Lesson 3.3.3.1
3.3.3.1 Nucleophilic substitution Quiz: AQA Chemistry, Unit 3
20 questions
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Lesson 3.3.3.1, Nucleophilic substitution: 20 multiple choice questions for the AQA Chemistry (7405), Unit 3: Organic chemistry, written with Revision Ninja.
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The 20 questions
-
Why are halogenoalkanes more reactive than alkanes?
- Halogenoalkanes contain double bonds that are very reactive
- The C-H bonds are polar and are attacked directly by hydroxide ions
- Halogenoalkanes have no bonds that can break
- The carbon-halogen bond is polar, making the carbon electron-deficient
-
Which nucleophile is used to hydrolyse halogenoalkanes to alcohols?
- OH-
- H+
- NO2+
- Br2
-
Which nucleophile produces a nitrile from a halogenoalkane?
- H2O
- NO3-
- CN-
- Cl2
-
Which nucleophile reacts with a halogenoalkane to form an amine?
- O2
- NH3
- Ar
- CH4
-
Which halogenoalkane reacts fastest with hydroxide ions?
- 1-bromobutane, which is slowest at room temperature
- 1-iodobutane
- 1-chlorobutane
- 1-fluorobutane
-
Why does the rate of nucleophilic substitution increase down group 17 for halogenoalkanes?
- The halogens become lighter down the group
- The carbon-halogen bond enthalpy decreases down the group, so bonds break more easily
- Halogens become less electronegative so the bond is less polar
- The bonds become stronger down the group
-
What is the observed test-tube result for 1-chlorobutane hydrolysis with aqueous silver nitrate after warming with ethanol?
- No precipitate forms
- A white precipitate of AgCl forms
- A cream precipitate of AgBr forms
- A yellow precipitate of AgI forms
-
Which silver halide precipitate is yellow?
- AgBr
- AgCl
- AgI
- AgF
-
Which halogenoalkane gives a cream precipitate in the silver nitrate test?
- Bromoalkane
- Iodoalkane
- Chloroalkane
- Fluoroalkane
-
Which halogenoalkane is the least reactive in nucleophilic substitution?
- 1-bromobutane
- 1-iodobutane
- 1-fluorobutane
- 1-chlorobutane
-
Which of these nucleophiles has a lone pair and is negatively charged?
- OH-
- H+
- CH3+
- BF3
-
In the SN2 mechanism of a primary halogenoalkane with OH-, how many species are involved in the rate-determining step?
- Three: the halogenoalkane, hydroxide and water
- Zero: the reaction is spontaneous
- One: the halogenoalkane only
- Two: the halogenoalkane and the hydroxide ion
-
What is the product of the nucleophilic substitution of 1-bromopropane with aqueous OH-?
- Propanal
- Propene
- Propane
- Propan-1-ol
-
What product is formed when bromoethane reacts with excess aqueous ammonia?
- Ethylamine
- Ethanol
- Ethene
- Ethanenitrile
-
Which statement explains why C-Br bonds are more reactive than C-Cl bonds in substitution?
- C-Br has no polarity
- C-Br has a lower bond enthalpy, so less energy is needed to break it
- C-Br is a stronger bond than C-Cl
- C-Br bonds never break in substitution
-
Which halogenoalkane is the most polar carbon-halogen bond?
- C-I
- C-Br
- C-F
- C-H
-
Why is the carbon atom in C-X electron-deficient?
- The carbon is bonded to a metal atom
- Halogens are more electronegative, pulling electron density away from carbon
- The C-X bond has no electrons
- Carbon is more electronegative than the halogen
-
Which halogenoalkane is tertiary?
- 2-chloro-2-methylpropane
- 1-chloropropane
- 2-chloropropane
- Chloromethane
-
Explain in terms of bond enthalpy why 1-iodobutane hydrolyses faster than 1-chlorobutane.
- The C-I bond has a lower bond enthalpy, so it is broken more easily in the substitution step
- The C-I bond is stronger, so more energy is released
- Iodine is less electronegative so the C-I bond is more polar than C-Cl
- The C-Cl bond is ionic and reacts faster
-
Explain why the reaction of halogenoalkanes with silver nitrate in ethanol is used as a test for the rate of hydrolysis.
- The precipitate forms as the halide ions are released, so the time taken shows how fast the C-X bond breaks
- The silver ions change colour with the alkane
- Silver nitrate catalyses the reaction by removing hydrogen
- Silver nitrate reacts with the alkane to form a gas that shows the rate
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