Lesson A20
A20 Solving equations by iteration Quiz: AQA Maths, Unit 2
20 questions
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Lesson A20, Solving equations by iteration: 20 multiple choice questions for the AQA GCSE Maths (8300), Unit 2: Algebra, written with Revision Ninja.
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The 20 questions
-
(H) Starting at x0 = 2, x(n+1) = x(n)^2 - 3, what is x1?
- -1
- 1
- 4
- 7
-
(H) What does x(n+1) denote in an iterative method?
- The value of x(n) squared
- The gradient of the curve at x(n)
- The exact root of the equation
- The next approximation, found from x(n)
-
(H) Using x(n+1) = 2 + 1/x(n) with x0 = 2, what is x1?
- 2.5
- 3
- 1.5
- 2.4
-
(H) Using x(n+1) = 2 + 1/x(n) with x0 = 2, what is x2 to 1 decimal place?
- 2.5
- 2.25
- 3.4
- 2.4
-
Between which two whole numbers does the root of x^3 + x - 4 = 0 lie?
- 2 and 3
- -1 and 0
- 1 and 2
- 0 and 1
-
A sign change of f(x) between x = 1 and x = 2 shows what?
- There are no roots in this interval
- The graph has a turning point at x = 1
- The root is exactly 1.5
- A root lies between 1 and 2
-
(H) For x(n+1) = sqrt(x(n) + 1) with x0 = 1, what is x1 to 2 decimal places?
- 1.5
- 1.00
- 2.00
- 1.41
-
(H) When successive iterates settle down to the same value, what does this mean?
- They satisfy the rearranged equation
- The graph has a maximum there
- The equation has no real roots
- The method has failed
-
In x(n+1), what does the subscript n + 1 indicate?
- The next term after the nth term in the sequence of iterates
- The gradient of the graph at the point x = n + 1
- The term n plus one in a different sequence of values
- The first term multiplied by n, repeated each step
-
(H) Starting with x0 = 3, what is x1 for x(n+1) = 5 - x(n)?
- 2
- 3
- 8
- -3
-
(H) For x(n+1) = 4 / x(n) with x0 = 1, what is x2?
- 0.25
- 2
- 4
- 1
-
(H) To iterate x^3 + 2x = 10, which rearrangement is suitable?
- x = (10 - x^3) / 2
- x = (10 - 2x) / x^3
- x = 10 - x^3 + 2
- x = 10 / (x^3 + 2)
-
(H) Why might iterating a rearrangement fail to find a root?
- The starting value must always be zero
- Each iterate must be a whole number
- Iteration only works for linear equations
- Its iterates may move away from the root
-
(H) Starting at x0 = 1, x(n+1) = 1 + 1/x(n), what is x2?
- 1.67
- 1.5
- 2
- 1
-
(H) Iterating x(n+1) = 0.5 x(n) + 3 from x0 = 0, what is x2?
- 3
- 4.5
- 6
- 1.5
-
(H) The iteration x(n+1) = 3 / x(n) from x0 = 1 gives 1, 3, 1, 3 and so on. Why does it not converge?
- The iterates alternate and never settle on a value
- The iterates reach zero after two steps and stop
- The iterates grow without limit, getting larger each step
- The iterates equal the root of x^2 + 3
-
(H) f(x) = x^2 - 5 has f(2) < 0 and f(3) > 0. Between which values is the root?
- 2 and 3
- 3 and 4
- -3 and -2
- 0 and 2
-
(H) To find a root to 2 decimal places by iteration, when should you stop?
- When the function value is exactly 2 at that step
- When two successive iterates agree to 2 decimal places
- After five iterations, regardless of the values reached
- When the iterate equals zero to two decimal places
-
(H) Starting at x0 = 3, x(n+1) = 2 x(n) - 1, what is x2?
- 9
- 5
- 11
- 7
-
(H) Starting at x0 = 4, x(n+1) = x(n) / 2 + 1, what is x3?
- 3
- 2
- 2.5
- 2.25
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