Lesson 3.2.2.4
3.2.2.4 Wave-particle duality Quiz: AQA Physics, Unit 2
20 questions
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Lesson 3.2.2.4, Wave-particle duality: 20 multiple choice questions for the AQA Physics (7408), Unit 2: Particles and radiation, written with Revision Ninja.
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The 20 questions
-
What does electron diffraction suggest about particles?
- Particles are always at rest
- Particles have no momentum
- Particles cannot be diffracted
- Particles possess wave properties
-
What does the photoelectric effect suggest about electromagnetic waves?
- They are always longitudinal
- They have a particulate nature
- They cannot transfer energy
- They travel slower than sound
-
What is the de Broglie wavelength formula?
- λ = h/(mv)
- λ = h/(mv^2)
- λ = hmv
- λ = mv/h
-
If the momentum of an electron increases, what happens to its de Broglie wavelength?
- It doubles
- It stays the same
- It decreases
- It increases
-
Which experiment gives evidence for the wave nature of electrons?
- Photoelectric effect
- Compton scattering
- Electron diffraction
- Rutherford scattering
-
What is the de Broglie wavelength of an electron moving at 1.0 × 10^6 m/s? Use m = 9.11 × 10^-31 kg.
- 7.3 × 10^-7 m
- 1.5 × 10^-9 m
- 6.6 × 10^-28 m
- 7.3 × 10^-10 m
-
A proton (m = 1.67 × 10^-27 kg) moves at 1.0 × 10^6 m/s. What is its de Broglie wavelength?
- 4.0 × 10^-13 m
- 4.0 × 10^-10 m
- 4.0 × 10^-16 m
- 7.3 × 10^-10 m
-
If the momentum of a particle is doubled, what happens to its de Broglie wavelength?
- It stays the same
- It halves
- It becomes a quarter
- It doubles
-
An electron is accelerated through 100 V from rest. What is its de Broglie wavelength? Use m = 9.11 × 10^-31 kg and e = 1.6 × 10^-19 C.
- 1.2 × 10^-10 m
- 1.2 × 10^-13 m
- 1.2 × 10^-7 m
- 3.9 × 10^-10 m
-
A particle has a de Broglie wavelength of 1.0 × 10^-10 m. What is its momentum?
- 6.6 × 10^-34 kg m s^-1
- 6.6 × 10^-14 kg m s^-1
- 1.5 × 10^-24 kg m s^-1
- 6.6 × 10^-24 kg m s^-1
-
What is the momentum of a photon of wavelength 500 nm?
- 1.3 × 10^-27 kg m s^-1
- 1.3 × 10^-18 kg m s^-1
- 2.0 × 10^-27 kg m s^-1
- 6.6 × 10^-34 kg m s^-1
-
Why does electron diffraction become more pronounced as momentum decreases?
- The electrons become more massive
- The wavelength increases, so it becomes comparable to the spacing of the diffracting structure
- The wavelength falls to zero
- The electric charge increases
-
An electron and a proton have the same speed. What is the ratio of the electron's wavelength to the proton's wavelength?
- about 1840
- 1
- about 40
- about 1/1840
-
An electron is accelerated through 1.0 kV from rest. What is its de Broglie wavelength?
- 1.2 × 10^-13 m
- 3.9 × 10^-11 m
- 1.2 × 10^-10 m
- 3.9 × 10^-8 m
-
An electron and a photon have the same wavelength. What is the ratio of the electron's momentum to the photon's momentum?
- 2
- 0.5
- 1
- 1836
-
Which observation in the photoelectric effect supports the particle nature of light?
- Emission depends on frequency and a threshold, not on intensity
- Emission rate depends on light intensity alone
- Electrons are emitted after a delay at low intensity
- Electrons are emitted at all frequencies when intensity rises
-
What is the de Broglie wavelength of a 0.1 kg ball moving at 10 m/s?
- 6.6 × 10^-32 m
- 1.0 × 10^-34 m
- 6.6 × 10^-30 m
- 6.6 × 10^-34 m
-
Why is the wave-particle duality model regarded as provisional?
- Because electrons are never observed directly
- New evidence must be peer reviewed and validated by the scientific community
- Because the Planck constant is not fixed
- Because diffraction cannot be measured
-
What speed must an electron have for its de Broglie wavelength to be 0.1 nm? Use m = 9.11 × 10^-31 kg.
- 7.3 × 10^6 m/s
- 7.3 × 10^9 m/s
- 7.3 × 10^3 m/s
- 2.2 × 10^8 m/s
-
In the de Broglie formula, what does the product mv represent?
- The force acting on the particle
- The kinetic energy of the particle
- The momentum of the particle
- The angular momentum of the particle
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