug concentration is C = 12 e^(-0.5t) mg/L. What is it after 2 hours?
- 0.12 mg/L
- 1.62 mg/L
- 6.00 mg/L
- 4.41 mg/L
-
A car worth £20 000 depreciates by 15% each year. What is its value after 3 years?
- £14 450.00
- £12 282.50
- £17 000.00
- £11 000.00
-
A quantity grows as e^(0.1t). What is its doubling time?
- About 0.69 years
- About 5.00 years
- About 10.00 years
- About 6.93 years
-
A population doubles every 20 days under exponential growth. What is the growth constant k?
- About 0.0500 per day
- About 0.0347 per day
- About 0.0200 per day
- About 0.693 per day
-
How long does N = 200 e^(0.3t) take to reach 1000?
- About 5.37
- 3.00
- 1.61
- 16.09
-
A substance has a half-life of 30 years. What is its decay constant lambda?
- About 0.0231 per year
- About 0.6931 per year
- About 0.0333 per year
- About 20.79 per year
-
Which expression gives the annual growth factor for a continuous growth rate of 5%?
- 1.05^1
- e^0.05
- ln(0.05)
- e^1.05
-
In the exponential growth model y = A e^(kt), what does k represent?
- Time elapsed
- Growth rate
- Initial value
- Upper limit
-
What is the initial value of N = 50 e^(0.02t)?
- 50
- 1
- 0.02
- 51
-
A bacterial colony doubles every 4 hours. Which model gives the count N after t hours from N0?
- N = N0 e^(4t)
- N = N0 4^(t/2)
- N = N0 2^(t/4)
- N = N0 2^(4t)
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