Lesson 3.5.1.5
3.5.1.5 Potential divider Quiz: AQA Physics, Unit 5
20 questions
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Lesson 3.5.1.5, Potential divider: 20 multiple choice questions for the AQA Physics (7408), Unit 5: Electricity, written with Revision Ninja.
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The 20 questions
-
A potential divider is used to:
- convert alternating current to direct current
- store charge in a capacitor
- supply a constant or variable potential difference from a supply
- measure resistance directly with a meter
-
Two resistors R1 and R2 are in series across a supply pd V. The output pd across R2 is:
- V R1 / (R1 + R2)
- V R2 / (R1 + R2)
- V (R1 + R2) / R2
- V / (R1 + R2)
-
A thermistor with negative temperature coefficient is used as the output-side resistor of a potential divider. As temperature rises, the pd across it:
- decreases
- stays the same
- increases
- becomes negative
-
An LDR in darkness has:
- zero resistance
- a resistance that is zero at all light levels
- a high resistance
- a low resistance
-
Which component is commonly used as a variable resistor in a potential divider?
- a variable resistor such as a slider
- a capacitor
- an ideal ammeter
- a superconductor
-
In a potential divider, the output pd across R2 is zero when:
- R1 is zero
- R2 is zero
- R2 is infinite
- R1 equals R2
-
A 6.0 V supply is across two resistors in series, 2.0 kohm and 4.0 kohm. What is the output pd across the 4.0 kohm resistor?
- 2 V
- 4 V
- 3 V
- 6 V
-
A 9.0 V supply is across a 3.0 ohm and a 6.0 ohm resistor in series. What is the pd across the 6.0 ohm resistor?
- 4.5 V
- 9 V
- 3 V
- 6 V
-
A 12 V supply is across a 10 kohm fixed resistor in series with an LDR. In darkness the LDR is 100 kohm. What is the pd across the LDR?
- about 6.0 V
- 12 V
- about 1.1 V
- about 10.9 V
-
As a wiper moves along a variable resistor used as a potential divider, the output pd:
- increases from zero to the full supply pd
- stays constant at half the supply pd
- oscillates between zero and the supply pd
- decreases from full supply pd to zero
-
A 6.0 V supply is across a fixed 2.0 kohm resistor in series with an NTC thermistor of 1.0 kohm. What is the pd across the thermistor?
- 2 V
- 4 V
- 1 V
- 3 V
-
A 12 V supply must give a 3 V output across R2 in a potential divider. What ratio R2 : R1 is needed?
- 1 : 4
- 3 : 1
- 1 : 3
- 1 : 1
-
A potential divider has total resistance 1.5 kohm. Its output across R2 is two thirds of the supply pd. What is R2?
- 0.5 kohm
- 1.5 kohm
- 0.67 kohm
- 1.0 kohm
-
A divider with R1 = 1.0 kohm and R2 = 3.0 kohm is across an 8.0 V supply. What is the output pd across R2?
- 2 V
- 6 V
- 4 V
- 8 V
-
A variable resistor is a 10 ohm track connected across 10 V with no load. The output is taken from its midpoint. What is the output pd?
- 0 V
- 5 V
- 10 V
- 2.5 V
-
When a load resistor is connected across the output of a potential divider, the output pd falls because:
- the load adds resistance to R1, increasing the output
- the load is in parallel with R2, lowering the combined resistance of the lower branch
- the load is in series with the supply, increasing the output
- the load stores charge that raises the output
-
A fixed resistor R1 = 2.0 kohm is in series with an NTC thermistor across 5.0 V. As the thermistor's resistance rises from 1.0 kohm to 4.0 kohm, how does the pd across the thermistor change?
- It increases from about 1.7 V to about 3.3 V
- It stays at 2.5 V
- It increases from 0 V to 5 V
- It decreases from about 3.3 V to about 1.7 V
-
A 5.0 kohm fixed resistor is in series with a 10 kohm LDR across 6.0 V. What is the pd across the fixed resistor?
- 1.2 V
- 3.0 V
- 4.0 V
- 2.0 V
-
A student claims that the potential divider output always equals the resistance ratio times the supply pd, even with a load attached. Which response is best?
- Incorrect, because a load in parallel with the output resistor lowers its effective resistance, so the output pd falls.
- Correct, since a load in series with the supply changes nothing.
- Incorrect, because the output rises whenever a load is attached.
- Correct, because a load does not change the ratio of resistances.
-
A 12 V supply is across R1 = 4.0 kohm and R2 = 8.0 kohm. An 8.0 kohm load is connected across R2. What is the output pd?
- 12 V
- 8 V
- 4 V
- 6 V
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