Lesson 3.3.2
3.3.2 Kinetic and potential energies Quiz: OCR Physics, Unit 2
20 questions
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Lesson 3.3.2, Kinetic and potential energies: 20 multiple choice questions for the OCR Physics (H156), Unit 2: Forces and motion, written with Revision Ninja.
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The 20 questions
-
The kinetic energy of an object of mass m moving at speed v is:
- (1/2) m v
- m g h
- m v^2
- (1/2) m v^2
-
Which formula gives the gravitational potential energy of a mass in a uniform field?
- m h / g
- m g / h
- m g h
- 0.5 m g h
-
For a freely falling object with no air resistance, the total mechanical energy is:
- Decreasing
- Zero
- Increasing
- Constant
-
What type of physical quantity is kinetic energy?
- Scalar
- Base SI quantity
- Vector
- Tensor
-
By what factor does kinetic energy increase if the speed of an object doubles?
- 2
- 4
- 8
- 16
-
Why can the zero reference level for gravitational potential energy be chosen arbitrarily?
- Gravity is constant
- Height is absolute
- Only changes matter
- Mass is invariant
-
According to the work-energy theorem, net work done on an object equals what?
- Kinetic energy change
- Rate of power
- Total momentum change
- Potential energy change
-
A 3 kg object moves at 4 m s^-1. What is its kinetic energy?
- 48 J
- 24 J
- 6 J
- 12 J
-
A 0.5 kg ball is at a height of 4 m. Using g = 9.8 m s^-2, what is its gravitational potential energy?
- 39.2 J
- 19.6 J
- 4.9 J
- 2.0 J
-
A ball is dropped from rest from a height of 5 m. Ignoring air resistance, what is its speed on landing? Use g = 9.8 m s^-2.
- 49 m s^-1
- 9.9 m s^-1
- 4.9 m s^-1
- 98 m s^-1
-
A 0.2 kg object falls through 1.5 m from rest. Using g = 9.8 m s^-2 and ignoring air resistance, what is its kinetic energy at the bottom?
- 14.7 J
- 1.5 J
- 2.9 J
- 0.3 J
-
A car of mass 1000 kg moves at 20 m s^-1. What is its kinetic energy?
- 2.0 x 10^4 J
- 4.0 x 10^5 J
- 2.0 x 10^5 J
- 1.0 x 10^5 J
-
A 6 kg mass is lowered by 3 m. Using g = 9.8 m s^-2, what is the change in its gravitational potential energy?
- -353 J (a loss of 353 J)
- -176 J (a loss of 176 J)
- +59 J (a gain of 59 J)
- +18 J (a gain of 18 J)
-
A roller coaster starts from rest 20 m above the bottom of a frictionless track. What is its speed at the bottom? Use g = 9.8 m s^-2.
- 9.9 m s^-1
- 392 m s^-1
- 39.2 m s^-1
- 19.8 m s^-1
-
A 0.4 kg object moves at 3 m s^-1 at a height of 2 m. Using g = 9.8 m s^-2, what is its total mechanical energy?
- 1.8 J
- 9.6 J
- 7.8 J
- 17.4 J
-
Which step correctly derives kinetic energy from the work done by a constant force F that accelerates a mass m from rest to speed v over distance s?
- F s = m g s
- F s = m a s = (1/2) m v^2
- F / s = m v
- F s = m v^2
-
A 2 kg ball falls 3 m from rest and reaches the bottom at 5 m s^-1. Using g = 9.8 m s^-2, how much energy is transferred to other forms?
- 58.8 J
- 8.8 J
- 33.8 J
- 25 J
-
A 1 kg object has speed 2 m s^-1 and height 1 m above the reference level. Using g = 9.8 m s^-2, what is its total energy?
- 2 J
- 9.8 J
- 4 J
- 11.8 J
-
An object has four times the mass of another but equal kinetic energy. What is its speed?
- Twice as fast
- Same speed
- Quarter as fast
- Half as fast
-
A ball is thrown vertically upwards at 12 m s^-1. Ignoring air resistance and using g = 9.8 m s^-2, what is its maximum height above the launch point?
- 7.3 m
- 14.7 m
- 6.1 m
- 12 m
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